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AP Statistics 1.10 The Normal Distribution - MCQs - Exam Style Questions

Question

The distribution of the sale price of a certain car model is approximately normal with a mean of \(\$65{,}200\) and a standard deviation of \(\$3{,}100\). Based on the distribution, which of the following is an appropriate conclusion?
(A) Approximately \(5\%\) of the cars of this model have a sale price less than \(\$56{,}700\).
(B) Approximately \(99\%\) of the cars of this model have a sale price between \(\$57{,}500\) and \(\$73{,}500\).
(C) The interquartile range of the car model’s sale price is approximately \(\$6{,}200\).
(D) The maximum of the car model’s sale price is \(\$69{,}800\).
(E) Approximately \(84\%\) of the cars of this model have a sale price greater than \(\$57{,}400\).
▶️ Answer/Explanation
Detailed solution
Use the normal model with mean \(\mu=65{,}200\) and standard deviation \(\sigma=3{,}100\).
Empirical/normal-rule benchmarks: about \(68\%\) within \(\pm1\sigma\), \(95\%\) within \(\pm2\sigma\), and \(99.7\%\) within \(\pm3\sigma\). Roughly \(99\%\) is within about \(\pm2.58\sigma\).
Check each statement quickly with \(z\)-scores:
• (A) \(56{,}700\) is \(z=\dfrac{56{,}700-65{,}200}{3{,}100}\approx -2.74\Rightarrow P\lt 1\%\), not \(5\%\). ✗
• (B) Endpoints: \(57{,}500\Rightarrow z\approx -2.48\); \(73{,}500\Rightarrow z\approx 2.68\). Central area between these \(z\)-values is about \(0.99\) (≈\(99\%\)). ✓
• (C) IQR for a normal is \(Q_3-Q_1\approx(0.674-(-0.674))\sigma\approx1.349\sigma\approx1.349(3{,}100)\approx \$4{,}180\), not \(\$6{,}200\). ✗
• (D) “Maximum” is not determined by a normal model; distribution is unbounded. ✗
• (E) \(57{,}400\Rightarrow z\approx -2.52\Rightarrow P(X\gt 57{,}400)\approx 0.99\), not \(84\%\). ✗
Answer: (B)

Question

A certain state has many mountains, and the heights of those mountains are approximately normally distributed with a mean of 10,500 feet and a standard deviation of 900 feet. Four of the mountains in the state are Trapper Peak, Granite Peak, Crazy Peak, and McDonald Peak. Trapper Peak has a height of 10,517 feet, Granite Peak’s height has a z-score of 2.56, Crazy Peak has a height of 11,214 feet, and McDonald Peak’s height has a z-score of −0.76.
Which of the following orders the mountains from the peak with the lowest height to the peak with the highest height?
(A) Trapper Peak, McDonald Peak, Crazy Peak, Granite Peak
(B) Granite Peak, Crazy Peak, Trapper Peak, McDonald Peak
(C) McDonald Peak, Granite Peak, Trapper Peak, Crazy Peak
(D) McDonald Peak, Trapper Peak, Crazy Peak, Granite Peak
(E) Trapper Peak, McDonald Peak, Granite Peak, Crazy Peak
▶️ Answer/Explanation
Detailed solution

Convert the z-scores to heights (mean \(=10500\), SD \(=900\)).
McDonald: \(x=10500+(-0.76)(900)=10500-684=9816\) ft.
Trapper: given \(x=10517\) ft (≈ \(z=0.02\)).
Crazy: given \(x=11214\) ft.
Granite: \(x=10500+2.56(900)=10500+2304=12804\) ft.
Order from lowest to highest: McDonald (9816), Trapper (10517), Crazy (11214), Granite (12804).
Answer: (D)

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