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Edexcel iGCSE Biology 4BI1 - Paper 1B -Human influences on the environment- Exam Style Questions- New Syllabus

Question

Insect pests can eat and damage crop plants.

The cottony cushion scale insect is a pest that feeds on orange trees.

(a) This insect feeds from the phloem of the trees, reducing crop yield.

(i) Name two substances carried in the phloem.
(ii) Explain why insects feeding from the phloem can reduce crop yield from the orange trees.

(b) Farmers can reduce insect pests by using chemical pesticide or biological control.

Insects called ladybugs can be used as a method of biological control as they feed on the scale insects.

The graph shows how the number of scale insects changes after the introduction of ladybugs.

The graph also shows how the number of scale insects changes after being sprayed with an insecticide, a pesticide that kills insects.

(i) Discuss the effects that the introduction of ladybugs, and the use of insecticides, has on the numbers of scale insects.

Use information from the graph and your own knowledge to help with your answer.

(ii) Give three advantages of using biological control instead of pesticides to control pests.

Most-appropriate topic codes (Edexcel IGCSE Biology):

  • 3(h): Transport — part (a)
  • 6(a): Food production — parts (b)(i), (b)(ii)
  • 5(d): Human influences on the environment — parts (b)(i), (b)(ii)
  • 5(b): Feeding relationships — part (b)(i)
  • 2(e): Nutrition — part (a)(ii)
▶️ Answer/Explanation
Solution

(a)(i) Two substances carried in the phloem:

1. Sucrose/sugars (1)

2. Amino acids (1)

Marking guidance: ignore glucose; allow water/plant hormones/named plant hormone

(a)(ii) Explanation why insects feeding from phloem reduce crop yield:

An explanation that makes reference to three of the following:

  1. No/less respiration/no/less energy (1)
  2. No/less protein (1)
  3. No/less growth/new cells (1)
  4. Less fruit production/fewer oranges/smaller fruit (1)

Marking guidance: No credit for less sugar amino acid or glucose; Ignore less crops/less yield

(b)(i) Discussion of effects on scale insect numbers:

An answer that makes reference to five of the following:

  1. Reduce (quickly/steeply) after ladybug introduced (1)
  2. As the ladybugs feed on scale/pests (1)
  3. Scale insects numbers go up and down/fluctuate/oscillate (1)
  4. Some pests required for ladybugs to feed on/scale insects never completely wiped out (1)
  5. Insecticide release causes (rapid) increase in scale insects/pests (1)
  6. As (more) ladybugs killed (than scales/pests) (1)
  7. Fewer scale insects are eaten/less predation (1)
  8. Insecticide becomes less effective/disperses/ladybugs recover/ladybugs develop resistance (1)
  9. Scale insects/pest numbers drop (1)
  10. Ladybugs/biological control more effective than insecticide/kill more pests (1)

(b)(ii) Three advantages of biological control instead of pesticides:

An explanation that makes reference to four of the following points:

  1. Lasts longer/does not need reapplication (1)
  2. Specific/does not affect food chain/other organisms (1)
  3. No residue on crop/not eaten by humans/does not affect humans (1)
  4. No bioaccumulation/biomagnification (1)
  5. Pest does not become resistant (1)

Marking guidance: allow converse; ignore cheaper alone; ignore pollution alone; allow contaminate crops; ignore immune

Question

Limpets are marine animals that attach to rocks on coastal shores.
The diagram shows a food web that contains limpets.

(a) (i) Which are the trophic levels of the starfish in this food web?

A) primary consumer and secondary consumer
B) primary consumer and tertiary consumer
C) secondary consumer and tertiary consumer
D) secondary consumer only

(ii) State what is meant by the term population.
(iii) Explain why only 1% of the energy in the algae is transferred to the starfish.

(b) Some scientists think that food webs on rocky shores are at risk from an increase in greenhouse gases.

The scientists record these two factors during August every year for 17 years:

  • the number of limpets per m² on a rocky shore
  • the mean temperature at the same rocky shore

The graph shows the scientists’ results.

(i) Describe how the scientists could determine the number of limpets on the rocky shore.
(ii) Give one factor the scientists should control when comparing the number of limpets per m² each year.
(iii) The scientists conclude that the combustion of fossil fuels is a risk to the food web. Discuss the scientists’ conclusion.
Use the information in the graph and your own knowledge to support your answer.

Most-appropriate topic codes (Edexcel IGCSE Biology):

4(b): Feeding relationships — parts (a)(i), (a)(iii)
4(a): The organism in the environment — parts (a)(ii), (b)(i), (b)(ii)
4(d): Human influences on the environment — part (b)(iii)
2(f): Respiration — part (a)(iii)
4(c): Cycles within ecosystems — part (b)(iii)
▶️ Answer/Explanation
Solution

(a)(i) C (secondary consumer and tertiary consumer)
A is incorrect as it is not a primary consumer
B is incorrect as it is not a primary consumer
D is incorrect as it is also a tertiary consumer

(a)(ii) • all of (the organisms of) one / a species in an area (at one time)

(a)(iii) An explanation that makes reference to three of the following:
• (energy lost) from movement
• (energy lost) from respiration / heat loss
• (energy lost) as not some not eaten / are inedible
• (energy lost) as some not digested / indigestible / faeces / egestion
• (energy loss) due to death and decay / (energy lost) to other food chains

(b)(i) A description that makes reference to three of the following:
• quadrat / square in gridded area
• place randomly / choose random coordinates
• repeats
• count limpets (in quadrat / square)
• scale up for whole area multiply by area

(b)(ii) • time of day / location / area / position on shore / species of limpet / same day in August

(b)(iii) An answer that makes reference to five of the following:
1. fossil fuel use releases carbon dioxide
2. carbon dioxide is a greenhouse gas / may cause global warming
3. increased temperature reduces limpet number
4. less food / energy for starfish / dogwhelks / gulls
5. dogwhelks / gulls / starfish / secondary consumers would decrease
6. algae would increase / less algae eaten / more food for periwinkles
7. there are anomalies / outliers / not all close to line of best fit
8. other factors may affect limpet population / other greenhouse gases may have effect
9. not done for long enough time so less reliable OR done for long time / 17 years so reliable
10. data only for one month / only August / only one location / only one shore / only looks at one species

Question

Golden rice is an example of a genetically modified plant. Golden rice has been given a gene to make a substance called carotene.
This gene was taken from daffodil plants.

(a)(i) State the term for a genetically modified organism that has been given a gene from a different species. 
(ii) Describe how named enzymes are used to transfer a gene from one species to another species. 

(b) Carotene is converted into vitamin A after being consumed by humans. Non-genetically modified rice does not usually contain carotene.

(i) Vitamin A deficiency is common in some countries. Explain why growing golden rice may benefit people in these countries.
(ii) Suggest why some people may not agree with growing genetically modified crops such as golden rice. 

(c) Chemical pesticides can be used in rice fields to kill insect pests. Scientists investigate the effect that spraying pesticides in a rice field has on three types of organism.

The three types of organism investigated are:

  • insect pests
  • carnivorous beetles (predators of insect pests)
  • lizards (higher trophic level predators)

The scientists count the number of each type of organism in the rice field.
The scientists then spray the field with pesticide.
The number of each type of organism in the field are then counted every three months for a year.
The table shows the scientists’ results:

(i) Comment on the effects on the numbers of different organisms of spraying pesticides in a rice field. 
(ii) State two reasons why using biological control is better for the environment than using chemical pesticide. 

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(c): Genetic modification (genetic engineering) — parts (a)(i), (a)(ii), (b)(i), (b)(ii)
5(a): Food production — parts (b)(i), (c)(ii)
4(b): Feeding relationships — part (c)(i)
4(d): Human influences on the environment — part (c)(i)
▶️ Answer/Explanation
Solution

(a)(i) • transgenic (1)

(a)(ii) A description that makes reference to three of the following:

  • plasmid (is used) (1)
  • restriction enzyme cuts gene / DNA / plasmid / eq (1)
  • ligase joins plasmid and gene / joins DNA / eq (1)
  • forming a recombinant plasmid / forming recombinant DNA / eq (1)

(b)(i) An answer that makes reference to two of the following:

  • less night blindness / fewer eye problems / better vision / eq (1)
  • rice is a common food / part of many diets / common crop / cheap (for consumers) to buy / eq (1)
  • cheap to grow / easy to grow / easy to get large yields / eq (1)
  • less health care needed / less damage to economy / eq (1)

(b)(ii) An answer that makes reference to two of the following:

  • (may grow in wild and) affect food chains / food webs / ecosystems / eq (1)
  • may compete with other species (in wild) / eq (1)
  • may interbreed with wild plants / genes may transfer into wild plants / eq (1)
  • people may think they are a risk to health / eq (1)
  • may be better to give people a more balanced diet / should use natural sources of carotene / eq (1)

(c)(i) An explanation that makes reference to four of the following:

  • all species decrease / eq (1)
  • insects increase after 3 months / from 6 months / eq (1)
  • beetles increase after 9 months / from 12 months / eq (1)
  • lizard numbers do not recover / stay low / do not increase / level off after 9 months / eq (1)
  • pesticide washes away / breaks down / eq (1)
  • pesticide passes along food chain to beetles / to lizards / eq (1)
  • insects become resistant / eq (1)
  • insects increase as there are fewer beetles eating them / beetles decrease as few insects to eat / lizards decrease as few beetles to eat / eq (1)
  • insects have short life cycles / lizards have long life cycle / eq (1)

(c)(ii) An answer that makes reference to two of the following:

  • (biological is) more specific / does not kill other species / eq (1)
  • (biological is) not toxic to humans / no residue left on plants / crops / eq (1)
  • (biological is) no development of resistance / eq (1)
  • (biological) lasts longer / no need to keep reapplying / eq (1)
  • no bioaccumulation / no biomagnification / does not pass along food chains / eq (1)
Question

Coronary heart disease (CHD) is caused by damage to the walls of the coronary artery.

(a) (i) Explain two differences between the structure of the wall of an artery and the wall of a vein.

(ii) The diagram shows a cross-section of a coronary artery from a healthy person and from a person with CHD.

The heart needs to respond to extra demands during exercise.

Explain why, during exercise, the heart of a person with CHD would not respond as efficiently as the heart of a healthy person.

(b) Genetics and smoking are two risk factors for CHD.

The alleles of some genes increase the risk of developing CHD in people. These are known as risk factor alleles.

Scientists compared the relative risk of developing CHD in people with different numbers of these risk factor alleles.

The scientists also compared the risk of developing CHD for non-smokers and smokers.

The graph shows the scientists’ results.

(i) Give one risk factor for CHD, other than genetics and smoking.
(ii) Comment on the relationship between the number of risk factor alleles and smoking on the risk of developing CHD. Use data from the graph to help your answer.

Most-appropriate topic codes (Edexcel IGCSE Biology):

3(h): Transport — part (a)(i), (a)(ii)
3(h): Coronary heart disease — parts (a)(ii), (b)(i), (b)(ii)
2(g): Gas exchange (Human) — part (a)(ii) link to oxygen delivery
4(b): Inheritance — part (b)(ii) link to alleles and risk
5(d): Human influences on the environment — part (b)(i) link to lifestyle factors
▶️ Answer/Explanation
Solution

(a)(i) An explanation that makes reference to four of the following points (marked in pairs):

  • Artery wall has a thick layer of elastic tissue / more elastic (1) as blood pressure is higher / for the wall to recoil / to expand / to smooth blood flow (1).
  • Artery wall has a thick layer of muscle / more muscle (1) to control blood flow (1).
  • Artery has no valves (1) as blood pressure is sufficient to prevent backflow (1).

Accept converse statements for veins. Credit thick wall due to high pressure (two marks) if other points are not given.

(a)(ii) An explanation that makes reference to three of the following points:

  • The artery in CHD has a blockage / is narrower / has a narrower lumen (1).
  • Less blood / less oxygen can flow to the heart muscle (1).
  • This leads to less aerobic respiration / more anaerobic respiration (1).
  • Less energy / less ATP is produced (1).
  • Therefore, the heart is unable to beat faster / contract as effectively during exercise (1).

(b)(i) An answer that makes reference to one of the following:

  • High cholesterol / high-fat diet (1)
  • Lack of exercise (1)
  • Stress (1)
  • High salt diet (1)
  • High BMI / obesity (1)
  • Diabetes (1)
  • Age (1)
  • Sex (1)
  • High blood pressure (1)

Ignore “diet”, “bad diet”, “unbalanced diet” without specific link.

(b)(ii) An answer that makes reference to five of the following points:

  • Smoking increases the risk of CHD for all allele groups (1).
  • Having more risk factor alleles increases the risk of CHD (1).
  • The highest risk is for smokers with a high number of alleles / The lowest risk is for non-smokers with few alleles (1).
  • The biggest increase in risk from smoking is seen in those with few risk alleles / The increase from smoking is lower for the medium or high allele groups (1).
  • Smokers with few alleles have a similar risk to non-smokers with many alleles (1).
  • Credit use of data, e.g., smoking increases risk by approximately 1 for the low allele group (1).
  • Carbon monoxide in cigarette smoke contributes to CHD (1).
  • Smoking causes plaque / cholesterol build-up / blocks the coronary artery (1).
  • Limitation: group size / sample size may be small (1).
  • Limitation: other factors like age, sex, diet, frequency of smoking were not considered (1).

Accept: The increase in risk from smoking is similar for medium and high allele groups.

Question

Transgenic varieties of tomato plants have been produced that can photosynthesise more efficiently than natural varieties.

(a) To make the transgenic tomato plants, a gene is inserted into a vector that is then placed into tomato plant cells. Describe how a recombinant vector containing a gene can be produced.

(b) The graph shows the effect of temperature on the rate of photosynthesis of tomato plants at two different light intensities.

Explain the effect of temperature on the rate of photosynthesis of the tomato plants at high and low light intensity.

(c) The diagram shows a sustainable glasshouse system that is used in the United Kingdom to grow tomato plants throughout the year.

The glasshouse has artificial lighting and heating powered by electricity from a wood-burning power station. Carbon dioxide is pumped from the power station into the glasshouse.

Discuss the advantages of growing tomato plants in this glasshouse system. In your answer include the benefits for farmers and for the environment.

Most-appropriate topic codes (Edexcel IGCSE Biology):

6(c): Genetic modification (genetic engineering) — part (a)
2(e): Nutrition — Flowering plants — Photosynthesis and factors affecting rate — part (b)
6(a): Food production — Crop plants — Glasshouses — part (c)
5(d): Human influences on the environment — Greenhouse gases — part (c)
▶️ Answer/Explanation
Solution

(a) A description that makes reference to the following points:

  • Plasmid (used) as vector (1).
  • Restriction enzyme used to cut out gene / cut plasmid / cut DNA (1).
  • Ligase used to insert gene into plasmid / stick DNA / glue DNA / stick gene with DNA (1).

(b) An explanation that makes reference to three of the following points:

  • Increasing temperature increases the rate of photosynthesis (1).
  • Because particles have more (kinetic) energy / more frequent collisions / there is more enzyme activity (1).
  • (At low light intensity rate levels off) so light is limiting (1).
  • (At high light intensity) carbon dioxide limits rate / not enough carbon dioxide (1).
  • (At high light intensity) rate levels off because temperature is no longer limiting / other factors become limiting (1).

(c) An answer that makes reference to five of the following points:

  1. Light, carbon dioxide and (warm) temperature are supplied / provided (1).
  2. Therefore no factors for photosynthesis are limiting / all factors present for photosynthesis / there is more photosynthesis (1).
  3. So high yield / fast production / (to give high profit) / more tomatoes (1).
  4. No need to buy carbon dioxide / no need to buy electricity / wood is cheaper than fossil fuel / wood cheaper than buying electricity (1).
  5. Tomatoes protected from pests / disease / frost / cold / bad weather (1).
  6. Wood is renewable (energy) (1).
  7. Less use of fossil fuel (1).
  8. Carbon dioxide not released into atmosphere / is reused (1).
  9. Less greenhouse effect / less climate change / less ice cap melting (1).
  10. Less release of sulfur dioxide / less acid rain (1).
Question

(a) Increased release of greenhouse gases are a threat to many ecosystems.

(i) Which of these are greenhouse gases?

  1. CFCs
  2. methane
  3. oxygen
  4. water vapour

A) 1 and 2 only
B) 1, 2 and 3 only
C) 1, 2 and 4 only
D) all of them

(ii) Explain what is meant by the term greenhouse effect.

(b) The graph shows the mass of greenhouse gases emitted from four sources in the United Kingdom from 1990 to 2020.

(i) Calculate the percentage of the total greenhouse gases emitted that came from energy production in 2020.
(ii) Comment on the changes in the four sources of greenhouse gases from 1990 to 2020. Use the information in the graph and your own knowledge to support your answer.

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(d): Human influences on the environment — parts 5(a)(i), 5(a)(ii), 5(b)(i), 5(b)(ii)
5.13: Understand that water vapour, carbon dioxide, nitrous oxide, methane and CFCs are greenhouse gases — part 5(a)(i)
5.14: Understand how human activities contribute to greenhouse gases — part 5(b)(ii)
5.15: Understand how an increase in greenhouse gases results in an enhanced greenhouse effect — part 5(a)(ii)
▶️ Answer/Explanation
Solution

(a)(i) C (1, 2 and 4 only)
A is not correct as water vapour is a greenhouse gas
B is not correct as oxygen is not a greenhouse gas and water vapour is a greenhouse gas
D is not correct as oxygen is not a greenhouse gas
(1 mark)

(a)(ii) An explanation that makes reference to the following:
• IR / long wave radiation is absorbed / traps IR / long wave radiation / traps heat / prevents heat escaping (1)
• (so) increases (global) temperature / earth warms / global warming (1)
(2 marks)

(b)(i)
Calculation:
Readings from the graph (in million tonnes, approximately):
Agriculture ≈ 50, Energy ≈ 110, Business ≈ 118, Transport ≈ 175.
Total = \(50 + 110 + 118 + 175 = 453\).
Percentage from energy = \(\left(\frac{110}{453}\right) \times 100 \approx 24.3\%\) (Allow range: 23.9% – 24.9%).
(3 marks for correct answer with working; 1 mark for correct readings even if unlabelled; 1 mark for dividing 110 by their total if not correct answer)

(b)(ii)
An answer that makes reference to five of the following points (1 mark each):
1. Overall emissions fall / less mass from 1990 to 2020.
2. Energy production had the highest emissions in 1990 and showed the largest fall.
3. The fall in energy emissions is due to a shift to renewable sources (wind, solar) and less use of coal/gas power stations (burning fewer fossil fuels).
4. Transport emissions increased initially, then fell from around 2009/2010.
5. The initial rise in transport was due to more cars/vehicles; the later fall is linked to more electric/hybrid cars and less commuting.
6. Agriculture emissions dropped.
7. This drop may be due to less cattle farming, reducing methane release.
8. Business emissions changed little / dropped slightly.
(5 marks total)

Question

This food web comes from a woodland ecosystem.

(a) (i) Which organism is the producer?

A) caterpillar
B) earthworm
C) oak tree
D) stoat

(ii) Which organism is a secondary consumer?

A) caterpillar
B) earthworm
C) fox
D) ladybird

(iii) Which organism is both a secondary and a tertiary consumer?

A) blackbird
B) earthworm
C) fox
D) stoat

(b) A farmer is using a pesticide in fields next to the woodland. The pesticide is reducing the numbers of greenfly and caterpillars in the woodland.

(i) Explain what effect this may have on the blackbirds in the woodland.
(ii) Describe a different method the farmer could use to reduce the number of greenfly on his crops.

Most-appropriate topic codes (Edexcel IGCSE Biology):

4(b): Feeding relationships — parts (a)(i), (a)(ii), (a)(iii)
4(d): Human influences on the environment — parts (b)(i), (b)(ii)
5(a): Food production — part (b)(ii)
▶️ Answer/Explanation
Solution

(a)(i) C (oak tree)
The oak tree is the producer because it can produce its own food via photosynthesis. It forms the base of the food web.
A is not correct because a caterpillar is a consumer (primary).
B is not correct because an earthworm is a decomposer/consumer.
D is not correct because a stoat is a tertiary consumer.

(a)(ii) D (ladybird)
A secondary consumer is an organism that feeds on primary consumers. In this web, the ladybird eats greenfly (a primary consumer).
A is not correct because a caterpillar is a primary consumer (eats producer).
B is not correct because an earthworm is a decomposer/primary consumer.
C is not correct because a fox can be a secondary or tertiary consumer, but is not exclusively a secondary consumer in this context.

(a)(iii) A (blackbird)
The blackbird is both a secondary and tertiary consumer because its diet includes both primary consumers (like caterpillars, snails) and secondary consumers (like ladybirds).
B is not correct because an earthworm is not a secondary/tertiary consumer.
C is not correct because a fox is primarily a tertiary consumer.
D is not correct because a stoat is a tertiary consumer.

(b)(i)
An explanation that makes reference to three of the following points:
• The number of blackbirds may decrease / population falls / some may die or migrate. (1 mark)
• There is less food available for blackbirds, as they eat caterpillars and ladybirds. (1 mark)
• Ladybirds also have less food (greenfly), reducing their numbers, which further reduces the blackbird’s food source. (1 mark)
• Blackbirds may switch to eating more earthworms, but this may not fully compensate. (1 mark)
• Blackbirds could consume pesticide directly or via bioaccumulation, which may poison them. (1 mark)
(Maximum 3 marks)

(b)(ii)
A description that makes reference to the following:
• Use biological control. (1 mark)
• Introduce a natural predator of greenfly, such as more ladybirds or lacewings. (1 mark)
• The predator will eat / consume / prey on the greenfly, reducing their population. (1 mark)
This method avoids the harmful side-effects of chemical pesticides on non-target species and the environment.

Question

Variegated leaves have areas that are green and areas that are white.

A student uses this method to investigate the effect of light on photosynthesis in a variegated leaf.

  • place a plant in the dark for 24 hours
  • wrap a strip of black paper across a leaf
  • shine light on the plant for 24 hours
  • remove the black paper
  • use iodine solution to test the leaf for starch

The diagram shows the apparatus the student uses.

(a) Complete the balanced chemical symbol equation for photosynthesis.

__________ + 6 H2O → __________ + __________

(b) (i) State why the plant was placed in the dark for 24 hours.

(ii) Diagram 1 shows the position of the black paper on the leaf.

Complete diagram 2 to show where the variegated leaf would appear black after testing with iodine solution.

(c) The student observes that the leaves on different ivy plants seem to be different sizes depending on the amount of sunlight the plants receive.

Design an investigation to test whether the amount of sunlight received by ivy plants affects the size of their leaves.

Include experimental details in your answer and write in full sentences.

Most-appropriate topic codes (Edexcel IGCSE Biology):

2(e): Nutrition (Flowering plants) — part (a), (b)(i), (b)(ii)
2(e): Photosynthesis — part (a), (b)
2(e): Practical investigation of photosynthesis — part (b)(ii)
4(a): The organism in the environment — part (c)
4(e): Human influences on the environment — part (c)
Appendix 6: Suggested practical investigations — part (c)
▶️ Answer/Explanation
Solution

(a) 6CO2 + 6H2O → C6H12O6 + 6O2

Explanation: The balanced equation for photosynthesis shows that six molecules of carbon dioxide and six molecules of water are used as reactants. In the presence of light energy and chlorophyll, these are converted into one molecule of glucose (a sugar) and six molecules of oxygen gas, which is released as a byproduct.

(b)(i) To destarch the leaves / remove starch / so no starch is present (in leaves) at the start of the experiment.

Explanation: Placing the plant in darkness for 24 hours ensures that any starch already present in the leaves is used up by the plant for respiration or converted to other forms for transport and storage. This is crucial because it means that any starch detected after the experiment must have been produced during the 24-hour light period, allowing the student to accurately investigate the effect of light on photosynthesis.

(b)(ii)

Explanation: Iodine solution turns blue-black in the presence of starch. Starch is only produced in areas of the leaf where photosynthesis occurs, which requires both chlorophyll (found only in the green parts) and light. Therefore, the green areas that were exposed to light will test positive for starch and appear black. The white areas lack chlorophyll and cannot photosynthesize, so they will not produce starch and will not turn black. The green area that was covered by the black paper was deprived of light and also could not photosynthesize, so it will not produce starch and will not turn black.

(c) A designed investigation that includes references to six of the following points:

  • Control Variable: Plant ivy in areas with different exposures to light (e.g., a shaded area and an unshaded area).
  • Organism: Use the same species/type of ivy. Use plants of the same age or starting size to ensure a fair test.
  • Repeats: Repeat the investigation with multiple leaves and multiple plants in each light condition to improve reliability.
  • Measurement 1: Measure the size of the leaves. This could be done by measuring their length, width, or calculating their surface area using a ruler.
  • Measurement 2: Grow the ivy plants for a specified, identical period of time (e.g., one month) before taking measurements.
  • Standardization 1: Control other factors that could affect leaf size, such as temperature, humidity, and carbon dioxide concentration.
  • Standardization 2: Ensure the plants receive the same amounts of water, minerals, and the same type of soil to ensure any difference in leaf size is due to light intensity alone.

Example Investigation Description:
To investigate this, I would obtain several young ivy plants of the same species and similar size. I would place half of them in a very sunny location and the other half in a heavily shaded location. All plants would be planted in the same type of soil and would be given the same amount of water each day. I would leave the plants to grow for two months. After this time, I would randomly select 10 leaves from different parts of several plants in each group. I would measure the length and width of each leaf and calculate the average leaf size for the sunny group and the average leaf size for the shaded group. By comparing these averages, I could determine if the amount of sunlight affects leaf size. Using multiple plants and multiple leaves ensures the results are reliable.

Question

The diagram shows the carbon cycle.

(a) (i) Which letter in the diagram represents respiration?

  • A. T
  • B. X
  • C. Y
  • D. Z

(a) (ii) Give the name of the process labelled W.

(b) Carbon dioxide, methane, and nitrous oxide are three greenhouse gases. The table shows a comparison of these greenhouse gases. The Global Warming Potential (GWP) is the ratio of the heat absorbed by a greenhouse gas in the atmosphere relative to the heat absorbed by the same mass of carbon dioxide gas.

(b) (i) Name one other greenhouse gas.

(b) (ii) Evaluate the information in the table to identify which of these gases is likely to contribute most to global warming.

Most-appropriate topic codes (Edexcel IGCSE Biology):

4(c): Cycles within ecosystems — parts (a)(i), (a)(ii)
4(d): Human influences on the environment — parts (b)(i), (b)(ii)
▶️ Answer/Explanation
Solution

(a)(i) C (Y)

Explanation: Respiration is the process where living organisms break down organic compounds to release energy, producing carbon dioxide (CO₂) as a waste product. The arrow labelled Y shows carbon moving from organic compounds in animals back to the atmosphere as CO₂, which represents this process.

(a)(ii) Photosynthesis

Explanation: Process W shows carbon dioxide being taken from the atmosphere and converted into organic compounds in plants. This is the fundamental process of photosynthesis, where plants use light energy to fix carbon into glucose and other molecules.

(b)(i) Water vapour / Chlorofluorocarbons (CFCs)

Explanation: Water vapour is the most abundant greenhouse gas in the atmosphere. Human-made gases like Chlorofluorocarbons (CFCs), used in refrigeration and aerosols, are also potent greenhouse gases, though their use is now restricted.

(b)(ii) Carbon dioxide is likely to contribute the most to global warming.

Explanation: Although carbon dioxide (CO₂) has the lowest Global Warming Potential (GWP=1), it is emitted in vastly larger quantities (77% of emissions) compared to methane (16%) and nitrous oxide (0.77%). Furthermore, its atmospheric lifetime is extremely long (1000 years), meaning its warming effect is persistent and cumulative. The combination of its massive volume and long lifespan means the total heat trapped by CO₂ outweighs the significant but shorter-term impact of the more potent but less abundant gases.

Question

The diagram shows the structure of a human eye.

(a) (i) Give the name of structure Z.

(ii) Describe how structures X and Y control the shape of a lens when focusing on a near object.

(b) A cataract occurs when the lens becomes cloudy.
Severe cataracts are the main cause of blindness around the world.

(i) Explain why people with cataracts are unable to see clearly.

(ii) Exposure to ultraviolet light is thought to be a risk factor for the development of cataracts.
The table shows the results of a 25-year investigation into the effect of different mean hours of sunlight on agricultural workers in one south Asian country.

Comment on the results of the investigation.

Most-appropriate topic codes (Edexcel IGCSE Biology):

2(j): Co-ordination and response — parts (a)(i), (a)(ii), (b)(i)
4(d): Human influences on the environment — part (b)(ii) context
▶️ Answer/Explanation
Solution

(a) (i) iris

Explanation: Structure Z is the iris. The iris is the colored part of the eye that controls the size of the pupil, thereby regulating the amount of light that enters the eye.

(a) (ii) A description that makes reference to the following three points:

  • X / ciliary muscle, contracts
  • Y / suspensory ligaments go slack / loosen
  • lens becomes thicker / more spherical / more convex

Detailed Explanation: When focusing on a near object, the ciliary muscles (X) contract. This contraction reduces the tension on the suspensory ligaments (Y), causing them to become slack or loosen. Because these ligaments are no longer pulling the lens taut, the natural elasticity of the lens causes it to become thicker, more spherical, and more convex. This change in shape increases the refractive power of the lens, allowing it to bend light rays more sharply and focus the image of the close object correctly onto the retina.

(b) (i) An explanation that makes reference to two of the following:

  • less light can pass through / refraction affected
  • to retina / fovea / rods / cones / photoreceptors
  • so fewer impulses (to brain)

Detailed Explanation: A cataract causes the normally clear lens to become cloudy or opaque. This cloudiness scatters and blocks light, preventing a clear, sharp image from being formed. Less light can pass through the lens to reach the light-sensitive cells (rods and cones) in the retina at the back of the eye. Furthermore, the cloudiness disrupts the precise refraction (bending) of light rays that is necessary for focusing. As a result, the light rays are not properly focused onto the retina, leading to a blurred or dim image. This faulty image results in fewer or confused nerve impulses being sent to the brain via the optic nerve, causing unclear vision.

(b) (ii) An answer that makes reference to four of the following points based on the data:

  • numbers (of cataracts) increase as exposure to sunlight increases (e.g., 2 at 7 hrs vs 35 at 12 hrs).
  • group sizes are different (e.g., 100 at 7 hrs vs 540 at 12 hrs), which must be considered when interpreting raw numbers.
  • the proportion/percentage of cases fluctuates/does not change much between 7 and 10 hours (approx 2%, 1.9%, 2.0%, 1.6%).
  • the proportion/percentage rises more noticeably after 10/11 hours (3.2% at 11 hrs, 6.5% at 12 hrs).
  • the large number of people in the study overall makes it somewhat reliable, OR it is less reliable as data is only from one country/climate.
  • other factors like age, genetics, diet, or protective gear (sunglasses, hats) could affect the results and are not accounted for.

Detailed Comment: The data suggests a general trend where the number of people developing cataracts increases with higher mean daily hours of sunlight exposure, from 2 cases at 7 hours to 35 cases at 12 hours. However, because the group sizes vary significantly (e.g., 100 people vs 540 people), it’s more accurate to look at the percentage of each group affected. Calculating these percentages (7h: 2%, 8h: ~1.9%, 9h: 2%, 10h: ~1.6%, 11h: ~3.2%, 12h: ~6.5%) reveals that the risk appears relatively stable and low (around 2%) for exposures up to 10 hours. A more substantial increase in risk is observed beyond 10 hours, jumping to 3.2% at 11 hours and 6.5% at 12 hours, indicating a potential threshold effect. The 25-year duration and large total sample size add weight to the findings. However, the study is limited to agricultural workers in one South Asian country, so the results may not be directly applicable to populations in different climates, with different genetics, or with different sun protection behaviors. Other unmeasured factors, such as the exact intensity of UV exposure, age of the workers, dietary intake of antioxidants, and use of protective eyewear, could also influence cataract development and are not considered in this data table.

Question

The photograph shows a red fire ant.

Fire ants are pests that damage crops.

Phorid flies can be used as a biological control of fire ants.

Scientists use this method to investigate the use of pesticides and biological control on populations of fire ants that live on plants in glasshouses.

  • in one glasshouse, keep plants with no treatment
  • in a second glasshouse, treat plants with pesticide
  • in a third glasshouse, treat plants with pesticide and then immediately introduce phorid flies
  • count the number of fire ants in each glasshouse at intervals for 24 months

The table shows the scientists’ results.

(a) Give a reason why the scientists include results from a glasshouse with no treatment in their investigation.

(b) Draw a line graph to show the changes in the number of fire ants with pesticide only and with both pesticide and phorid flies for the 24 months. Join your points with straight lines.

(c) Describe the effect of using pesticide only on the number of fire ants for the 24 months.

(d) Discuss the effects of using pesticide only and of using both pesticide and phorid flies on the number of fire ants. Use the data and your own biological knowledge in your answer.

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(a): Food production — Crop plants — parts (a), (c), (d)
4(d): Human influences on the environment — parts (c), (d)
3(b): Inheritance — part (d)
▶️ Answer/Explanation
Solution

(a) It is a control (experiment) / to compare the results / check that change is due to the treatments.

Explanation: The glasshouse with no treatment serves as a control. This is a fundamental part of a scientific investigation. The control provides a baseline for comparison. It allows the scientists to see what happens to the fire ant population when no treatment is applied. By comparing the results from the treated glasshouses to this control, they can be confident that any changes observed (like a decrease in ant numbers) are actually due to the pesticide or the combination of pesticide and flies, and not just due to other factors that might affect the population over time.

(b)

Graph Description: A line graph should be drawn with the following features to score full marks:

  • Axes: The x-axis should be labelled “Time after treatment (months)” and the y-axis should be labelled “Number of fire ants”. Both axes must have a linear scale that uses at least half of the grid provided.
  • Data Points: Points should be plotted accurately for both data sets (Pesticide only and Pesticide + phorid flies) at the correct time intervals (0, 6, 12, 18, 24 months).
  • Lines: The plotted points for each data set should be joined with straight lines.
  • Key: The graph must include a key or the lines must be clearly labelled to identify which line represents “Pesticide only” and which represents “Pesticide and phorid flies”.

Explanation: The graph for “Pesticide only” would start at 500 ants at 0 months, drop sharply to 50 at 6 months, rise slightly to 75 at 12 months, continue rising to 125 at 18 months, and then rise sharply again to 400 at 24 months. The graph for “Pesticide and phorid flies” would also start at 500, drop to 50 at 6 months, but then drop further to 25 at 12 months and remain steady at 25 for both 18 and 24 months. This visual representation clearly shows the initial effectiveness of both treatments and the crucial long-term difference the biological control agent makes.

(c) The number of fire ants decreases (sharply at first) and then increases (again).

Explanation: Looking at the data for “Pesticide only”, we see a very effective initial result. The number of ants plummets from 500 to just 50 within the first 6 months. This shows the pesticide is highly effective at killing the ants upon application. However, after this initial success, the population begins to recover. It increases to 75 at 12 months, 125 at 18 months, and is nearly back to its original size at 400 by 24 months. This indicates that the effect of the pesticide is not lasting.

(d) Discussion points should include:

  • Both treatments (pesticide alone and pesticide + flies) are initially very effective, drastically reducing the ant population within 6 months.
  • The population recovers over time when only pesticide is used, reaching 400 ants by 24 months. This suggests the pesticide’s effect is temporary; it may wear off, wash away, or the ants may develop resistance to it through natural selection. Resistant ants survive and reproduce, passing on the resistance allele to their offspring.
  • In contrast, when phorid flies (a biological control agent) are introduced alongside the pesticide, the ant population is not only reduced but is also maintained at a very low level (25 ants) from 12 months onwards.
  • The phorid flies provide a sustainable, long-term control method. Unlike the chemical pesticide, the flies can reproduce and continue to prey on the fire ants, keeping their population in check. The population stabilizes at a low level where the death rate (due to predation by flies) equals the birth rate.
  • This shows that integrating biological control (phorid flies) with chemical control (pesticide) is a much more effective long-term strategy for managing fire ant populations than using pesticides alone. The pesticide provides a quick “knock-down” of the population, and the biological control agent prevents it from recovering.

Explanation: The data clearly shows that while pesticides offer a powerful short-term solution, they often fail as a long-term strategy on their own due to factors like resistance development. Biological control, though it may work more slowly, acts as a persistent regulating force. The combination of both methods leverages the immediate impact of the pesticide with the sustained, self-replicating pressure of the biological control agent, resulting in a much more effective and durable pest management outcome. This is a key principle in integrated pest management (IPM).

Question

Large quantities of food are wasted every year. Waste food needs to be disposed of using methods that do not harm the environment.

The table shows the mass of each gas released into the air from three different methods of waste disposal.

(a) Calculate how much carbon dioxide would be released from 125 kg of waste food when using an anaerobic digester.

Give your answer to two significant figures.

(b) Some scientists have claimed that anaerobic digesters are the most environmentally friendly method of waste disposal.

Evaluate this claim using data from the table and your own knowledge.

Most-appropriate topic codes (Edexcel IGCSE Biology):

2(f): Respiration — part (a), anaerobic digestion context
4(d): Human influences on the environment — part (b), pollution and environmental impact
5(a): Use of biological resources – Food production — part (b), waste management and resource use
Appendix 4: Mathematical skills — part (a), calculations and significant figures
▶️ Answer/Explanation
Solution

(a) 4.6 kg

Explanation:

The table shows that 37 kg of carbon dioxide is released from 1000 kg of waste food using an anaerobic digester. We need to find out how much is released from 125 kg.

First, find the amount of CO₂ released per kg of waste:

\[ \frac{37\, \text{kg}}{1000\, \text{kg}} = 0.037\, \text{kg of CO}_2 \text{ per kg of waste} \]

Now, multiply this by the mass of waste we are interested in (125 kg):

\[ 0.037\, \text{kg/kg} \times 125\, \text{kg} = 4.625\, \text{kg} \]

Finally, round this answer to two significant figures:

\[ 4.625\, \text{kg} \approx 4.6\, \text{kg} \]

So, the mass of carbon dioxide released is 4.6 kg.

(b)

Evaluation:

Arguments in favor (Agreement):

  • The data shows that anaerobic digesters release significantly less carbon dioxide (37 kg) per 1000 kg of waste compared to burning (680 kg) and burying in landfill (220 kg). Carbon dioxide is a major greenhouse gas contributing to global warming.
  • Anaerobic digesters also release less methane (3.05 kg) than landfills (14.70 kg). Methane is a much more potent greenhouse gas than CO₂ in the short term, so reducing its release is crucial for mitigating climate change.
  • The amount of carbon monoxide (0.012 kg) released by digesters is much lower than from landfills (0.680 kg) and slightly lower than from burning (0.059 kg). Carbon monoxide is a toxic gas that can bind to haemoglobin in blood, reducing oxygen transport.
  • By producing less of these gases, anaerobic digesters contribute less to the greenhouse effect, global warming, and associated problems like ice cap melting, habitat loss, extreme weather, and flooding.
  • Furthermore, the process of anaerobic digestion produces biogas (a mixture of methane and carbon dioxide), which can be captured and used as a renewable energy source, adding to its environmental benefits.

Arguments against (Disagreement/Limitations):

  • However, the table shows that anaerobic digesters release more sulfur dioxide (0.23 kg) than the other two methods (Landfill: 0.14 kg, Burning: 0.08 kg).
  • Sulfur dioxide is a primary cause of acid rain. Acid rain can lead to deforestation, acidification of lakes and rivers (killing fish and other aquatic life), and damage to buildings and statues.
  • Therefore, while anaerobic digesters are better in terms of greenhouse gas emissions, their higher sulfur dioxide output is a significant environmental drawback that must be considered and potentially mitigated.

Conclusion:

Based on the data provided, anaerobic digesters appear to be the most environmentally friendly method specifically regarding greenhouse gas emissions (CO₂, CH₄, CO), which are a major global concern. The claim is strongly supported by this data. However, the higher release of sulfur dioxide, which causes regional environmental problems like acid rain, means they are not unequivocally the best in every aspect. A full evaluation would require weighing the global impact of climate change against the more localized impact of acid rain. Technologies to capture or reduce sulfur dioxide emissions from digesters could make them even more environmentally friendly.

Question

Alkaptonuria is an inherited condition caused by the presence of recessive alleles.

(a) State what is meant by a recessive allele.

(b) Alkaptonuria is first diagnosed in children when it is noticed that they produce very dark urine that turns black when exposed to air.

A woman and a man do not have alkaptonuria. They have a child who has the condition.

The woman and the man are expecting a second child.

(i) Draw a genetic diagram to show the genotypes of the woman and the man, the gametes they produce and the possible phenotypes and genotypes of the second child.

(ii) Calculate the probability that the second child is male and does not have the condition.

(c) Alkaptonuria is caused by the body being unable to break down the amino acids tyrosine and phenylalanine.

This leads to a build-up of a toxin that causes damage to joints and tendons and can also lead to heart valve damage in later life.

A new drug treatment is being tested that can slow the damage to the joints and tendons.

Scientists selected 40 adults who all had alkaptonuria. They placed each patient into one of two groups. One group was given the drug treatment and the other group acted as a control.

The scientists then compared the symptoms of the patients in each group after three years.

(i) Describe what is meant by the control group.

(ii) The table compares the control group with the drug treatment group.

It shows the numbers starting and completing the trial and those showing harmful effects.

It also compares improvements in two symptoms of alkaptonuria.

Evaluate whether the new drug should be recommended as an effective treatment for alkaptonuria.

(d) Other scientists have suggested that eating fewer proteins that contain tyrosine and phenylalanine would reduce the symptoms of alkaptonuria.

Suggest why eating fewer of these proteins may be difficult.

Most-appropriate topic codes (Edexcel IGCSE Biology):

3(b): Inheritance — parts (a), (b)(i), (b)(ii)
2(c): Biological molecules (proteins & amino acids) — part (c) introduction, (d)
4(d): Human influences on the environment (evaluation of scientific data) — part (c)(ii)
Appendix 5: Command word taxonomy — parts (a) “State”, (c)(i) “Describe”, (c)(ii) “Evaluate”
Question

The diagram shows part of a food web from an ecosystem in a region of North America.

(a) (i) Which of these organisms in the food web is a primary consumer?

  • A. beaver
  • B. coyote
  • C. grass
  • D. wolf

(ii) State what is meant by the term ecosystem.

(b) Wolves were hunted in this region of North America until they became extinct in 1926.

The extinction of wolves damaged the ecosystem in these ways:

  • the population of mice, hawks and beavers decreased
  • the population of producer species decreased

Beavers are important in this ecosystem because they cut down old trees and create shelters that other organisms nest in.

Discuss why the extinction of wolves damaged the ecosystem.

(c) In 1995, 14 wolves were reintroduced to this region.

The diagram shows the change in wolf population from 1996 to 2016.

(i) Calculate the percentage change in the wolf population between 1996 and 2004.

(ii) Suggest why the wolf population changed between 2004 and 2012.

(iii) The reintroduction of wolves caused changes in the populations of some plant species.

Describe how the population size of a plant species in the region could be determined.

Most-appropriate topic codes (Edexcel IGCSE Biology):

4(a): The organism in the environment — parts (a)(ii), (b), (c)(iii)
4(b): Feeding relationships — part (a)(i)
4(d): Human influences on the environment — parts (b), (c)(ii)
Appendix 4: Mathematical skills — part (c)(i)
▶️ Answer/Explanation
Solution

(a)(i) A (beaver)

Explanation: Primary consumers are organisms that eat producers (plants). In this food web, grass and aspen trees are producers. The beaver eats these plants, making it a primary consumer. Coyotes and wolves are secondary or tertiary consumers as they eat other animals.

(a)(ii) An ecosystem refers to a community of living organisms (biotic factors) interacting with each other and their physical environment (abiotic factors).

Explanation: An ecosystem isn’t just about the organisms living in an area; it also includes all the non-living components like soil, water, air, and sunlight that they interact with. These interactions create a functional unit where energy flows and nutrients cycle.

(b) The extinction of wolves damaged the ecosystem because it disrupted the natural balance of predator-prey relationships.

Detailed Discussion: Wolves are apex predators that play a crucial role in regulating prey populations. When wolves were removed:

  • The elk population likely increased dramatically since their main predator was gone.
  • With more elk, there was increased grazing pressure on plants like aspen trees and grass.
  • This overgrazing reduced plant populations, which in turn affected other species that depend on these plants for food and habitat.
  • Beaver populations decreased because their food sources (trees) were reduced by elk overgrazing.
  • With fewer beavers, there were fewer dams and wetland habitats that many species depend on.
  • Mouse populations decreased due to reduced plant food sources and possibly increased predation from coyotes (who may have switched prey when wolves disappeared).
  • Hawk populations decreased because their prey (mice) became less abundant.

This demonstrates how the removal of a keystone species like the wolf can cause cascading effects throughout an entire ecosystem.

(c)(i) Percentage change = 260%

Calculation:
Population in 1996 ≈ 50 wolves
Population in 2004 ≈ 180 wolves
Change = 180 – 50 = 130 wolves
Percentage change = (130 ÷ 50) × 100 = 260%

This shows the wolf population increased by 260% over this 8-year period following reintroduction.

(c)(ii) The wolf population likely changed between 2004 and 2012 due to factors like limited food availability, disease, competition, or habitat constraints.

Explanation: After the initial rapid growth, the population likely reached carrying capacity – the maximum number of wolves the ecosystem can support. Factors that may have caused fluctuations include:

  • Prey populations (elk, etc.) decreasing due to predation pressure
  • Disease outbreaks that spread through the wolf population
  • Increased competition for territory and resources as the population grew
  • Human activities like hunting or habitat disturbance

These factors typically cause predator populations to stabilize or fluctuate after an initial colonization period.

(c)(iii) The population size of a plant species could be determined using quadrat sampling.

Method Description:

  1. Place quadrats (square frames of known area) randomly throughout the study area
  2. Count the number of individuals of the target plant species within each quadrat
  3. Calculate the average number of plants per quadrat
  4. Multiply this average by the total number of quadrats that would fit in the entire study area to estimate the total population
  5. Repeat the process multiple times to improve accuracy

This method provides a reliable estimate of plant population size without having to count every individual plant across large areas.

Question

Scientists have developed genetically modified (GM) crops in order to increase food production by increasing crop yields.

(a) (i) Some GM crops are described as transgenic.
Explain what is meant by the term transgenic.

(ii) Give the role of two named enzymes in the production of GM organisms.

(b) Some GM crops that are available to farmers are resistant to herbicides (weedkillers).
Other GM crops are resistant to diseases caused by viruses and to damage by insects.
Some people are for the use of GM crops because they may be beneficial to ecosystems.
Some people are against the use of GM crops because they could harm ecosystems.
Discuss these opinions for and against the use of GM crops.

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(c): Genetic modification (genetic engineering) — parts (a)(i), (a)(ii)
5(a): Food production — part (b)
4(d): Human influences on the environment — part (b)
▶️ Answer/Explanation
Solution

(a) (i) Transgenic refers to an organism that contains genetic material from a different species that has been artificially introduced.

Explanation: When scientists create transgenic crops, they isolate a specific gene from one species (like a bacterium) that has a desirable trait, such as pest resistance. This gene is then inserted into the DNA of the crop plant. The resulting plant is called transgenic because its genome now includes functional DNA from another, often very different, organism.

(a) (ii)

1. Restriction enzyme (or endonuclease): Cuts DNA at specific sequences.

2. Ligase: Joins pieces of DNA together.

Explanation: The process of creating a GM organism relies heavily on specific enzymes. First, a restriction enzyme is used like molecular scissors. It recognizes a specific, short sequence of DNA and cuts the DNA strand at that point. This is used to cut out the desired gene from the source organism’s DNA and to cut open the plasmid (a small, circular piece of DNA from a bacterium) that will act as a vector. Once the gene is isolated and the plasmid is prepared, the enzyme ligase acts like molecular glue. It seals the ends of the desired gene into the plasmid vector, creating a recombinant DNA molecule. This recombinant plasmid can then be inserted into the host organism’s cells.

(b)

Arguments for GM crops being beneficial to ecosystems:

  • Herbicide-resistant crops allow farmers to spray herbicides that kill weeds without harming the crop itself. This can lead to reduced use of insecticides if the weeds, which often harbour pests, are better controlled.
  • Crops engineered to be resistant to insects (e.g., by producing their own pesticide, like Bt corn) mean farmers don’t need to spray broad-spectrum chemical insecticides. This reduces harm to non-target species, such as pollinators like bees, and prevents the bioaccumulation of these chemicals in the environment.
  • Virus-resistant crops can prevent the spread of plant viruses to other, non-GM crops or wild plant species nearby.

Arguments against GM crops due to potential harm to ecosystems:

  • There is a concern that the introduced genes could transfer to wild relatives through cross-pollination. For example, a gene for herbicide resistance could spread to a weed species, creating “superweeds” that are very difficult to control.
  • If a GM crop is very vigorous or resistant, it could potentially outcompete native plant species, reducing biodiversity and disrupting local food chains.
  • While insect-resistant crops reduce spraying, the constant production of insecticide by the plant itself could, in theory, accelerate the evolution of resistance in pest populations or harm beneficial insect populations.
  • The system of herbicide-resistant crops often encourages increased use of specific herbicides, which could have negative effects on soil health and nearby waterways.

Explanation: The discussion around GM crops and ecosystems is complex and involves weighing potential benefits against risks. Proponents argue that GM technology can lead to more targeted pest control, reducing the overall chemical load on the environment. Opponents worry about unintended and irreversible consequences, such as gene flow to wild species or harm to beneficial organisms, which could upset the delicate balance of an ecosystem. A thorough discussion considers both the direct and indirect, long-term ecological impacts.

Question

The diagram shows an insect transferring pollen grains from flower P to flower Q.

(a) Which structure in flowers contains pollen grains?

  • A. anther
  • B. ovary
  • C. petal
  • D. sepal

(b) (i) Pollen grains are deposited on the stigma and grow tubes down the style. Suggest how style tissue helps the tube to grow.

(ii) The graph shows the change in the length of a pollen tube over a 180 minute period.

Calculate the fastest rate of pollen tube growth in mm per minute.

(c) A farmer grows apple trees. The flowers on the apple trees must be pollinated by insects to produce an apple crop. The farmer is concerned that the use of pesticides may affect the yield of apples. Design an investigation to find out if pesticides reduce the yield of apples. Include experimental details in your answer and write in full sentences.

Most-appropriate topic codes (Edexcel IGCSE Biology):

3(a): Reproduction — flowering plants — part (a)
3(a): Reproduction — pollen tube growth and fertilisation — part (b)(i)
Appendix 4: Mathematical skills — calculations and graph interpretation — part (b)(ii)
5(a): Food production — effects of pesticides and crop yield — part (c)
4(d): Human influences on the environment — impact of pesticides on ecosystems — part (c)
Appendix 6: Suggested practical investigations — designing investigations — part (c)
▶️ Answer/Explanation
Solution

(a) A anther

Explanation: The anther is the male reproductive part of the flower where pollen grains are produced and stored. The ovary contains ovules, petals attract pollinators, and sepals protect the flower bud, but none of these structures contain pollen grains.

(b)(i)

Explanation: The style tissue provides essential nutrients and support for the growing pollen tube. It supplies glucose or sucrose through its tissues, which the pollen tube uses for respiration to produce ATP and energy needed for growth. Additionally, the style may provide amino acids for protein synthesis and water to maintain turgor pressure and enable cell elongation as the tube grows toward the ovary.

(b)(ii) 0.055 mm per minute

Explanation: To calculate the fastest rate of growth, we need to find the steepest slope on the graph. Looking at the time intervals:

From 0-60 minutes: (1.4 – 0)/60 = 0.023 mm/min

From 60-120 minutes: (4.7 – 1.4)/60 = 3.3/60 = 0.055 mm/min

From 120-180 minutes: (5.8 – 4.7)/60 = 1.1/60 = 0.018 mm/min

The fastest growth occurs between 60-120 minutes with a rate of 0.055 mm per minute.

(c)

Explanation: To design a proper investigation:

First, I would select two groups of apple trees of the same variety, age, and size to ensure fair comparison. One group would be treated with pesticide (experimental group) while the other would not receive any pesticide treatment (control group).

I would use multiple trees in each group (at least 5-10) to ensure reliable results and repeat the experiment over multiple growing seasons. All trees should be grown in the same soil type with identical fertilization, watering schedules, and exposure to sunlight and temperature conditions.

The independent variable would be the application of pesticide, while the dependent variables would be the yield measurements – specifically the number of apples produced and the total mass of apples harvested from each tree.

The investigation should run for the entire flowering and fruiting period. I would carefully count and weigh the apples from each tree at harvest time and compare the average yield between the pesticide-treated and untreated groups using statistical analysis to determine if there’s a significant difference.

This experimental design controls for other variables that might affect yield while specifically testing the effect of pesticides on apple production through insect pollination.

Question

(a) The table gives some examples of biological processes. Complete the table by giving the name of each process. The first one has been done for you.

(b) Zinc is poisonous to many plants and can affect natural selection. A scientist investigates the ability of one grass species to survive at different distances from a zinc mine. The scientist uses a sampling method to measure the percentage cover of this grass species at different distances from the zinc mine. The graph shows the scientist’s results.

(i) The zinc concentration in soil is higher near the zinc mine than it is further from the zinc mine.

Explain how natural selection could be responsible for the results shown in the graph between 0 and 100 metres.

(ii) Describe a method the scientist could use to compare the population size of the grass species at 50 metres and 100 metres from the mine.

Most-appropriate topic codes (Edexcel IGCSE Biology):

4(a): The organism in the environment — part (b)(ii)
4(b): Feeding relationships — part (a) eutrophication
4(d): Human influences on the environment — part (a) eutrophication
3(a): Reproduction — part (a) insect pollination
2(d): Movement of substances into and out of cells — part (a) active transport
3(b): Inheritance — part (b)(i) natural selection, variation
3.38: Darwin’s theory of evolution by natural selection — part (b)(i)
3.33: Variation within a species — part (b)(i)
▶️ Answer/Explanation
Solution

(a)

Explanation:

Eutrophication is the process where water bodies become enriched with nutrients (like fertilisers), leading to excessive growth of algae and other aquatic plants. This depletes oxygen in the water, harming other aquatic life.

Insect pollination occurs when insects transfer pollen from the anther of one flower to the stigma of another, facilitating fertilization in plants.

Active transport is the movement of ions or molecules across a cell membrane from a region of lower concentration to a region of higher concentration, requiring energy in the form of ATP.

(b)(i)

Explanation: Natural selection could explain the pattern seen in the graph between 0-100 meters from the mine through the following mechanism:

Initially, the high zinc concentration near the mine would be toxic to most individual grass plants. However, within the population, there might be genetic variation due to random mutations. A few individual grass plants might possess alleles that make them resistant to zinc toxicity. These resistant individuals would be more likely to survive and reproduce in the zinc-contaminated soil near the mine. They would pass these advantageous resistant alleles to their offspring. Over generations, the proportion of zinc-resistant grass plants in the population near the mine would increase. This results in a population that is better adapted to the high zinc levels, allowing the grass species to have a higher percentage cover closer to the mine (0-100m) than might be initially expected, as seen in the graph. The process involves variation, selection pressure (zinc), survival of the fittest (resistant plants), and inheritance of the resistant trait.

(b)(ii)

Explanation: To compare the population size of the grass species at 50m and 100m from the mine, the scientist could use a systematic sampling method like a belt transect or random quadrat sampling along a line.

First, a measuring tape would be laid out running perpendicular from the mine edge, passing through both the 50m and 100m points. For a belt transect, quadrats (e.g., 1m x 1m squares) would be placed contiguously along the tape between, for example, 45m-55m and 95m-105m to cover each area. Alternatively, for random sampling, multiple random coordinates within a 10m band centered on 50m and another band centered on 100m could be generated, and a quadrat placed at each coordinate.

Within each quadrat, the scientist would estimate the percentage cover of the specific grass species. This is a measure of how much of the ground within the quadrat is occupied by the vertical projection of its leaves and stems. This process would be repeated multiple times (e.g., 10-20 quadrats) at each distance to obtain a representative sample and calculate a mean percentage cover. The mean percentage cover at 50m can then be statistically compared to the mean percentage cover at 100m to determine if there is a significant difference in the population size of the grass species between the two distances.

Question

The table shows data on crops grown and pesticide used in Norway in 2011.

(a) State what is meant by the term pesticide.

(b) Determine which crop had the largest area sprayed with herbicide. Show your working.

(c) Suggest why spring and winter wheat have different percentages of insecticide applied to them.

(d) Discuss the different combinations of pesticides applied to fruit and cereal crops.

(e) Explain an alternative to insecticide that a farmer could use.

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(a): Food production — Crop plants — parts (a), (c), (d), (e)
5(a): Food production — Crop plants — Pest control — parts (a), (e)
4(d): Human influences on the environment — parts (a), (e)
Appendix 4: Mathematical skills — Handling data — part (b)
▶️ Answer/Explanation
Solution

(a) A chemical/substance that kills/destroys pests (such as animals/plants/insects).

Explanation: A pesticide is a broad term for any chemical agent used to eliminate or control organisms considered pests. This includes herbicides for weeds, fungicides for fungi, and insecticides for insects. They work through various mechanisms to disrupt the pest’s life processes.

(b) Largest area = 1319.5 km² (accept 1320 or 1300), Crop = Barley

Explanation: To find the largest area sprayed with herbicide, we need to calculate the actual area sprayed for each crop by multiplying the total area by the percentage sprayed with herbicide (converted to a decimal).

Working for key crops:

  • Barley: 1450 km² × 0.91 = 1319.5 km²
  • Oats: 694 km² × 0.94 = 652.36 km²
  • Spring Wheat: 588 km² × 0.98 = 576.24 km²
  • Winter Wheat: 139 km² × 0.96 = 133.44 km²
  • Potato: 128 km² × 0.92 = 117.76 km²

Barley has the largest calculated area sprayed with herbicide at 1319.5 km².

(c) In winter, colder temperatures mean fewer insects are active, so less insecticide is needed compared to spring when warmer weather leads to more insect activity.

Explanation: The different growing seasons directly impact pest populations. Winter wheat is cultivated during colder months when insect activity is minimal due to low temperatures and reduced food availability. Consequently, the need for insecticide application is lower (7% for winter wheat). In contrast, spring wheat grows during warmer periods, which favor insect reproduction and activity, necessitating a higher use of insecticides (27% for spring wheat) to protect the crop from potential damage.

(d) Fruit crops show a more balanced use of all three pesticide types (around 56-87%), while cereal crops use herbicides most heavily (91-98%) with more variable fungicide use and generally lower insecticide use.

Explanation: The pesticide application patterns reflect the different vulnerabilities of these crop types. Fruit crops (strawberry, apple) have relatively high and even usage across herbicide, fungicide, and insecticide. This is because fruits are often susceptible to insect damage, fungal rots (especially due to their high sugar content and moisture), and weed competition. Cereal crops (barley, oats, wheat), on the other hand, demonstrate a very high reliance on herbicides (91-98%). This is crucial during their early growth stages to eliminate weed competition for resources like light, water, and nutrients. Fungicide use in cereals is more variable (24-86%), possibly depending on specific disease risks for each cereal type. Insecticide use is generally lower in cereals (4-27%) compared to fruits, suggesting insects may be a lesser threat to these crops in this context, or that other control methods are prioritized.

(e) An alternative is biological control, which involves introducing a natural predator of the pest insect.

Explanation: Instead of using chemical insecticides, farmers can employ biological control. This method uses living organisms to manage pest populations. For example, ladybirds can be introduced to control aphids, or the parasitic wasp Encarsia formosa can be used against whitefly. This approach is often more targeted and can be more environmentally sustainable, reducing chemical residues and the risk of pests developing resistance. Other non-chemical alternatives include using physical barriers like nets to exclude insects from the plants.

Question

Lichens are organisms that grow well on stone walls in unpolluted air. Lichens grow less well in polluted air. Car exhaust fumes contain sulfur dioxide that pollutes air.

A scientist investigates the effect of pollution by cars in a city. This is her method:

  • measure the percentage area of a stone wall in the city centre covered by lichen
  • repeat this measurement at different distances from the city centre

The table shows her results.

(a) Explain the results shown in the table.

(b) Describe a method to measure the percentage of a stone wall covered by lichen. 

(c) Adding water to a powder called sodium metabisulphite will release sulfur dioxide gas. Devise a laboratory investigation to find out the effect of sulfur dioxide gas on the heat released by germinating seeds. Include experimental details in your answer and write in full sentences.

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(d): Human influences on the environment — parts (a), (b), (c)
2(f): Respiration — part (c)
3: Assessment Information / Experimental Skillsparts (b), (c)
▶️ Answer/Explanation
Solution

(a) An explanation that makes reference to two of the following points:
• As distance from the city centre increases, the percentage area covered by lichen increases.
• There are more cars/pollution/sulfur dioxide in the city centre, which inhibits lichen growth.
Allow converse statements (e.g., lichen coverage decreases closer to the city centre).

(b) An answer that makes reference to three of the following points:
• Measure the area covered by lichen. Allow using a grid/quadrat to count squares with lichen.
• Measure the total area of the stone wall.
• Divide the lichen-covered area by the total area and multiply by \(100\) to get the percentage.
• Repeat the measurements in different places on the wall to find a mean.

(c) An answer that makes reference to six of the following points:
C (Change): Expose one set of germinating seeds to sulfur dioxide (\(SO_2\)) from sodium metabisulphite and another set to air without \(SO_2\) (or use different concentrations of \(SO_2\)).
O (Organisms): Use the same species/type/age/variety of seeds.
R (Repeat): Use a large number of seeds/repeat the experiment.
M1 (Measurement 1): Measure the temperature change.
M2 (Measurement 2): Use a thermometer.
S1 (Same 1): Use a thermos flask (or insulated container) to contain the seeds and prevent heat loss.
S2 (Same 2): Control other variables (e.g., same moisture, oxygen, starting temperature, light, time, disinfect seeds).

Answer must be in full sentences and include experimental details to access the marks.

Question

Farmers may add chemical fertilisers to their soil.

(a) Explain how chemical fertilisers can increase crop yield.

(b) These fertilisers may leak into rivers.

A scientist measures the oxygen content of water in two different locations of the same river during the month of April.

In location A he finds that the mean dissolved oxygen was 6 mg per litre and at location B he finds that the mean dissolved oxygen was 3 mg per litre.

He concludes that the use of fertiliser in the field has affected the oxygen content of the river.

Discuss his conclusion.

(c) Some farmers use alternative substances to chemical fertilisers.

Suggest one alternative substance that a farmer may use.

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(d): Human influences on the environment — parts (b), (c)
6(a): Food production — part (a)
2(e): Nutrition (Plants) — part (a)
▶️ Answer/Explanation
Solution

(a) An explanation that makes reference to four of the following points:

  • nitrates (for growth)
  • for amino acids
  • for protein 
  • magnesium for chlorophyll / chloroplasts 
  • so more photosynthesis 
  • more glucose 
  • phosphates used for ATP / DNA / eq 
  • potassium for control of water movement / eq 

(b) An answer that makes reference to four of the following points:

  • fertiliser leaches into river / washed into river / eq 
  • fertiliser would cause algal / plant growth / algal bloom / eutrophication 
  • dead algae are decomposed / broken down by bacteria / decomposers 
  • (bacterial) respiration would reduce oxygen 
  • means were calculated / readings repeated so experiment is reliable / valid 
  • measurements taken at same time of year / in April (so are valid) 
  • direction of river is past farm 
  • reduced oxygen could be due to other factors / sources of fertiliser from other fields 

(c) • manure / faeces / dung / compost / seaweed / bone / blood / animal wastes / eq 

Question

The diagram shows a food chain in the Antarctic ocean.

(a) (i) Which term describes the trophic level of the krill?

  • A. predator
  • B. prey
  • C. primary consumer
  • D. secondary consumer

(ii) Draw a labelled pyramid of biomass to represent this food chain.

(b) The microscopic plants float in seawater, but also grow on the lower surface of ice. The krill feed on the microscopic plants. They remove microscopic plants from the lower surface of the ice at a rate of 1.6 cm\(^2\) per second. Calculate the time taken for the krill to remove microscopic plants from one square metre of ice. Give your answer in minutes.

(c) A student investigates the rate that krill feeding removes microscopic plants floating in seawater. Suggest how the student could do this investigation in a laboratory.

(d) Krill obtain most of their food from microscopic plants growing on the lower surface of ice. Explain how global warming could affect the whale population in the Antarctic ocean.

Most-appropriate topic codes (Edexcel IGCSE Biology):

5(b): Feeding relationships — parts (a)(i), (a)(ii), (d)
5(d): Human influences on the environment — part (d)
Appendix 3: Mathematical skills — part (b)
Appendix 5: Suggested practical investigations — part (c)
▶️ Answer/Explanation
Solution

(a)(i) C primary consumer

Explanation: Krill feed directly on microscopic plants, which are the producers in this food chain. Organisms that eat producers are called primary consumers. Predators (A) hunt other animals, prey (B) are hunted by others, and secondary consumers (D) eat primary consumers, which would be the whale in this chain, not the krill.

(a)(ii)

[Pyramid sketch showing: wide base labeled “microscopic plants”, middle section labeled “krill”, narrow top labeled “whale”]

Explanation: A pyramid of biomass represents the total mass of living material at each trophic level. Producers (microscopic plants) have the greatest biomass, forming the base. Primary consumers (krill) have less biomass, and secondary consumers (whales) have the least biomass, forming the top. The pyramid should be upright with labels in the correct order.

(b) Time taken = 104 minutes (approximately)

Explanation: First, we need to convert the area from square meters to square centimeters because the feeding rate is given in cm²/s. One square meter equals 10,000 cm². If krill remove plants at 1.6 cm² per second, the time to clear 10,000 cm² is 10,000 ÷ 1.6 = 6,250 seconds. To convert seconds to minutes, we divide by 60: 6,250 ÷ 60 ≈ 104.17 minutes. Giving the answer as 104 minutes is appropriate, considering significant figures.

(c)

Explanation: To investigate this in a lab, the student would need to set up a controlled environment. They could use a large container filled with seawater. They would add a known, measurable quantity of microscopic plants – this could be done by counting them under a microscope or measuring their mass or the area they cover. Then, they would introduce a specific number of krill into the container. The container would be left for a set period of time. After this time, the student would re-measure the number or mass of the remaining microscopic plants. The difference between the starting and ending amounts shows how much was consumed. To ensure reliability, this experiment should be repeated several times to calculate a mean rate of consumption.

(d)

Explanation: Global warming leads to rising temperatures, which causes polar ice to melt. Since the microscopic plants that krill primarily eat grow on the underside of this ice, melting ice directly reduces their habitat. With less surface area for the plants to grow on, the population of these microscopic plants will decline. Krill rely on this food source, so a reduction in plants leads to a reduction in the krill population, either through starvation, lower reproduction rates, or migration. Whales, being at the top of this food chain, depend entirely on consuming large quantities of krill. Therefore, a significant drop in the krill population would mean less food is available for the whales. This could lead to a decline in the whale population, as whales might starve, die from malnutrition, or be forced to migrate to other areas in search of food, reducing their numbers in the Antarctic ocean.

Question

The diagram shows part of the digestive system of a cow.

(a) Name the parts labelled P and Q.

(b) The cow’s stomach contains microorganisms that digest plant cell walls.
Suggest why these microorganisms are useful to a cow.

(c) Farmers keep cows to produce milk.
Injecting cows with growth hormone (GH) will increase milk production.
This allows farmers to obtain the same volume of milk from fewer cows.
Digestion in cows releases methane gas into the atmosphere.
A scientist claims that injecting GH into cows would reduce climate change.
Comment on this claim.

Most-appropriate topic codes (Edexcel IGCSE Biology):

2(e): Nutrition — Humans (digestive system) — part (a)
5(a): Food production — Micro-organisms — part (b)
4(d): Human influences on the environment — part (c)
5(a): Food production — Crop plants & Micro-organisms — part (c)
▶️ Answer/Explanation
Solution

(a)

P: Ileum / Small Intestine
Q: Rumen

Explanation: In the digestive system of a cow, which is a ruminant, part P is the ileum, which is the final section of the small intestine where further digestion and absorption of nutrients occur. Part Q is the rumen, the first and largest chamber of the stomach, where microbial fermentation of plant material takes place.

(b)

Explanation: The microorganisms in the cow’s stomach, particularly in the rumen, are essential because they produce enzymes like cellulase that break down cellulose, a major component of plant cell walls. Cows, like other mammals, cannot produce cellulase on their own. By digesting cellulose, these microbes release glucose and other simpler sugars that the cow can then absorb and use for energy through respiration. This symbiotic relationship allows the cow to efficiently utilize grass and other fibrous plant materials as its primary food source.

(c)

Explanation: The scientist’s claim has both supporting and opposing points. On one hand, using GH to increase milk yield per cow could mean that farmers need to keep fewer cows to produce the same amount of milk. Since cows are a significant source of methane (a potent greenhouse gas) released during digestion, having fewer cows could lead to less methane being released into the atmosphere. This could potentially reduce the greenhouse effect and slow down global warming.

However, there are limitations to this claim. Farmers might choose to keep the same number of cows to produce even more milk, negating any potential environmental benefit. Furthermore, cows are also kept for beef production, not just milk, so the overall number of cows might not decrease significantly. Finally, climate change is driven by many factors, including other greenhouse gases from sources like fossil fuels, so the impact of reducing methane from cows alone might be limited without addressing other major contributors.

Question

The diagram shows a yeast cell.

(a) (i) Which row of the table is correct for this yeast cell?

(ii) Which type of organism is a yeast cell?

  • A. a bacterium
  • B. a fungus
  • C. a plant
  • D. a protoctist

(b) Biofuel is made from ethanol.

Scientists use genetically modified (GM) yeast to produce biofuel.

The GM yeast contains an enzyme that digests plant cell walls to produce glucose.

The yeast uses the glucose in respiration to produce ethanol.

(i) Which of these equations shows the respiration in the yeast?

  • A. glucose → ethanol
  • B. glucose → ethanol + carbon dioxide
  • C. glucose + oxygen → ethanol
  • D. glucose + oxygen → ethanol + carbon dioxide

(ii) Name an enzyme used by scientists to genetically modify the yeast.

(iii) The GM yeast is a recombinant strain.

State what is meant by the term recombinant.

(iv) Suggest why biofuel produced using glucose from plants could reduce global warming.

(c) The graph shows the mass of ethanol produced by GM yeast and by normal yeast over a period of 3 days.

(i) Calculate the percentage increase in the mass of ethanol produced by GM yeast compared to normal yeast after 1 day.

(ii) Give two reasons why the rate of ethanol production decreases after 1 day.

Most-appropriate topic codes (Edexcel IGCSE Biology):

1(b): Variety of living organisms — part (a)(i), (a)(ii)
5(a): Food production — part (b)
2(f): Respiration — part (b)(i)
5(c): Genetic modification (genetic engineering) — parts (b)(ii), (b)(iii)
4(d): Human influences on the environment — part (b)(iv)
4: Mathematical skills (Arithmetic and numerical computation):part (c)(i)
2(f): Respiration — part (c)(ii)
▶️ Answer/Explanation
Solution

(a)(i) C (chitin and glycogen)

Explanation: Yeast is a fungus, and fungal cell walls are primarily composed of chitin, not cellulose which is found in plants. For energy storage, fungi like yeast store glycogen in their cytoplasm, similar to animals, rather than starch which is typical of plants.

(a)(ii) B (a fungus)

Explanation: Yeast is classified as a unicellular fungus. It is not a bacterium (which are prokaryotic), a plant (which are multicellular and photosynthetic), or a protoctist (which is a diverse group including algae and protozoa).

(b)(i) B (glucose → ethanol + carbon dioxide)

Explanation: The respiration described is anaerobic respiration (fermentation) in yeast. The correct chemical equation for this process is glucose being broken down into ethanol and carbon dioxide, without the use of oxygen. Option A is incomplete, and options C and D involve oxygen, which characterizes aerobic respiration.

(b)(ii) Restriction enzyme / endonuclease / ligase

Explanation: To genetically modify the yeast, scientists use enzymes like restriction endonucleases (which cut DNA at specific sequences) and DNA ligase (which joins DNA fragments together). These enzymes are essential tools in genetic engineering for inserting new genes into an organism’s genome.

(b)(iii) Contains new / foreign DNA / gene from another organism.

Explanation: A recombinant organism is one that has had its genetic material altered by the insertion of DNA from a different source. In this case, the GM yeast has been modified to contain a gene from another organism that codes for an enzyme capable of digesting plant cell walls.

(b)(iv)

Explanation: Biofuel from plants can help reduce global warming primarily because it is part of a carbon-neutral cycle. The carbon dioxide released when the biofuel is burned is approximately equal to the carbon dioxide that the plants absorbed from the atmosphere during photosynthesis. This contrasts with burning fossil fuels, which releases carbon that has been locked away for millions of years, thereby increasing the net concentration of CO₂ in the atmosphere. Additionally, using biofuels can reduce our dependence on fossil fuels, leading to lower overall emissions of greenhouse gases.

(c)(i) 76% (accept range 69-80%)

Explanation: To calculate the percentage increase, we use the formula: \[ \text{Percentage Increase} = \frac{\text{Mass from GM yeast} – \text{Mass from normal yeast}}{\text{Mass from normal yeast}} \times 100\% \] From the graph, after 1 day, the mass from GM yeast is approximately 2.2 g and from normal yeast is approximately 1.25 g. \[ \text{Increase} = 2.2 – 1.25 = 0.95 \text{ g} \] \[ \text{Percentage Increase} = \frac{0.95}{1.25} \times 100\% = 76\% \] Slight variations in reading the graph values can lead to answers between 69% and 80% being accepted.

(c)(ii)

Explanation: The rate of ethanol production decreases after 1 day likely due to two main factors. First, the glucose (substrate) that the yeast uses for respiration begins to run out or become depleted, slowing down the metabolic process. Second, the ethanol produced is actually toxic to the yeast in high concentrations. As ethanol builds up in the surrounding environment, it can inhibit the yeast’s enzymes and eventually kill the cells, leading to a decline in the production rate.

Question

Pollution of air or water can affect ecosystems.

(a) (i) Explain the biological consequences of air pollution by sulfur dioxide.

(a) (ii) State how sulfur dioxide pollution can be reduced.

(b) Some scientists have suggested that adding hydrogencarbonate solution to soil, instead of adding water, can increase plant growth.

Design an investigation to discover the effect that adding hydrogencarbonate solution has on the growth of seedlings.

Include experimental details in your answer and write in full sentences.

Most-appropriate topic codes (Edexcel IGCSE Biology):

4(d): Human influences on the environment – air pollution by sulfur dioxide — parts (a)(i), (a)(ii)
1(c): Factors affecting the rate of photosynthesis – carbon dioxide concentration — part (b)
1(a): Characteristics of living organisms – growth — part (b)
▶️ Answer/Explanation
Solution

(a) (i)

Explanation: Sulfur dioxide (SO₂) released into the atmosphere, primarily from burning fossil fuels, has several harmful biological consequences. Firstly, it dissolves in atmospheric water vapour to form sulfuric acid (H₂SO₄), leading to acid rain. This acid rain can damage plant tissues, leading to deforestation, and can acidify lakes and rivers, causing the death of fish and other aquatic organisms. Furthermore, sulfur dioxide can cause breathing problems in humans and animals by irritating the respiratory system.

(a) (ii)

Answer: By reducing the burning of fossil fuels / using low-sulfur fuels / using alternative energy sources.

Explanation: The most direct way to reduce sulfur dioxide pollution is to decrease its production at the source. This can be achieved by burning less fossil fuel (like coal and oil), switching to low-sulfur varieties of these fuels, or using alternative energy sources that do not produce SO₂, such as solar, wind, or nuclear power.

(b)

Answer:

A suitable investigation would be designed as follows:

  • Control Variable (C): Use a large number of seedlings of the same species, age, and size. Divide them into groups. One group will be watered with a solution containing hydrogencarbonate (HCO₃⁻) at a specific concentration, while the control group will be watered with pure water. You could also test different concentrations of HCO₃⁻ to see the effect of the concentration.
  • Organism (O): Use the same species, age, and strain of seedling to ensure that any differences in growth are due to the treatment and not genetic variation.
  • Repeat (R): The experiment should be repeated for each concentration of hydrogencarbonate solution to ensure the results are reliable and not due to chance.
  • Measurement 1 (M1): The growth should be measured using a suitable metric, such as the yield (dry mass), height of the seedlings, number of leaves, or the number of plants that successfully germinate.
  • Measurement 2 (M2): These measurements should be taken after a stated, suitable period, for example, 48 hours or longer, to allow measurable growth to occur.
  • Standardization 1 (S1): Other factors that affect plant growth must be kept constant. This includes light intensity, carbon dioxide levels, and temperature.
  • Standardization 2 (S2): Further controls are needed, such as using the same type and volume of compost, the same volume of solution, and the same levels of humidity, moisture, and minerals/fertiliser for all seedlings.

Explanation: This experimental design is comprehensive. It starts by clearly defining the independent variable (presence and concentration of HCO₃⁻) and the dependent variable (a measure of growth). Using a large number of identical seedlings and repeating the experiment ensures reliability. Controlling all other variables (light, temperature, water volume, etc.) is crucial to ensure that any observed effect on growth can be confidently attributed to the hydrogencarbonate solution and not to other factors. Measuring growth after a set time allows for a fair comparison between the different treatment groups.

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