Home / AP® Exam / AP® Statistics / 4.2 Estimating Probabilities Using Simulation- FRQs

AP Statistics 4.2 Estimating Probabilities Using Simulation- FRQs - Exam Style Questions

Question

To increase morale among employees, a company began a program in which one employee is randomly selected each week to receive a gift card. Each of the company’s \( 200 \) employees is equally likely to be selected each week, and the same employee could be selected more than once. Each week’s selection is independent from every other week.
(a) Consider the probability that a particular employee receives at least one gift card in a \( 52 \)-week year.
(i) Define the random variable of interest and state how the random variable is distributed.
(ii) Determine the probability that a particular employee receives at least one gift card in a \( 52 \)-week year. Show your work.
(b) Calculate and interpret the expected value for the number of gift cards a particular employee will receive in a \( 52 \)-week year. Show your work.
(c) Suppose that Agatha, an employee at the company, never receives a gift card for an entire \( 52 \)-week year. Based on her experience, does Agatha have a strong argument that the selection process was not truly random? Explain your answer.

Most-appropriate topic codes (CED):

TOPIC 4.10: Introduction to the Binomial Distribution — part (a)
TOPIC 4.8: Mean and Standard Deviation of Random Variables — part (b)
TOPIC 4.2: Estimating Probabilities Using Simulation — part (c)
▶️ Answer/Explanation
Detailed solution

(a)
(i) Let \( X \) = the number of gift cards a particular employee receives in a \( 52 \)-week year.
\( X \) follows a binomial distribution with \( n = 52 \) trials and probability of success \( p = \frac{1}{200} = 0.005 \) for each trial.

(ii) The probability that a particular employee receives at least one gift card is:
\( P(X \geq 1) = 1 – P(X = 0) \)
\( P(X = 0) = \binom{52}{0}(0.005)^0(0.995)^{52} = (1)(1)(0.995)^{52} \approx 0.7705 \)
\( P(X \geq 1) = 1 – 0.7705 = 0.2295 \)
The probability is approximately \( \boxed{0.2295} \).

(b)
The expected value is:
\( E(X) = np = 52 \times 0.005 = 0.26 \)
Interpretation: If this random selection process is repeated over many years, a particular employee would receive an average of \( 0.26 \) gift cards per year, or about one gift card every four years.

(c)
No, Agatha does not have a strong argument that the selection process was not truly random.
Explanation: The probability that a particular employee receives no gift cards in a \( 52 \)-week year is \( (0.995)^{52} \approx 0.7705 \), which means there’s about a \( 77\% \) chance that any given employee would not receive a gift card in a year. Since this is quite likely to occur by random chance, Agatha’s experience does not provide strong evidence against the randomness of the selection process.

Scroll to Top