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AP Statistics 3.9 Sampling Distributions for the Difference Between Sample Proportions- Exam Style Questions - FRQs - New Syllabus

Question

A French study was conducted in the 1990s to compare the effectiveness of using an instrument called a cardiopump with the effectiveness of using traditional cardiopulmonary resuscitation (CPR) in saving lives of heart attack victims. Heart attack patients in participating cities were treated with either a cardiopump or CPR, depending on whether the individual’s heart attack occurred on an even-numbered or an odd-numbered day of the month. Before the start of the study, a coin was tossed to determine which treatment, a cardiopump or CPR, was given on the even-numbered days. The other treatment was given on the odd-numbered days. In total, 754 patients were treated with a cardiopump, and 37 survived at least one year; while 746 patients were treated with CPR, and 15 survived at least one year.
(a) The conditions for inference are satisfied in the study. State the conditions and indicate how they are satisfied.
(b) Perform a statistical test to determine whether the survival rate for patients treated with a cardiopump is significantly higher than the survival rate for patients treated with CPR.

Most-appropriate topic codes (AP Statistics):

• Topic \(3.12\) — Setting Up a Test for the Difference Between Two Population Proportions (Part \(\mathrm{b}\): hypotheses and test selection)
• Topic \(3.13\) — Carrying Out a Test for the Difference Between Two Population Proportions (Part \(\mathrm{b}\): test statistic, \(p\)-value, and conclusion)
• Topic \(3.9\) — Sampling Distributions for the Difference Between Sample Proportions (Part \(\mathrm{a}\): large counts condition for inference)
• Topic \(1.13\) — Experimental Design (Part \(\mathrm{a}\): random assignment of treatments)
▶️ Answer/Explanation

Let \(p_A\) = true proportion of patients who survive at least one year if treated with the cardiopump.
Let \(p_B\) = true proportion of patients who survive at least one year if treated with CPR.

(a)
The two conditions required for a two-sample \(z\)-test comparing proportions in an experiment are:
Condition 1 — Random assignment of treatments: Before the study began, a coin was tossed to determine which treatment was assigned to even-numbered days and which to odd-numbered days. This coin toss serves as a reasonable approximation to randomly assigning the two treatments to the available subjects, so this condition is satisfied.
Condition 2 — Sufficiently large sample sizes: All four counts (successes and failures for each group) must be at least 5. Checking:
\(n_A \hat{p}_A = 37 \geq 5, \quad n_A(1-\hat{p}_A) = 754 – 37 = 717 \geq 5\)
\(n_B \hat{p}_B = 15 \geq 5, \quad n_B(1-\hat{p}_B) = 746 – 15 = 731 \geq 5\)
All four values are well above 5, so the large sample condition is satisfied.

(b)

Step 1 — Hypotheses:
\(H_0: p_A = p_B \quad \text{(or } p_A – p_B = 0\text{)}\)
\(H_a: p_A > p_B \quad \text{(or } p_A – p_B > 0\text{)}\)

Step 2 — Test: Two-sample \(z\)-test for proportions (one-sided).

Step 3 — Compute the test statistic:
First, compute the pooled sample proportion:
\(\hat{p} = \frac{n_A \hat{p}_A + n_B \hat{p}_B}{n_A + n_B} = \frac{37 + 15}{754 + 746} = \frac{52}{1500} \approx 0.0347\)
Now compute the \(z\)-statistic:
\(z = \frac{\hat{p}_A – \hat{p}_B}{\sqrt{\hat{p}(1-\hat{p})\left(\dfrac{1}{n_A} + \dfrac{1}{n_B}\right)}}\)
\(z = \frac{\dfrac{37}{754} – \dfrac{15}{746}}{\sqrt{(0.0347)(1 – 0.0347)\left(\dfrac{1}{754} + \dfrac{1}{746}\right)}} \approx 3.066\)
The corresponding one-sided \(p\)-value is:
\(p\text{-value} = P(Z > 3.066) \approx 0.0011\)

Step 4 — Conclusion:
Since the \(p\)-value of \(0.0011\) is much less than any reasonable significance level (such as \(\alpha = 0.05\) or \(\alpha = 0.01\)), we reject \(H_0\).
There is strong statistical evidence that the proportion of patients who survive at least one year is higher when treated with the cardiopump than when treated with CPR — that is, the cardiopump has a significantly higher survival rate than CPR.

Question

A study was conducted to determine if taking vitamin C reduces the occurrence of the flu. The study was conducted using 808 student volunteers who did not take a flu shot. The subjects were randomly assigned to one of two groups: a treatment group who received 1,000 milligrams of vitamin C daily or a control group who received a placebo flavored to taste like the vitamin C treatment. All participants were monitored to ensure that they adhered to their assigned treatment on a daily basis throughout the period of the study. At the end of the flu season, each subject’s medical record was reviewed by a physician to determine whether he or she had contracted the flu during the period of the study. The physician did not know which treatment each subject received. The results of the study are shown in the table below.
(a) Is this study an experiment or an observational study? Explain your answer.
(b) Based on this study, a health expert claims that there is evidence to suggest that vitamin C reduces the occurrence of the flu in the population of students who would volunteer for such a study. State the name of a test and the null and alternative hypotheses that the health expert could have used to support this claim. Do not carry out the test.

Most-appropriate topic codes (AP Statistics):

• Topic 1.13 — Experimental Design (Part a)
• Topic 3.12 — Setting Up a Test for the Difference Between Two Population Proportions (Part b)
• Topic 3.13 — Carrying Out a Test for the Difference Between Two Population Proportions (Part b)
• Topic 3.9 — Sampling Distributions for the Difference Between Sample Proportions (Part b)
▶️ Answer/Explanation

(a)

This study is an experiment, not an observational study.
In an experiment, the researchers deliberately impose a treatment on the subjects — here, the researchers assigned subjects to either the vitamin C group or the placebo group, rather than simply observing what subjects naturally chose to do.
Crucially, subjects were randomly assigned to the two treatment groups, which is the hallmark of a well-designed experiment and allows for causal conclusions to be drawn.
The use of a placebo and blind evaluation by a physician further strengthen this as a controlled experiment.

(b)

The health expert could use a two-proportion \(z\)-test to support this claim.
Let \(p_T\) be the true proportion of students (in the population of volunteers) who contract the flu when taking vitamin C, and let \(p_C\) be the true proportion who contract the flu when taking a placebo.
The hypotheses are:
\( H_0: p_T – p_C = 0 \quad \text{(vitamin C has no effect on flu occurrence)} \)
\( H_a: p_T – p_C < 0 \quad \text{(vitamin C reduces flu occurrence)} \)
Equivalently, this can be written as \(H_0: p_T = p_C\) versus \(H_a: p_T < p_C\), where a one-sided alternative is used because the claim is specifically that vitamin C reduces the occurrence of flu.

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