Home / AP® Exam / AP® PreCalculus / AP® Precalculus

AP Precalculus -2.2 Linear and Exponential Change- MCQ Exam Style Questions - Effective Fall 2023

AP Precalculus -2.2 Linear and Exponential Change- MCQ Exam Style Questions – Effective Fall 2023

AP Precalculus -2.2 Linear and Exponential Change- MCQ Exam Style Questions – AP Precalculus- per latest AP Precalculus Syllabus.

AP Precalculus – MCQ Exam Style Questions- All Topics

Question 

Which of the following tables provides evidence that \( f \) is an exponential function if \( y = f(x) \)?
(A) \[\begin{array}{c|c} x & y \\ \hline 1 & 3 \\ 2 & 6 \\ 3 & 9 \\ 4 & 12 \\ \end{array}\]
(B) \[\begin{array}{c|c} x & y \\ \hline 5 & 30 \\ 6 & 42 \\ 7 & 56 \\ 8 & 72 \\ \end{array}\]
(C) \[\begin{array}{c|c} x & \ln y \\ \hline 1 & 1 \\ 2 & 3 \\ 3 & 9 \\ 4 & 27 \\ \end{array}\]
(D) \[\begin{array}{c|c} x & \ln y \\ \hline 5 & 50 \\ 6 & 60 \\ 7 & 70 \\ 8 & 80 \\ \end{array}\]
▶️ Answer/Explanation
Detailed solution

A function is exponential if the natural logarithm of its output values \( \ln y \) is linear in \( x \).
In option (C), \( \ln y \) values are 1, 3, 9, 27 — these are not linear in \( x \).
In option (D), \( \ln y \) values are 50, 60, 70, 80 — these form an arithmetic sequence, so \( \ln y \) is linear in \( x \).
Thus \( y = e^{mx+b} \) is exponential.
Answer: (D)

Question 

The function \( g \) is a function of the form \( g(x) = a \cdot b^x \), where \( a \neq 0 \) and \( b > 0 \). The function \( f \) is given by \( f(x) = g(x) + 4 \). Which of the following statements is true?
(A) The output values of both \( f \) and \( g \) are proportional over equal-length input-value intervals.
(B) The output values of \( f \) only, not \( g \), are proportional over equal-length input-value intervals.
(C) The output values of \( g \) only, not \( f \), are proportional over equal-length input-value intervals.
(D) The output values of neither \( f \) nor \( g \) are proportional over equal-length input-value intervals.
▶️ Answer/Explanation
Detailed solution

Exponential functions \( g(x) = a \cdot b^x \) have outputs that are proportional over equal-length input intervals (ratio constant).
Adding a constant \( +4 \) to \( g \) gives \( f(x) \), which is no longer a pure exponential; its successive ratios are not constant.
Thus only \( g \) has proportional output changes over equal-length input intervals.
Answer: (C)

Question 

The number of students at Speedway High School that earn a qualifying score on an AP math exam can be modeled using an arithmetic sequence, where Mr. Passwater’s first year at SHS is year 1. The number of students earning a qualifying score in year 3 was 52, and the number of students earning a qualifying score in year 6 was 61. Which of the following functions gives the number of students earning a qualifying score in year \(t\), where \(t\) is a whole number?
(A) \( f(t) = \frac{1}{3}t + 51 \)
(B) \( g(t) = 3t + 43 \)
(C) \( h(t) = 3t + 52 \)
(D) \( k(t) = 3t + 61 \)
▶️ Answer/Explanation
Detailed solution
The problem provides two data points for an arithmetic sequence (linear model): \((3, 52)\) and \((6, 61)\).
Step 1: Calculate the common difference (slope, \(d\)) using the two points: \(d = \frac{61 – 52}{6 – 3} = \frac{9}{3} = 3\).
Step 2: The function is linear, so it takes the form \(y = dt + b\). Substitute \(d=3\).
Step 3: Use the point \((3, 52)\) to solve for the constant \(b\): \(52 = 3(3) + b \rightarrow 52 = 9 + b\).
Step 4: Solving for \(b\) gives \(b = 52 – 9 = 43\).
Step 5: The final function is \(g(t) = 3t + 43\). This matches option (B).

Question 

(Calculator Active) Fearing a new computer virus, a security company performs a simulation to predict the number of computers that might be affected by the virus. The number of infected computers can be modeled by a geometric sequence, where the first day of the simulation is day \(1\). On day \(6\), the virus had infected \(750\) computers, and on day \(10\) the virus had infected \(3200\) computers. To the nearest whole number, how many computers had been infected by the virus on day \(14\) based on the simulation?
(A) \(5,650\)
(B) \(5,717\)
(C) \(13,653\)
(D) \(120,329\)
▶️ Answer/Explanation
Detailed solution

The problem describes a geometric sequence where the term \(g_n\) represents the number of infected computers on day \(n\).
We are given \(g_6 = 750\) and \(g_{10} = 3200\).
Using the property of geometric sequences, we can relate terms using the common ratio \(r\): \(g_{10} = g_6 \cdot r^{(10-6)}\).
Substitute the known values: \(3200 = 750 \cdot r^4\).
Solving for \(r^4\) gives: \(r^4 = \frac{3200}{750}\).
We need to find \(g_{14}\), which can be expressed as: \(g_{14} = g_{10} \cdot r^{(14-10)} = 3200 \cdot r^4\).
Substituting the value of \(r^4\): \(g_{14} = 3200 \cdot \left(\frac{3200}{750}\right) = 13653.33\dots\)
Rounding to the nearest whole number, the number of infected computers is \(13,653\).
The correct option is (C).

Question 

Which of the following tables provides evidence that $f$ is an exponential function if $y = f(x)$?
(A)
$x$$y$
$1$$3$
$2$$6$
$3$$9$
$4$$12$

(B)

$x$$y$
$5$$30$
$6$$42$
$7$$56$
$8$$72$

(C)

$x$$\ln y$
$1$$1$
$2$$3$
$3$$9$
$4$$27$

(D)

$x$$\ln y$
$5$$50$
$6$$60$
$7$$70$
$8$$80$
▶️ Answer/Explanation
Detailed solution

An exponential function $y = a \cdot b^x$ becomes linear when transformed by logarithms.
Applying the natural log gives the equation $\ln y = \ln a + x \ln b$.
This implies that for an exponential function, $\ln y$ must have a constant rate of change relative to $x$.
In Table (D), as $x$ increases by $1$ unit, $\ln y$ increases by a constant addition of $10$.
Table (A) shows a linear relationship for $y$ itself, not an exponential one.
Table (C) shows $\ln y$ growing exponentially, which would mean $y$ grows even faster.
Only Table (D) shows the constant slope for $\ln y$ that characterizes an exponential function $f(x)$.
Thus, the correct choice is Table (D).

Question 

The table gives ordered pairs $(x, \ln y)$. For the function $y = f(x)$, which of the following statements about $f$ is supported by the data in the table?
(A) The function $f$ is logarithmic because the values of $x$ and the values of $\ln y$ both form arithmetic sequences.
(B) The function $f$ is linear because the values in each column form an arithmetic sequence.
(C) The function $f$ is exponential because the values of $x$ and the values of $\ln y$ both form arithmetic sequences.
(D) The function $f$ is exponential because the values of $\ln y$ increase faster than the values of $x$.
▶️ Answer/Explanation
Detailed solution

The $x$ values increase by a constant $1$ ($5, 6, 7, 8$), forming an arithmetic sequence.
The $\ln y$ values increase by a constant $3$ ($3, 6, 9, 12$), forming an arithmetic sequence.
Since $\ln y$ is a linear function of $x$, the relationship is of the form $\ln y = mx + b$.
Applying the exponential to both sides gives $y = e^{mx + b}$, which simplifies to $y = Ab^x$.
This structure confirms that the function $f(x)$ is an exponential function.
Therefore, statement (C) is the correct characterization of the data.
Correct Option: (C)

Question 

Consider the function $f$. The table gives values of $\log_{3}(f(x))$ for selected values of $x$. Which of the following is a graph of $y = f(x)$ ?
(A)
(B)
(C)
(D)
▶️ Answer/Explanation
Detailed solution

From the table, the linear relationship is $\log_{3}(f(x)) = x + 2$.
Convert this to exponential form: $f(x) = 3^{x+2}$.
Calculate the y-intercept by setting $x = 0$: $f(0) = 3^{0+2} = 9$.
Calculate the value at $x = 1$: $f(1) = 3^{1+2} = 27$.
Calculate the value at $x = 2$: $f(2) = 3^{2+2} = 81$.
The graph must be exponential and pass through points $(0, 9)$ and $(1, 27)$.
Therefore, the correct choice is (D).

Scroll to Top