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Pre AP Chemistry -3.1B Ideal Gas Law and Gas Particles- MCQ Exam Style Questions -New Syllabus 2025-2026

Pre AP Chemistry -Link- MCQ Exam Style Questions – New Syllabus 2025-2026

Pre AP Chemistry -Link- MCQ Exam Style Questions – Pre AP Chemistry – per latest Pre AP Chemistry Syllabus.

Pre AP Chemistry – MCQ Exam Style Questions- All Topics

Question

\(10cm^{3}\) of ethane is burned in \(45cm_{3}\)  of oxygen at a pressure of 101kPa and a temperature of  200 °C. Complete combustion takes place. 

What is the total volume of gas present when the reaction is complete, measured under the same conditions?

A \(30cm^{3}\)          B \(50cm^{3}\)         C \(55cm^{3}\)          D \(60cm^{3}\)

▶️Answer/Explanation

Ans:D

Question: 

 1.8 g of water, heated to 227 °C in a sealed container, turns to steam with a pressure of 200 kPa.
What is the approximate volume of the container?

A \(9\times10^{-4}m^{3}\)          B \(2\times10^{3}m^{3}\)         C \(2m^{3}\)         D \(8\times10^{7}m^{3}\)

▶️Answer/Explanation

Ans:C

Question

The gas laws can be summarised in the ideal gas equation.
                                                                                         pV = nRT

0.960 g of oxygen gas is contained in a vessel of volume 7.00 × 10–3 m3 at a temperature of 30 °C.

Assume that the gas behaves as an ideal gas.
What is the pressure in the vessel?

A    1.07 kPa               B    2.14 kPa               C    10.8 kPa               D    21.6 kPa

Answer/Explanation

Answer:

C

Question

 A fluorescent light tube has an internal volume of 400 \(cm^3\) and an internal pressure of 200 kPa. It is filled with 0.03 moles of an ideal gas.

What is the temperature of the gas inside the fluorescent light tube?
A 3.21 × \(10^{–1}\)K
B 3.21 × \(10^2\)K
C 3.21 × \(10^5\)K
D 3.21 × \(10^8\)K

Answer/Explanation

Ans: B

Question

Use of the Data Booklet is relevant to this question. The gas laws can be summarised in the ideal gas equation below.

                                                                                                    pV = nRT

0.96 g of oxygen gas is contained in a glass vessel of volume \( 7.0 × 10^{–3}m^{3}\) at a temperature of 30°C. Assume the gas behaves as an ideal gas.
What is the pressure in the vessel?
A 1.1kPa                     B 2.1kPa                              C 10.8kPa                         D 21.6kPa

Answer/Explanation

Ans:C

Question .

 The gas laws can be summarised in the ideal gas equation.

pV = nRT

where each symbol has its usual meaning.

Which statements are correct?

  1. One mole of an ideal gas occupies the same volume under the same conditions of temperature and pressure.
  2. The density of an ideal gas at constant pressure is inversely proportional to the temperature, T.
  3. The volume of a given mass of an ideal gas is doubled if its temperature is raised from 25 °C to 50°C at constant pressure.

Answer/Explanation

Ans:

B

Question

 Under which set of conditions is a gas most likely to behave ideally?

Answer/Explanation

Ans:

B

Question

 Use of the Data Booklet is relevant to this question.

The gas laws can be summarised in the ideal gas equation.

pV = nRT

0.56g of ethene gas is contained in a vessel at a pressure of 102kPa and a temperature of 30°C.

What is the volume of the vessel?

A 49 cm3               B 494 cm3                C 48 900 cm3                D 494 000 cm3

Answer/Explanation

Ans:

B

 Question

In the ideal gas equation, pV = nRT, what are the units of n and T?

Answer/Explanation

Answer:    D

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