AP Statistics 6.10 Setting Up a Test for the Difference of Two Population Proportions- MCQs - Exam Style Questions
Question
(B) Two proportion z-test
(C) One sample z-test for a mean
(D) One sample t-test for a mean
(E) Two sample t-test for means
▶️ Answer/Explanation
1. Identify the Parameter of Interest:
The study is comparing the **proportion** of hand-washers in two groups. This eliminates the tests for means (C, D, E).
2. Identify the Number of Groups:
Data were collected from two independent groups: \(634\) females and \(561\) males. The goal is to compare the proportions between these two groups.
3. Select the Appropriate Test:
The correct procedure for comparing two proportions from two independent samples is a **two-proportion z-test**.
✅ Answer: (B)
Question
(B) 0.9893
(C) 0.9453
(D) 0.0547
(Ε) 0.0439
▶️ Answer/Explanation
This is a binomial probability problem.To escape experimentation, you must get 8 or more questions correct (i.e., 8, 9, or 10 correct) .
The parameters for the binomial distribution are:
– Number of trials, $n = 10$ (ten questions).
– Probability of success, $p = 0.5$ (guessing on a true-false test).
We need to find $P(X \ge 8) = P(X=8) + P(X=9) + P(X=10)$.
The binomial formula is $P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}$.
1. $P(X=8) = \binom{10}{8} (0.5)^8 (0.5)^2 = 45 \times (0.5)^{10} \approx 0.0439$
2. $P(X=9) = \binom{10}{9} (0.5)^9 (0.5)^1 = 10 \times (0.5)^{10} \approx 0.0098$
3. $P(X=10) = \binom{10}{10} (0.5)^{10} (0.5)^0 = 1 \times (0.5)^{10} \approx 0.0010$
Adding these probabilities together: $0.0439 + 0.0098 + 0.0010 = 0.0547$.
✅ Answer: (D)
