AP Statistics 1.1 Introducing Statistics: What Can We Learn from Data?- Exam Style Questions - FRQs - New Syllabus
Question


Most-appropriate topic codes (AP Statistics):
• Topic \(1.1\) — Introducing Statistics: Do the Data We Collected Match What We Expected? (Parts \( \mathrm{b} \), \( \mathrm{c} \))
▶️ Answer/Explanation
(a)
The median reduction in blood pressure for the dark chocolate group is 7 mmHg, and the median reduction in blood pressure for the white chocolate group is 0 mmHg. Therefore, the median reduction for the dark chocolate group is greater than the median reduction for the white chocolate group.
(b)
The researcher’s conclusion might not be true because the difference in sample means could simply be due to sampling variability (chance variation) arising from the random assignment of participants to the two groups. A difference of 5.66 mmHg can sometimes occur by chance even if the treatments are equally effective, so a statistical simulation or hypothesis test is necessary to determine if the result is statistically significant.
(c)
Yes, the results provide convincing statistical evidence. The observed difference in sample means is $6.08 – 0.42 = 5.66$ mmHg. According to the simulation dotplot, a simulated difference of 5.66 or greater occurred in only 3 of the 120 trials. The estimated p-value is $\frac{3}{120} = 0.025$. Because the p-value ($0.025$) is less than the significance level ($\alpha = 0.05$), we reject the null hypothesis and conclude there is convincing evidence that dark chocolate results in a greater reduction in blood pressure on average than white chocolate.
Question


Most-appropriate topic codes (AP Statistics):
• Topic \(1.7\) — Summary Statistics for a Quantitative Variable (Center, Spread, Shape) (Parts \(\mathrm{a}\), \(\mathrm{b}\), \(\mathrm{c}\))
• Topic \(1.9\) — Comparing Distributions of a Quantitative Variable (Parts \(\mathrm{a}\), \(\mathrm{b}\))
• Topic \(1.10\) — The Effect of Adding a Constant or Multiplying by a Constant on Summary Statistics (Part \(\mathrm{b}\))
• Topic \(3.1\) — Mean and Standard Deviation of a Linear Transformation (Part \(\mathrm{c}\))
▶️ Answer/Explanation
(a)
When comparing two distributions from boxplots, we examine center, spread, shape, and unusual features.
The cereals with one-cup serving sizes have a higher median sugar content per serving than the cereals with three-quarter-cup serving sizes. The one-cup distribution also has greater variability, as indicated by its larger range and larger interquartile range (IQR). In terms of shape, the one-cup distribution appears somewhat left-skewed because the median is closer to the upper quartile than to the lower quartile, while the three-quarter-cup distribution is more nearly symmetric. Neither distribution appears to contain extreme outliers.
(b)
Multiplying each sugar value in the three-quarter-cup group by \(\dfrac{4}{3}\) converts the measurements to sugar content per cup, allowing a fair comparison using equal serving sizes.
The adjusted boxplot shows that cereals with recommended serving sizes of three-quarter cup tend to contain more sugar per cup than cereals with recommended serving sizes of one cup. The median for the adjusted three-quarter-cup distribution is now noticeably higher than the median for the one-cup distribution. In addition, all measures of spread (range and IQR) for the adjusted distribution have increased by a factor of \(\dfrac{4}{3}\), reflecting the effect of multiplying every observation by a constant.
(c)
We would expect the mean sugar content per cup to be greater for cereals that list a serving size of three-quarter cup.
After adjustment, the three-quarter-cup distribution has a higher center than the one-cup distribution, as seen from its higher median. Because the mean generally follows the center of the distribution, the higher overall location of the adjusted three-quarter-cup distribution suggests a larger mean sugar content per cup.
\(\boxed{\bar{x}_{\frac{3}{4}\text{-cup}} > \bar{x}_{\text{1-cup}}}\)
