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CIE IGCSE Physics (0625) Turning effect of forces Study Notes

CIE IGCSE Physics (0625) Turning effect of forces Study Notes - New Syllabus

CIE IGCSE Physics (0625) Turning effect of forces  Study Notes

LEARNING OBJECTIVE

  • Understanding the concepts of Turning effect of forces 

Key Concepts: 

  • Moment
  • Principle of Moments
  • Equilibrium of an Object

CIE iGCSE Physics (0625)  Study Notes – All topics

Moment

Moment

  • The moment of a force is a measure of its turning effect about a point (called the pivot or fulcrum).
  • It tells us how effectively a force can cause an object to rotate or turn.
  • Greater force or greater distance from the pivot produces a bigger turning effect (larger moment).

Examples of Moments:

  • Opening a door — the handle is placed far from the hinge to increase the moment.
  • Using a spanner to tighten a bolt — a longer spanner increases the turning effect.
  • Seesaw — children of different weights sit at different distances from the pivot to balance.
  • Turning a tap, steering a wheel, or using a crowbar — all involve rotation about a point due to applied force.

Defining the Moment of a Force:

  • The moment of a force depends on:
    • The magnitude of the force.
    • The perpendicular distance from the pivot to the line of action of the force.

Formula:

Moment = Force × Perpendicular distance

\( \text{Moment} = F \times d \)

Where:

  • \( F \) = force in newtons (N)
  • \( d \) = perpendicular distance from pivot to line of action of force (in meters)
  • Moment is measured in newton-metres (Nm)

Example:

A person pushes a door with a force of 20 N at a point 0.8 m from the hinges. What is the moment produced?

▶️ Answer/Explanation

Use the formula: \( \text{Moment} = F \times d \)

\( \text{Moment} = 20 \times 0.8 = \boxed{16 \, \text{Nm}} \)

Example:

Two people apply the same 50 N force to loosen a nut using different spanners. Person A uses a 0.1 m spanner, Person B uses a 0.25 m spanner. Who produces the greater turning effect?

▶️ Answer/Explanation

Person A: \( M = 50 \times 0.1 = 5 \, \text{Nm} \)

Person B: \( M = 50 \times 0.25 = \boxed{12.5 \, \text{Nm}} \)

Person B creates the larger moment because the distance from the pivot is greater.

Principle of Moments

Principle of Moments

  • The principle of moments states that for an object in equilibrium (not turning):

    Total clockwise moment = Total anticlockwise moment

  • This applies to any system where forces are causing rotation about a pivot point.
  • If this condition is not met, the object will rotate.

How to Use It:

  • Choose a pivot point (can be one of the forces or an actual support).
  • Calculate the moment of each force: \( \text{Moment} = \text{Force} \times \text{Perpendicular distance to pivot} \).
  • Set up the equation:

    Clockwise moments = Anticlockwise moments

  • Solve for unknowns (force or distance).

Example:

A 2 m long uniform beam is balanced on a pivot at its center. A 30 N force is applied 0.8 m from the left of the pivot. Where must a 20 N force be applied on the right to keep the beam balanced?

▶️ Answer/Explanation

Step 1: Set up the moment equation.

Left (anticlockwise): \( 30 \times 0.8 = 24 \, \text{Nm} \)

Right (clockwise): \( 20 \times d \)

Step 2: Set moments equal:

\( 20d = 24 \Rightarrow d = \boxed{1.2 \, \text{m}} \)

So the 20 N force must be applied 1.2 m from the pivot to balance the beam.

Example:

A uniform beam is 3 m long and pivots at the center. On the left, a 15 N force is applied 0.5 m from the pivot, and a 10 N force is applied 1.2 m from the pivot. On the right, a single unknown force F is applied 0.9 m from the pivot. What is the value of F to balance the beam?

▶️ Answer/Explanation

Step 1: Calculate total anticlockwise moment:

\( (15 \times 0.5) + (10 \times 1.2) = 7.5 + 12 = 19.5 \, \text{Nm} \)

Step 2: Set this equal to clockwise moment:

\( F \times 0.9 = 19.5 \Rightarrow F = \dfrac{19.5}{0.9} = \boxed{21.7 \, \text{N}} \)

Example:

A 25 N force is applied 1.0 m to the left of the pivot. What distance from the pivot should a 20 N force be applied on the right to balance the moments?

▶️ Answer/Explanation

Anticlockwise moment: \( 25 \times 1 = 25 \, \text{Nm} \)

Clockwise moment: \( 20 \times d = 25 \Rightarrow d = \dfrac{25}{20} = \boxed{1.25 \, \text{m}} \)

Equilibrium of an Object

Equilibrium of an Object:

  • An object is said to be in equilibrium when both of the following conditions are satisfied:
    • There is no resultant force acting on the object — all forces cancel out.
    • There is no resultant moment acting — the object is not trying to rotate.
  • In equilibrium:
    • The object will stay at rest (if already at rest).
    • The object will move with constant velocity (if already moving).
    • The object will not start rotating or change its rotational state.

Experiment: Proving No Resultant Moment

  • Apparatus:
    • A uniform metre ruler (wood or metal)
    • A pivot (triangular wedge or clamp stand)
    • 2 or 3 known weights (e.g., 10 N, 5 N)
    • Clips or strings to hang weights at known distances
  • Procedure:
    1. Place the ruler on the pivot at its center (50 cm mark) and ensure it is level and balanced.
    2. Hang a known weight (e.g., 10 N) at a known distance to the left of the pivot (say at 30 cm → 20 cm from pivot).
    3. Hang another weight (e.g., 5 N) on the right side and move it until the ruler is perfectly horizontal and balanced again.
    4. Measure the distance of the second weight from the pivot.
    5. Calculate the moments about the pivot.
  • Expected Result:
    • When the ruler is balanced, total clockwise moment = total anticlockwise moment.
    • This proves that the object is in rotational equilibrium (no resultant moment).

Example:

A 10 N weight is hung 0.2 m to the left of the pivot on a uniform ruler. A 4 N weight is hung on the right and the system balances. At what distance from the pivot is the 4 N weight placed?

▶️ Answer/Explanation

Anticlockwise moment: \( 10 \times 0.2 = 2.0 \, \text{Nm} \)

Clockwise moment: \( 4 \times d = 2.0 \Rightarrow d = \boxed{0.5 \, \text{m}} \)

So the 4 N weight must be 0.5 m to the right of the pivot for the system to be in equilibrium.

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