AP Statistics 6.8 Confidence Intervals for the Difference of Two Proportions- FRQs - Exam Style Questions
Question
A polling agency showed the following two statements to a random sample of \(1,048\) adults in the United States.
Environment statement: Protection of the environment should be given priority over economic growth.
Economy statement: Economic growth should be given priority over protection of the environment.
The order in which the statements were shown was randomly selected for each person in the sample. After reading the statements, each person was asked to choose the statement that was most consistent with his or her opinion. The results are shown in the table.
| Environment Statement | Economy Statement | No Preference | |
|---|---|---|---|
| Percent of sample | \(58\%\) | \(37\%\) | \(5\%\) |
Most-appropriate topic codes (CED):
• TOPIC 6.3: Justifying a Claim Based on a Confidence Interval for a Population Proportion — part (a)
• TOPIC 5.5: Sampling Distributions for Sample Proportions — part (b)
• TOPIC 6.8: Confidence Intervals for the Difference of Two Proportions — part (c)
▶️ Answer/Explanation
(a)
State: We want to construct and interpret a \(95\%\) confidence interval for \(p\), the true proportion of all adults in the United States who would have chosen the economy statement.
Plan: The appropriate procedure is a one-sample z-interval for a population proportion. The problem states that the conditions for inference have been met , so we do not need to check them.
Do: The sample proportion is \(\hat{p} = 0.37\).The sample size is \(n = 1,048\) For a \(95\%\) confidence level, the critical value is \(z^* = 1.96\).
The confidence interval is calculated using the formula: [\[ \hat{p} \pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \] \[ 0.37 \pm 1.96 \sqrt{\frac{(0.37)(1-0.37)}{1,048}} \] \[ 0.37 \pm 1.96 \sqrt{\frac{(0.37)(0.63)}{1,048}} \] \[ 0.37 \pm 1.96 \sqrt{0.000222} \] \[ 0.37 \pm 1.96 (0.0149) \] \[ 0.37 \pm 0.0292 \] The interval is \((0.3408, 0.3992)\).
Conclude: We are \(95\) percent confident that the interval from \(0.34\) to \(0.40\) captures the true proportion of all adults in the United States who would have chosen the economy statement.
(b)
This condition, often called the Large Counts condition (\(n\hat{p} \ge 10\) and \(n(1-\hat{p}) \ge 10\)), is necessary to ensure that the sampling distribution of the sample proportion, \(\hat{p}\), is approximately normal. The formula used to calculate the z-confidence interval relies on the normal approximation to the binomial distribution. This approximation is reasonably accurate only when the expected number of successes and failures are both sufficiently large (at least \(10\)) .
(c)
No, the two-sample z-interval for a difference between proportions is not an appropriate procedure.
Justification: This procedure requires the two proportions to come from two independent random samples. In this study, there was only one random sample of \(1,048\) adults. The proportions of adults choosing the environment statement (\(58\%\)) and the economy statement (\(37\%\)) were calculated from the responses of the same group of people. Therefore, the two proportions are not independent; they are dependent because they come from the same sample, and the choice of one statement affects whether the other could be chosen.
