Question
The drag coefficient \(C_{d}\) is a number with no units. It is used to compare the drag on different cars at different speeds. It is given by the equation
\(C_{d} = \frac{2F}{\rho v^{n}A}\)
where F is the drag force on the car, ρ is the density of the air, A is the cross-sectional area of the car and v is the speed of the car.
What is the value of n?
A \(1\) B \(2\) C \(3\) D \(4\)
Answer/Explanation
Ans: B
Since the drag coefficient is a constant, therefore it is unit less, hence the units of the numerator and denominator must be the same therefore
Question
One property Q of a material is used to describe the behaviour of sound waves in the material. Q is defined as the pressure P of the sound wave divided by the speed v of the wave and the surface area A of the material through which the wave travels:
\(Q = \frac{P}{vA}\).
What are the SI base units of Q?
A \(kg\, m^{2}\, s^{–3}\) B \(kg\, m^{–3}\, s^{–1}\) C \(kg\, m^{–4}\, s^{–1}\) D \(kg\, m^{–2}\, s^{–2}\)
The unit of the quantity Q is given as,
Answer/Explanation
Ans: C
Question
The Y-input terminals of a cathode-ray oscilloscope (c.r.o.) are connected to a supply of amplitude \(5.0\)V and frequency \(50\)Hz. The time-base is set at \(10\)ms per division and the Y-gain at \(5.0\) V per division.
Which trace is obtained?
The time period is given as,
T = 1/f
= 1/50 = 0.02 s
= 20 ms
In the graph A, the time period is 10 ms since the wave is repeating itself after 1 time base of 10 ms. Hence the option (A) is incorrect.
In the graph B, the time period is 20 ms and the amplitude of the voltage is less than 5 V, therefore the option (B) is incorrect.
In the graph C, the time period is 10 ms therefore the option (C) is incorrect.
Answer/Explanation
Ans: D
Question:
What is the unit of weight in terms of SI base unit(s)?
A \(kg~ms^{-1}\) B \(kg~ms^{-2}\) C \(n\) D \(J~m^{-1}\)
Answer/Explanation
B
The weight is given as,
W = mg
hence the unit is weight is
Question
What is a possible unit for the product VI, where V is the potential difference across a resistor and I is the current through the same resistor?
A newton per second \(N~s^-1\)
B newton second \(N~s\)
C newton metre \(N~m\)
D newton metre per second \(N~m~s^-1\)
Answer/Explanation
Ans:D
We know that the power is given as,
P = VI
therefore the units of VI is that of power, also we know that the power is given as,
P = Fv
therefore the units of power can be given as,
[P ] = Newton meter per second
Hence the option (D) is correct.