AP Statistics 2.8 Least Squares 2 Regression- MCQs - Exam Style Questions
Question
(B) The least-squares regression line of height versus age will have a slope of \(0.8\).
(C) The proportion of the variation in height that is explained by a regression on age is \(0.64\).
(D) The least-squares regression line will correctly predict height based on age \(80\%\) of the time.
(E) The least-squares regression line will correctly predict height based on age \(64\%\) of the time.
▶️ Answer/Explanation
The correlation coefficient is \(r=0.8\). The coefficient of determination is \(r^2\), which gives the proportion of variation in the response (height) explained by the linear regression on the explanatory variable (age).
Compute \(r^2=(0.8)^2=0.64\). Thus, about \(64\%\) of the variation in height is explained by the regression on age.
Statements about the slope or prediction “percent correct” misinterpret \(r\).
✅ Answer: (C)
Question
Estimate | Std Error | t Ratio | Prob>|t| | |
---|---|---|---|---|
Intercept | 1.882 | 6.6854 | 0.28 | 0.7847 |
Number of items | 2.784 | 0.2265 | 12.29 | <0.0001 |
(B) $2.784\pm2.262(0.2265)$
(C) $2.784\pm2.262(\frac{0.2265}{\sqrt{11}})$
(D) $1.882\pm1.96(6.6854)$
(E) $1.882\pm2.262(6.6854)$
▶️ Answer/Explanation
1. Identify the Goal and Formula:
We need a 95% confidence interval for the slope of the regression line. The slope represents the average change in cost for each additional item.
The general formula is: $b \pm t^*(SE_b)$
2. Extract Values from the Table:
– The slope estimate ($b$) is the coefficient for “Number of items”: $b = 2.784$.
– The standard error of the slope ($SE_b$) is given in the same row: $SE_b = 0.2265$.
3. Determine the Critical Value ($t^*$):
– The confidence level is 95%.
– The degrees of freedom ($df$) for slope in linear regression is $n-2$.
– With a sample size of $n=11$, we have $df = 11 – 2 = 9$.
– The critical value $t^*$ for 95% confidence with 9 degrees of freedom is 2.262.
4. Construct the Interval:
Substitute the values into the formula:
$2.784 \pm 2.262(0.2265)$
✅ Answer: (B)