Edexcel Mathematics (4XMAF) -Unit 1 - 4.9 Mensuration of 2D Shapes- Study Notes- New Syllabus

Edexcel Mathematics (4XMAF) -Unit 1 – 4.9 Mensuration of 2D Shapes- Study Notes- New syllabus

Edexcel Mathematics (4XMAF) -Unit 1 – 4.9 Mensuration of 2D Shapes- Study Notes -Edexcel iGCSE Mathematics – per latest Syllabus.

Key Concepts:

A convert measurements within the metric system to include linear and area units (e.g. cm² to m² and vice versa)
B find the perimeter of shapes made from triangles and rectangles
C find the area of simple shapes using the formulae for the areas of triangles and rectangles
D find the area of parallelograms and trapezia
E find circumferences and areas of circles using relevant formulae; find perimeters and areas of semicircles

Edexcel iGCSE Mathematics -Concise Summary Notes- All Topics

Metric Unit Conversions (Length and Area)

In mensuration, measurements must be in the same units before calculating area or perimeter.

Length Conversions

\( 10 \text{ mm} = 1 \text{ cm} \)

\( 100 \text{ cm} = 1 \text{ m} \)

\( 1000 \text{ m} = 1 \text{ km} \)

When converting length, multiply or divide by 10, 100 or 1000.

Area Conversions

Area units are squared, so the conversion factor is also squared.

\( 1 \text{ m} = 100 \text{ cm} \)

\( 1 \text{ m}^2 = 100^2 = 10{,}000 \text{ cm}^2 \)

\( 1 \text{ cm}^2 = \dfrac{1}{10{,}000} \text{ m}^2 \)

Key Idea

Length → multiply/divide by 100

Area → multiply/divide by \( 100^2 = 10{,}000 \)

Example 1:

Convert \( 250 \) cm to metres.

▶️ Answer/Explanation

\( 250 ÷ 100 = 2.5 \)

Conclusion: \( 2.5 \) m.

Example 2:

Convert \( 3 \text{ m}^2 \) to \( \text{cm}^2 \).

▶️ Answer/Explanation

\( 1 \text{ m}^2 = 10{,}000 \text{ cm}^2 \)

\( 3 × 10{,}000 = 30{,}000 \)

Conclusion: \( 30{,}000 \text{ cm}^2 \).

Example 3:

Convert \( 45{,}000 \text{ cm}^2 \) to \( \text{m}^2 \).

▶️ Answer/Explanation

\( 45{,}000 ÷ 10{,}000 = 4.5 \)

Conclusion: \( 4.5 \text{ m}^2 \).

Perimeter of Shapes (Triangles and Rectangles)

The perimeter is the total distance around the outside of a shape.

To find the perimeter, add the lengths of all the sides.

Triangle

A triangle has three sides.

Perimeter \( = a + b + c \)

Rectangle

A rectangle has two equal lengths and two equal widths.

Perimeter \( = 2(\text{length} + \text{width}) \)

Important

Make sure all sides are in the same units before adding.

Example 1:

Find the perimeter of a triangle with sides \( 5 \) cm, \( 7 \) cm and \( 9 \) cm.

▶️ Answer/Explanation

\( 5 + 7 + 9 = 21 \)

Conclusion: \( 21 \) cm.

Example 2:

A rectangle has length \( 12 \) m and width \( 5 \) m. Find the perimeter.

▶️ Answer/Explanation

\( 2(12 + 5) = 2 × 17 = 34 \)

Conclusion: \( 34 \) m.

Example 3:

A triangular garden has sides \( 8 \) m, \( 10 \) m and \( 12 \) m. How much fencing is needed?

▶️ Answer/Explanation

\( 8 + 10 + 12 = 30 \)

Conclusion: \( 30 \) m of fencing.

Area of Triangles and Rectangles

The area of a shape is the amount of space inside it.

Area is measured in square units such as \( \text{cm}^2 \) or \( \text{m}^2 \).

Area of a Rectangle

\( \text{Area} = \text{length} \times \text{width} \)

Area of a Triangle

\( \text{Area} = \dfrac{1}{2} \times \text{base} \times \text{height} \)

The height must be perpendicular to the base.

Important

Use the same units for all lengths before calculating the area.

Example 1:

Find the area of a rectangle with length \( 9 \) cm and width \( 4 \) cm.

▶️ Answer/Explanation

\( 9 \times 4 = 36 \)

Conclusion: \( 36 \text{ cm}^2 \).

Example 2:

A triangle has base \( 10 \) m and height \( 6 \) m. Find the area.

▶️ Answer/Explanation

\( \dfrac{1}{2} \times 10 \times 6 = 30 \)

Conclusion: \( 30 \text{ m}^2 \).

Example 3:

A triangular field has base \( 12 \) m and perpendicular height \( 5 \) m. Find the area.

▶️ Answer/Explanation

\( \dfrac{1}{2} \times 12 \times 5 = 30 \)

Conclusion: \( 30 \text{ m}^2 \).

Area of Parallelograms and Trapezia

Area of a Parallelogram

A parallelogram has opposite sides parallel.

The area is found using the base and the perpendicular height.

\( \text{Area} = \text{base} \times \text{height} \)

The height must be measured at a right angle to the base.

Area of a Trapezium

A trapezium has one pair of parallel sides.

\( \text{Area} = \dfrac{1}{2}(a + b)h \)

where \( a \) and \( b \) are the parallel sides and \( h \) is the perpendicular height.

Important

The height is not the sloping side. It must be the perpendicular distance between the parallel sides.

Example 1:

A parallelogram has base \( 12 \) cm and height \( 7 \) cm. Find the area.

▶️ Answer/Explanation

\( 12 \times 7 = 84 \)

Conclusion: \( 84 \text{ cm}^2 \).

Example 2:

A trapezium has parallel sides \( 8 \) m and \( 14 \) m and height \( 5 \) m. Find the area.

▶️ Answer/Explanation

\( \dfrac{1}{2}(8 + 14) \times 5 \)

\( \dfrac{1}{2} \times 22 \times 5 = 11 \times 5 = 55 \)

Conclusion: \( 55 \text{ m}^2 \).

Example 3:

A parallelogram has area \( 72 \text{ cm}^2 \) and base \( 9 \) cm. Find the height.

▶️ Answer/Explanation

\( \text{height} = \dfrac{72}{9} = 8 \)

Conclusion: \( 8 \) cm.

Circles and Semicircles

Key Parts of a Circle

Radius \( (r) \) → distance from centre to edge

Diameter \( (d) \) → distance across the circle through the centre

\( d = 2r \)

Circumference of a Circle

The circumference is the distance around the circle.

\( C = 2\pi r \)

or

\( C = \pi d \)

Area of a Circle

\( A = \pi r^2 \)

Semicircles

A semicircle is half a circle.

Area of a Semicircle

\( A = \dfrac{1}{2}\pi r^2 \)

Perimeter of a Semicircle

The perimeter includes the curved part and the diameter.

  • Curved part \( = \pi r \)
  • Perimeter \( = \pi r + 2r \)

Important

Use \( \pi \approx 3.14 \) unless instructed otherwise.

Example 1:

Find the circumference of a circle with radius \( 7 \) cm.

▶️ Answer/Explanation

\( C = 2\pi r = 2 \times 3.14 \times 7 = 43.96 \)

Conclusion: \( 43.96 \) cm.

Example 2:

Find the area of a circle with diameter \( 10 \) cm.

▶️ Answer/Explanation

\( r = 5 \)

\( A = \pi r^2 = 3.14 \times 25 = 78.5 \)

Conclusion: \( 78.5 \text{ cm}^2 \).

Example 3:

A semicircle has radius \( 4 \) cm. Find its perimeter.

▶️ Answer/Explanation

\( \pi r + 2r = 3.14 \times 4 + 8 = 12.56 + 8 = 20.56 \)

Conclusion: \( 20.56 \) cm.

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