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AP Statistics 2.3 - Statistics for Two Categorical Variables- MCQs - Exam Style Questions

Question

A random sample of \(1{,}092\) people were asked whether color was a consideration in buying a new car. They were also asked to identify one additional feature that was important. The responses are shown in the table.
 YesNoMaybeTotal
Comfort\(40\)\(96\)\(12\)\(148\)
Cost\(108\)\(68\)\(8\)\(184\)
Performance\(62\)\(62\)\(12\)\(136\)
Reliability\(128\)\(116\)\(4\)\(248\)
Safety\(152\)\(192\)\(32\)\(376\)
Total\(490\)\(534\)\(68\)\(1{,}092\)
Which of the following is closest to the proportion of people who responded no to color consideration and who identified safety as the additional feature that was important?
(A) \(0.18\)
(B) \(0.34\)
(C) \(0.36\)
(D) \(0.49\)
(E) \(0.51\)
▶️ Answer/Explanation
Detailed solution

We want the joint proportion of all respondents who chose “No” for color consideration and “Safety” as the additional feature.
From the table, that cell count is \(192\). The total number of respondents is \(1{,}092\).
Compute the proportion: \[ \hat{p}=\frac{192}{1{,}092}\approx 0.176\approx 0.18. \] ✅ Answer: (A)

Why the other options are wrong:
(B) \(\frac{376}{1{,}092}\approx 0.34\) — proportion who selected Safety overall (Yes/No/Maybe combined).
(C) \(\frac{192}{534}\approx 0.36\) — conditional proportion among those who said “No.”
(D) \(\frac{534}{1{,}092}\approx 0.49\) — proportion who said “No” regardless of feature.
(E) \(\frac{1{,}092-534}{1{,}092}=\frac{558}{1{,}092}\approx 0.51\) — proportion who did not say “No.”

Question

Ali surveyed \(200\) students at a school and recorded the eye color and the gender of each student. Of the \(80\) male students who were surveyed, \(60\) had brown eyes. If eye color and gender are independent, how many female students surveyed would be expected to have brown eyes?
(A) \(5\)
(B) \(20\)
(C) \(30\)
(D) \(90\)
(E) \(100\)
▶️ Answer/Explanation
Detailed solution

1. Determine Sample Sizes:
– Total students = \(200\)
– Male students = \(80\)
– Female students = \(200 – 80 = 120\)

2. Use the Assumption of Independence:
If gender and eye color are independent, the proportion of students with brown eyes should be the same for both males and females.

3. Calculate the Proportion of Brown Eyes:
From the male group, the proportion with brown eyes is: \(\frac{60}{80} = 0.75\).

4. Calculate the Expected Number of Females:
Apply this proportion to the number of female students.
Expected Females with Brown Eyes = (Number of Females) \(\times\) (Proportion with Brown Eyes)
Expected = \(120 \times 0.75 = 90\)
Answer: (D)

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