AP Statistics 4.9 Setting Up a Test for the Difference Between Two Population Mean - Exam Style Questions - MCQs - New Syllabus
Question
A survey was conducted with a random sample of 250 U.S. adults who had school-age children and 300 U.S. adults who did not have school-age children. Each adult reported their current salary. The average salary for the 250 adults who had school-age children was $\$54,420$ and the average salary for the 300 adults who did not have school-age children was $\$63,050$.
Research Question: Is the population mean salary different for people who have school-age children versus those not having school-age children?
What is the correct alternative hypothesis statement?
(A) \(\mu_1 \ne \mu_2\) where 1 = people who have school-age children and 2 = people who do not have school-age children
(B) \(\mu_1 = \mu_2\) where 1 = people who have school-age children and 2 = people who do not have school-age children
(C) \(\mu_1 < \mu_2\) where 1 = people who have school-age children and 2 = people who do not have school-age children
(D) \(p_1 \ne p_2\) where 1 = people who have school-age children and 2 = people who do not have school-age children
(E) \(p_1 < p_2\) where 1 = people who have school-age children and 2 = people who do not have school-age children
▶️ Answer/Explanation
The research question asks whether the population mean salary is different between two groups. Because the parameter of interest is a mean, the hypotheses must use \(\mu\), not \(p\).
The phrase “is different” indicates a two-sided test, so the alternative hypothesis should allow for either group to have the larger mean.
Therefore, the correct alternative hypothesis is:
\(H_A:\mu_1 \ne \mu_2\)
where group 1 consists of adults with school-age children and group 2 consists of adults without school-age children.
✅ Answer: (A)
Question
| \(n\) | Mean | Standard Deviation | |
|---|---|---|---|
| \(9\text{ a.m.}\) | \(50\) | \(15.2\) | \(4.12\) |
| \(3\text{ p.m.}\) | \(50\) | \(17.9\) | \(4.43\) |
(B) The two groups are paired because all children answered the same \(25\) questions.
(C) The two groups are paired because both groups had the same sample size, \(n=50\).
(D) The two groups are independent because the two sample means are different.
▶️ Answer/Explanation
A paired \(t\)-test is used when each observation in one group has a natural matching observation in the other group, such as the same child tested twice or matched pairs of children.
In this study, different children were assigned to the \(9\text{ a.m.}\) and \(3\text{ p.m.}\) groups. A child in the \(9\text{ a.m.}\) group is not naturally paired with a particular child in the \(3\text{ p.m.}\) group.
Therefore, the two samples are independent, so a two-sample \(t\)-test for the difference in two population means is appropriate.
✅ Answer: (A)
Question

(B) A chi-square test of independence
(C) A matched-pairs \(t\)-test for means
(D) A two-sample \(t\)-test for means
(E) A linear regression \(t\)-test
▶️ Answer/Explanation
1. Identify Data Type:
We have quantitative data (test scores) from two independent groups.
2. Appropriate Test:
To compare means from two independent groups, use two-sample t-test.
3. Why Other Tests are Incorrect:
(A) & (B) are for categorical data
(C) is for paired/dependent data
(E) is for relationship between two quantitative variables
✅ Answer: (D)
