Bromoalkanes are used widely in industry, although there is increasing concern about their environmental impact.
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(a) Complete Fig. 4.2 to show the mechanism for the formation of 1,2-dibromoethane in reaction 1. Include charges, dipoles, lone pairs of electrons and curly arrows as appropriate. ![]()
(b) The enthalpy change of reaction 1, \(\Delta H_r\) = –90.0kJmol⁻¹.
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The enthalpy change of formation of ethene, \(ΔH_f\) = +52.2 kJ mol⁻¹. Calculate the enthalpy change of formation of 1,2-dibromoethane.
(c) (i) Complete Fig. 4.1 to:
• draw the structure of compound A
• name compound B.
(ii) Draw the structure of one repeat unit of polymer C in the box.
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(iii) In reaction 5, compound B reacts with an excess of NaOH dissolved in ethanol. The products are HBr, \(H_2O\), and an unsaturated hydrocarbon D. Suggest the identity of D.
(d) Compound E is the only isomer of 1,2-dibromoethane. Alkaline hydrolysis of E gives compound F.
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(i) Identify the type of isomerism shown by E and 1,2-dibromoethane.
(ii) Name the homologous series that F belongs to.
(iii) Complete Table 4.1 to state what is observed when F reacts with the reagents listed.
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(e) Compound F reacts with reagent G to form compound H.
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The infrared spectrum of H is shown in Fig. 4.3.
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H also shows a molecular ion peak at m/e = 60 in its mass spectrum.
(i) Use the information in (e), Fig. 4.3 and Table 4.2 to deduce the structure of H. Explain your answer fully. ![]()
(ii) Suggest the role of reagent G.
▶️ Answer/Explanation
(a)
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Explanation: The mechanism involves electrophilic addition where the π bond in ethene attacks Br₂, forming a bromonium ion intermediate. The Br⁻ then attacks from the opposite side, resulting in 1,2-dibromoethane.
(b) \(\Delta H_f\) of 1,2-dibromoethane = –142.2 kJ mol⁻¹.
Explanation: Using Hess’s Law, \(\Delta H_r = \Delta H_f(\text{products}) – \Delta H_f(\text{reactants})\). Given \(\Delta H_r = -90.0\) kJ mol⁻¹ and \(\Delta H_f(\text{ethene}) = +52.2\) kJ mol⁻¹, solving gives \(\Delta H_f(\text{1,2-dibromoethane}) = -90.0 – 52.2 = -142.2\) kJ mol⁻¹.
(c)(i) A: \(CH_2BrCH_2Br\), B: 1,2-dibromoethane.
(ii) Polymer C repeat unit: \(-CH_2-CH_2-\)
(iii) D: \(C_2H_2\) (ethyne).
Explanation: Elimination of HBr from 1,2-dibromoethane in the presence of NaOH/ethanol produces ethyne.
(d)(i) Structural/positional isomerism.
(ii) Aldehyde.
(iii)
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Explanation: F (ethanal) forms a silver mirror with Tollens’ reagent and a red precipitate with Fehling’s solution due to its aldehyde group.
(e)(i) H: \(CH_3COOH\) (ethanoic acid).
Explanation: The IR spectrum shows a broad O-H stretch (~3000 cm⁻¹) and a C=O stretch (~1700 cm⁻¹), consistent with a carboxylic acid. The mass spectrum peak at m/e = 60 matches ethanoic acid’s molecular weight.
(ii) Oxidising agent.
Explanation: Reagent G (e.g., acidified KMnO₄ or K₂Cr₂O₇) oxidises the aldehyde (F) to a carboxylic acid (H).
