Linear Momentum AP Physics C Mechanics MCQ – Exam Style Questions etc.
Linear Momentum AP Physics C Mechanics MCQ
Unit 4: Linear Momentum
Weightage : 15-25%
Question
The magnitude of a force as a function of time can be represented by \(F(t)=Rt^{2}-St+Z\)
The direction of the force does not change. If the force is exerted on an object of mass , the change in velocity of the object between t=0 and seconds is
A 2RT-S
B \(\frac{2RT}{M}-\frac{S}{M}\)
C \(\frac{1}{3}RT^{3}-\frac{1}{2}ST^{2}+ZT\)
D \(\frac{1}{3}\frac{RT^{3}}{M}-\frac{1}{2}\frac{ST^{2}}{M}+\frac{ZT}{M}\)
E \(\frac{RT^{2}}{M}-\frac{ST^{2}}{M}+\frac{Z}{M}\)
Answer/Explanation
Ans:D
Question
In an experiment, students use a force sensor to apply a force of magnitude to an object of mass m that is initially at rest. The force is exerted in the -direction for a time . The impulse exerted on the device is . Which of following procedure changes would result in an impulse 2J being exerted on an object?
A Exert a force of magnitude F2 on an object of mass m for a time .
B Exert a force of magnitude F on an object of mass 2m for a time .
C Exert a force of magnitude F on an object of mass 2m for a time .
D Exert a force of magnitude on an object of mass m for a time .
E Exert a force of magnitude 2F on an object of mass m for a time \(t=\frac{T}{2}\)
Answer/Explanation
Ans:C
The mass has no effect on the impulse. Doubling the time while keeping the force the same will double the impulse.
Question
If one knows only the constant resultant force acting on an object and the time during which this force acts, one can determine the
A change in momentum of the object
B change in velocity of the object
C change in kinetic energy of the object
D mass of the object
E acceleration of the object
Answer/Explanation
Ans:A
Question
Object has a mass of and is moving in the direction. It collides with object B , which has a mass of 2 and is initially at rest. After the collision, object B has a final velocity of v in the + direction. Which of the following best describes the impulse object B exerts on object during the collision?
A −2Mv
B −Mv
C 0
D +Mv
E +2Mv
Answer/Explanation
Ans:A
The impulse object exerts on object will be equal and opposite the impulse of on . The impulse on B can be calculated by its change in momentum, J=Δp=m(vf−vi)=2M(v−0)=2Mv. Therefore, the impulse on object is −2Mv.