AS/A Level Physics Scalars and vectors Study Notes 2025-2027 Syllabus
AS/A Level Physics Scalars and vectors Study Notes
AS/A Level Physics Scalars and vectors Study Notes at IITian Academy focus on specific topic and type of questions asked in actual exam. Study Notes focus on AS/A Level Physics Study Notes syllabus with Candidates should be able to:
- Understand the difference between scalar and vector quantities and give examples of scalar and vector quantities included in the syllabus
- add and subtract coplanar vectors
- represent a vector as two perpendicular components
Scalar and Vector Quantities
All physical quantities are classified as either scalar or vector quantities, depending on whether they have a direction associated with them.
Scalar Quantity:
- A scalar quantity has magnitude only (size or numerical value).
- It is completely described by a number and a unit.
- It has no direction associated with it.
Vector Quantity:
- A vector quantity has both magnitude and direction.
- It is represented graphically by an arrow — the length shows the magnitude, and the arrowhead shows the direction.
- Vectors follow the laws of vector addition (e.g., triangle or parallelogram law).
Key Idea: 
- Scalars describe how much of a quantity exists.
- Vectors describe how much and in which direction the quantity acts.
Examples of Scalar and Vector Quantities in A Level Physics:
| Type | Quantity | Symbol (common) | SI Unit | 
|---|---|---|---|
| Scalars | Mass | \( \mathrm{m} \) | \( \mathrm{kg} \) | 
| Time | \( \mathrm{t} \) | \( \mathrm{s} \) | |
| Temperature | \( \mathrm{T} \) | \( \mathrm{K} \) | |
| Speed | \( \mathrm{v} \) | \( \mathrm{m/s} \) | |
| Distance | \( \mathrm{s} \) | \( \mathrm{m} \) | |
| Energy / Work | \( \mathrm{E,\,W} \) | \( \mathrm{J} \) | |
| Power | \( \mathrm{P} \) | \( \mathrm{W} \) | |
| Pressure | \( \mathrm{p} \) | \( \mathrm{Pa} \) | |
| Vectors | Displacement | \( \mathrm{\vec{s}} \) | \( \mathrm{m} \) | 
| Velocity | \( \mathrm{\vec{v}} \) | \( \mathrm{m/s} \) | |
| Acceleration | \( \mathrm{\vec{a}} \) | \( \mathrm{m/s^2} \) | |
| Force | \( \mathrm{\vec{F}} \) | \( \mathrm{N} \) | |
| Momentum | \( \mathrm{\vec{p}} \) | \( \mathrm{kg\,m/s} \) | |
| Weight | \( \mathrm{\vec{W}} \) | \( \mathrm{N} \) | |
| Electric field | \( \mathrm{\vec{E}} \) | \( \mathrm{N/C} \) | |
| Magnetic flux density | \( \mathrm{\vec{B}} \) | \( \mathrm{T} \) | 
Example — Distinguishing Scalar and Vector Quantities
During a race, a car travels \( \mathrm{100\,m} \) east in \( \mathrm{5.0\,s} \).
▶️ Answer / Explanation
Step 1: Distance travelled = \( \mathrm{100\,m} \) → has magnitude only → Scalar.
Step 2: Displacement = \( \mathrm{100\,m} \) east → has magnitude and direction → Vector.
Step 3: Average speed = \( \mathrm{distance/time = 20\,m/s} \) → Scalar.
Step 4: Average velocity = \( \mathrm{displacement/time = 20\,m/s\ east} \) → Vector.
Result: Scalars and vectors represent different aspects of motion even when numerical values appear identical.
Addition and Subtraction of Coplanar Vectors
Coplanar vectors are vectors that lie in the same plane. Adding or subtracting coplanar vectors allows us to determine the resultant (single equivalent) vector that represents their combined effect.
Key Idea:
- Vector addition combines two or more vectors to find their resultant.
- Vector subtraction finds the difference between two vectors — equivalent to adding one vector to the negative of another.
- Coplanar vector addition follows geometric laws such as the triangle law and parallelogram law.
1. Triangle Law of Vector Addition
Statement: If two vectors are represented in magnitude and direction by two sides of a triangle taken in order, then their resultant is represented in magnitude and direction by the third side of the triangle taken in the opposite order.
Mathematically:
\( \mathrm{\vec{R} = \vec{A} + \vec{B}} \)
Graphical Representation:
- Draw \( \mathrm{\vec{A}} \) to scale.
- From the head of \( \mathrm{\vec{A}} \), draw \( \mathrm{\vec{B}} \) to scale in its direction.
- The resultant \( \mathrm{\vec{R}} \) is drawn from the tail of \( \mathrm{\vec{A}} \) to the head of \( \mathrm{\vec{B}} \).
2. Parallelogram Law of Vector Addition
Statement: If two vectors are represented by the adjacent sides of a parallelogram, their resultant is represented by the diagonal of the parallelogram drawn from the same point.
Formula for Magnitude:
\( \mathrm{R = \sqrt{A^2 + B^2 + 2AB\cos\theta}} \)
where:
- \( \mathrm{R} \) = magnitude of resultant vector
- \( \mathrm{A, B} \) = magnitudes of the two vectors
- \( \mathrm{\theta} \) = angle between \( \mathrm{\vec{A}} \) and \( \mathrm{\vec{B}} \)
Direction of Resultant:
\( \mathrm{\tan\beta = \dfrac{B\sin\theta}{A + B\cos\theta}} \)
where \( \mathrm{\beta } \) is the angle between \( \mathrm{\vec{A}} \) and \( \mathrm{\vec{R}} \).
3. Subtraction of Vectors
Rule: To subtract one vector from another, reverse the direction of the vector to be subtracted and then add it using the triangle law.
\( \mathrm{\vec{R} = \vec{A} – \vec{B} = \vec{A} + (-\vec{B})} \)
- Here \( \mathrm{-\vec{B}} \) has the same magnitude as \( \mathrm{\vec{B}} \) but points in the opposite direction.
- Graphically, draw \( \mathrm{\vec{A}} \), then from its head draw \( \mathrm{-\vec{B}} \).
- The resultant \( \mathrm{\vec{R}} \) is drawn from the tail of \( \mathrm{\vec{A}} \) to the head of \( \mathrm{-\vec{B}} \).
Special Cases:
- If \( \mathrm{\theta = 0^\circ} \): vectors act in the same direction → \( \mathrm{R = A + B} \).
- If \( \mathrm{\theta = 180^\circ} \): vectors act in opposite directions → \( \mathrm{R = |A – B|} \).
- If \( \mathrm{\theta = 90^\circ} \): vectors are perpendicular → \( \mathrm{R = \sqrt{A^2 + B^2}} \).
Example
Two forces of magnitudes \( \mathrm{5\,N} \) and \( \mathrm{12\,N} \) act on a body at an angle of \( \mathrm{90^\circ} \) to each other. Find the magnitude and direction of their resultant.
▶️ Answer / Explanation
Step 1: Use the parallelogram law.
\( \mathrm{R = \sqrt{A^2 + B^2 + 2AB\cos\theta}} \)
\( \mathrm{R = \sqrt{5^2 + 12^2 + 2(5)(12)\cos90^\circ}} \)
\( \mathrm{R = \sqrt{25 + 144 + 0} = \sqrt{169} = 13\,N} \)
Step 2: Find the direction.
\( \mathrm{\tan\alpha = \dfrac{B\sin\theta}{A + B\cos\theta} = \dfrac{12\sin90}{5 + 12\cos90} = \dfrac{12}{5}} \)
\( \mathrm{\alpha = \tan^{-1}(2.4) = 67.4^\circ} \)
Result: The resultant force has magnitude \( \mathrm{13\,N} \) and acts at \( \mathrm{67.4^\circ} \) to the \( \mathrm{5\,N} \) force.
Representation of a Vector as Two Perpendicular Components
Any vector acting in a plane can be represented as the sum of two perpendicular (mutually at 90°) component vectors. These components are usually chosen along the horizontal (x-axis) and vertical (y-axis) directions. Resolving a vector into components means finding two perpendicular vectors which, when added together, produce the original vector. This helps in analyzing forces, motion, and other vector quantities along chosen axes.
Conceptual Diagram:
Consider a vector \( \mathrm{\vec{A}} \) making an angle \( \mathrm{\theta} \) with the horizontal axis.
The components are:
Horizontal component: \( \mathrm{A_x = A\cos\theta} \)
Vertical component: \( \mathrm{A_y = A\sin\theta} \)
The original vector can be written as:
\( \mathrm{\vec{A} = A_x\hat{i} + A_y\hat{j}} \)
Derivation (from Geometry):
- Draw vector \( \mathrm{\vec{A}} \) making an angle \( \mathrm{\theta} \) with the x-axis.
- Drop a perpendicular from the tip of \( \mathrm{\vec{A}} \) onto the x-axis to form a right triangle.
- Using trigonometric ratios:
\( \mathrm{\cos\theta = \dfrac{A_x}{A}} \Rightarrow A_x = A\cos\theta \)
\( \mathrm{\sin\theta = \dfrac{A_y}{A}} \Rightarrow A_y = A\sin\theta \)
Recombination: The magnitude of the original vector is obtained from Pythagoras’ theorem:
\( \mathrm{A = \sqrt{A_x^2 + A_y^2}} \)
and its direction is given by:
\( \mathrm{\tan\theta = \dfrac{A_y}{A_x}} \)
Advantages of Resolving Vectors:
- Allows separate analysis of horizontal and vertical effects of a single vector (e.g., force or velocity).
- Helps apply equations of motion or Newton’s laws independently along each axis.
- Simplifies the addition of multiple non-parallel vectors by working with their components.
Special Notes:
- If the vector acts below the horizontal, the vertical component is negative.
- If it acts to the left, the horizontal component is negative.
- In component form, signs indicate direction relative to the chosen coordinate axes.
Example
A force of \( \mathrm{50\,N} \) acts at an angle of \( \mathrm{30^\circ} \) above the horizontal. Find its horizontal and vertical components.

▶️ Answer / Explanation
Step 1: Write the equations for components.

\( \mathrm{F_x = F\cos\theta, \quad F_y = F\sin\theta} \)
Step 2: Substitute values.
\( \mathrm{F_x = 50\cos30 = 50(0.866) = 43.3\,N} \)
\( \mathrm{F_y = 50\sin30 = 50(0.5) = 25.0\,N} \)
Result: \( \mathrm{F_x = 43.3\,N} \) horizontally, \( \mathrm{F_y = 25.0\,N} \) vertically upward.
