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AP Statistics 7.10 Skills Focus: Selecting, Implementing, and Communicating Inference Procedures- MCQs - Exam Style Questions

Question

A study will be conducted to examine a new medicine intended to reduce high blood pressure in adult men who have high blood pressure. As part of the study, a random sample of 40 men with high blood pressure will have their blood pressure measured, and then they will take the new medicine every day for one month. At the end of the month, their blood pressure will be measured again.
Of the following, which is the best procedure to investigate whether there will be convincing statistical evidence of a change, on average, in blood pressure for men with high blood pressure who take the new medicine?
(A) A one-sample z-test for a proportion
(B) A two-sample z-test for a difference between proportions
(C) A two-sample t-test for the difference between two means
(D) A matched-pairs t-test for a mean difference
(E) A chi-square test of independence
▶️ Answer/Explanation
Detailed solution

1. Analyze the Study Design:
The study measures the blood pressure of each of the 40 men twice: once before the treatment and once after. Because the two measurements are taken from the same subject, the data are not independent; they are paired.

2. Determine the Type of Data:
Blood pressure is a quantitative measurement, not a proportion or categorical count. The goal is to investigate the “change, on average,” which points to a test involving means.

3. Select the Correct Statistical Test:
– Tests for proportions (A, B) and categorical data (E) are incorrect.
– A two-sample t-test (C) is used for comparing the means of two independent groups. This is incorrect because our “before” and “after” groups are dependent.
– A matched-pairs t-test for a mean difference (D) is the appropriate procedure. This test analyzes the differences between the paired measurements for each subject (e.g., $BP_{after} – BP_{before}$) to determine if the average difference is statistically significant.

Answer: (D)

Question

A \(99\) percent one-sample z-interval for a proportion will be created from the point estimate obtained from each of two random samples selected from the same population: sample R and sample S. Let R represent a random sample of size \(1,000\), and let S represent a random sample of size \(4,000\). If the point estimate obtained from R is equal to the point estimate obtained from S, which of the following must be true about the respective margins of error constructed from those samples?
(A) The margin of error for S will be \(4\) times the margin of error for R.
(B) The margin of error for S will be \(2\) times the margin of error for R.
(C) The margin of error for S will be equal to the margin of error for R.
(D) The margin of error for R will be \(4\) times the margin of error for S.
(E) The margin of error for R will be \(2\) times the margin of error for S.
▶️ Answer/Explanation
Detailed solution

1. Margin of Error (ME) Formula:
\(ME = z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\)

2. Analyze the Relationship:
Since \(z^*\) and \(\hat{p}\) are the same for both samples, the ME is proportional to \(\frac{1}{\sqrt{n}}\).
– \(ME_R \propto \frac{1}{\sqrt{1000}}\)
– \(ME_S \propto \frac{1}{\sqrt{4000}}\)

3. Compare the Margins of Error:
To find the relationship, take the ratio:
\(\frac{ME_R}{ME_S} = \frac{1/\sqrt{1000}}{1/\sqrt{4000}} = \frac{\sqrt{4000}}{\sqrt{1000}} = \sqrt{\frac{4000}{1000}} = \sqrt{4} = 2\)

Therefore, \(ME_R = 2 \times ME_S\).
Answer: (E)

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