AP Statistics 3.13 Carrying Out a Test for the Difference Between Two Population Proportions- Exam Style Questions - MCQs - New Syllabus
Question
(B) \(\hat{p}_c=\dfrac{79}{230}\approx0.3435\)
(C) \(\hat{p}_c=\dfrac{51+79}{170+230}=0.325\)
(D) \(\hat{p}_c=\dfrac{0.30+0.3435}{2}\approx0.3218\)
▶️ Answer/Explanation
For a test of \(H_0:p_{\text{younger}}=p_{\text{older}}\), the large counts condition and standard error use the combined sample proportion.
The combined sample proportion is calculated by combining the successes and combining the total sample sizes:
\(\hat{p}_c=\dfrac{51+79}{170+230}\)
\(\hat{p}_c=\dfrac{130}{400}=0.325\)
This value is then used to calculate expected successes and failures for both samples.
✅ Answer: (C)
Question
The Interstate Highway Act of 1957 designated a scheme for numbering of the Interstate highways in the United States. A recent survey was taken asking people in the United States if they could explain the difference between an odd-numbered highway and an even-numbered highway. In a randomly selected sample of people aged 40 and older, 203 out of 240 were able to explain the difference. In a randomly selected sample of people under the age of 40, 188 out of 240 were able to explain the difference. Based on these samples, is there a significant difference in the proportion of people in the United States aged 40 and older and people under age 40 who can explain the difference between odd-numbered routes and even-numbered routes in the US Interstate Highway numbering system?
Note: Odd-numbered routes generally run north to south and even-numbered routes generally run east to west.
(A) Since the test statistic is 1.8 which is greater than 1, we can conclude there is a statistical difference between the two age groups (40 and older versus under 40).
(B) Since 0.04 < 0.05, we can conclude there is a statistical difference between the two age groups (40 and older versus under 40).
(C) Since 0.06 > 0.05, we can conclude there is insufficient evidence of a statistical difference between the two age groups (40 and older versus under 40).
(D) Since 0.08 > 0.05, we can conclude there is a statistical difference between the two age groups (40 and older versus under 40).
(E) Since 0.08 > 0.05, we can conclude there is insufficient evidence of a statistical difference between the two age groups (40 and older versus under 40).
▶️ Answer/Explanation
First compute the sample proportions:
\(\hat{p}_1=\frac{203}{240}=0.8458\)
\(\hat{p}_2=\frac{188}{240}=0.7833\)
The difference in sample proportions is:
\(\hat{p}_1-\hat{p}_2=0.0625\)
A two-proportion z-test for these data gives a p-value of approximately 0.08. Since:
\(0.08 > 0.05\)
we fail to reject the null hypothesis. There is not enough evidence to conclude that the population proportions differ between the two age groups.
✅ Answer: (E)
Question
Two types of medication were given to different patients to determine if there is a difference in the proportion of adults who showed a reduction in headache symptoms within 30 minutes of taking each medication. Eighteen out of the randomly sampled 300 adults given medication A did not see a reduction in their headache symptoms within 30 minutes. Twenty-four out of another random sample of 300 adults given medication B did not see a reduction in headache symptoms within 30 minutes of taking the medication.
Which of the following is the correct test statistic to test if there is statistical evidence of a difference in the effectiveness between Medication A and Medication B?
(A) \(\frac{0.94-0.92}{\sqrt{0.94(0.06)\left(\frac{2}{600}\right)}}\)
(B) \(\frac{0.94-0.92}{\sqrt{0.08(0.92)\left(\frac{1}{300}+\frac{1}{300}\right)}}\)
(C) \(\frac{0.08-0.06}{\sqrt{0.06(0.92)\left(\frac{2}{600}\right)}}\)
(D) \(\frac{0.94-0.92}{\sqrt{0.06(0.94)\left(\frac{1}{300}+\frac{1}{300}\right)}}\)
(E) \(\frac{0.94-0.92}{\sqrt{0.93(0.07)\left(\frac{1}{300}+\frac{1}{300}\right)}}\)
▶️ Answer/Explanation
For Medication A, the proportion showing improvement is:
\(\hat{p}_1=\frac{300-18}{300}=\frac{282}{300}=0.94\)
For Medication B, the proportion showing improvement is:
\(\hat{p}_2=\frac{300-24}{300}=\frac{276}{300}=0.92\)
For a two-proportion z-test, use the pooled proportion:
\(\hat{p}=\frac{282+276}{600}=\frac{558}{600}=0.93\)
\(\hat{q}=1-\hat{p}=0.07\)
The test statistic is:
\(z=\frac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p}\hat{q}\left(\frac{1}{n_1}+\frac{1}{n_2}\right)}}\)
\(\frac{0.94-0.92}{\sqrt{0.93(0.07)\left(\frac{1}{300}+\frac{1}{300}\right)}}\)
This matches choice (E).
✅ Answer: (E)
