AP Statistics 1.7 Summary Statistics for a Quantitative Variable- FRQs - Exam Style Questions
Question
| Sample Size | Mean | Std Dev | Min | \(Q_1\) | Median | \(Q_3\) | Max |
|---|---|---|---|---|---|---|---|
| \(20\) | \(5.12\) | \(0.743\) | \(4.25\) | \(4.51\) | \(4.885\) | \(5.475\) | \(6.58\) |
(b) Julio wants to examine some characteristics of the distribution of the sample of whistle prices.
(i) Describe the shape of the distribution of the sample of whistle prices. Justify your response using appropriate values from the summary statistics table.
(ii) Using the \(1.5 \times IQR\) rule, determine whether there are any outliers in the sample of whistle prices. Justify your response.
(ii) Indicate the value of the Pearson’s coefficient of skewness you calculated in part (c-i) for the appropriate sample size by marking it with an “X” on the preceding graph.
(d) Consider your work in part (c).
(i) What should you conclude about the shape of the distribution of the sample of whistle prices? Justify your response.
Julio’s inference procedure in part \((a\text{-}i)\) needs one of the following requirements to be satisfied to verify the normality condition.
- The sample size is greater than or equal to \(30\).
- If the sample size is less than \(30\), the distribution of the sample data is not strongly skewed and does not have outliers.
(ii) Using your response to (d-i) and the preceding requirements, is the normality condition satisfied for Julio’s data? Explain your response.
Most-appropriate topic codes (CED):
• TOPIC 1.6: Describing the Distribution of a Quantitative Variable
• TOPIC 1.7: Summary Statistics for a Quantitative Variable
▶️ Answer/Explanation
(a)
(i) The appropriate inference procedure is a one-sample t-interval for a population mean.
(ii) The parameter of interest is \(\mu\), the true mean price, in dollars, of this type of whistle at all stores that sell the whistle.
(b)
(i) The distribution of the sample of whistle prices appears to be slightly skewed to the right. This is because the sample mean (\(5.12\)) is greater than the sample median (\(4.885\)).
(ii) First, calculate the IQR: \(IQR = Q_3 – Q_1 = 5.475 – 4.51 = 0.965\).
Next, calculate the outlier fences:
– Lower Fence: \(Q_1 – 1.5(IQR) = 4.51 – 1.5(0.965) = 3.0625\)
– Upper Fence: \(Q_3 + 1.5(IQR) = 5.475 + 1.5(0.965) = 6.9225\)
Since the minimum value (\(4.25\)) is greater than the lower fence and the maximum value (\(6.58\)) is less than the upper fence, there are **no outliers** in the sample.
(c)
(i) Pearson’s Coefficient of Skewness = \(\frac{3(\bar{x} – m)}{s} = \frac{3(5.12 – 4.885)}{0.743} \approx 0.949\).
(ii) An “X” is marked on the graph at the coordinate (\(0.949, 20\)).![]()
(d)
(i) Based on the graph, the point (\(0.949, 20\)) falls into the region labeled “The distribution of sample data is considered strongly skewed.”
(ii) No, the normality condition is not satisfied. The sample size (\(n=20\)) is not greater than or equal to \(30\), and the analysis in part (d-i) shows that the distribution of the sample data is strongly skewed.
