Edexcel Mathematics (4XMAF) -Unit 1 - 6.3 Probability- Study Notes- New Syllabus

Edexcel Mathematics (4XMAF) -Unit 1 – 6.3 Probability- Study Notes- New syllabus

Edexcel Mathematics (4XMAF) -Unit 1 – 6.3 Probability- Study Notes -Edexcel iGCSE Mathematics – per latest Syllabus.

Key Concepts:

A understand the language of probability
Notes: outcomes, equally likely, events, random

B understand and use the probability scale
P(certainty) = 1
P(impossibility) = 0

C understand and use estimates or measures of probability from theoretical models

D find probabilities from a Venn diagram

E understand the concepts of a sample space and an event, and how the probability of an event happening can be determined from the sample space

Example for tossing two coins:
(H, H), (H, T), (T, H), (T, T)

F list all the outcomes for single events and for two successive events in a systematic way

G estimate probabilities from previously collected data

H calculate the probability of the complement of an event happening
P(A′) = 1 − P(A)

I use the addition rule of probability for mutually exclusive events
P(either A or B occurring) = P(A) + P(B) when A and B are mutually exclusive

J understand and use the term ‘expected frequency’
Determine an estimate of the number of times an event with probability 0.4 will happen over 300 tries

Edexcel iGCSE Mathematics -Concise Summary Notes- All Topics

Language of Probability

Probability measures how likely something is to happen.

We describe chance using special terms.

Outcome

An outcome is a possible result of an experiment.

Example: Tossing a coin → Heads or Tails

Event

An event is one or more outcomes.

Example: Getting a head when tossing a coin

Random

A random experiment has no predictable result.

Example: Rolling a fair die

Equal Likelihood

Outcomes are equally likely when each outcome has the same chance of happening.

Example: Each number on a fair die has probability \( \dfrac{1}{6} \).

Key Idea

Probability compares favourable outcomes to total outcomes.

Example 1:

When tossing a coin, state the outcomes.

▶️ Answer/Explanation

Heads, Tails

Conclusion: Two outcomes.

Example 2:

Rolling a fair die, what is the event “getting an even number”?

▶️ Answer/Explanation

Even numbers: \( 2,4,6 \)

Conclusion: The event contains 3 outcomes.

Example 3:

Is choosing a card from a shuffled deck a random experiment?

▶️ Answer/Explanation

The result cannot be predicted.

Conclusion: Yes, it is random.

The Probability Scale

Probability is measured on a scale from 0 to 1.

It shows how likely an event is to happen.

Key Values

\( P(\text{impossible}) = 0 \)

\( P(\text{certain}) = 1 \)

All probabilities lie between 0 and 1:

\( 0 \le P(A) \le 1 \)

Interpreting the Scale

Close to 0 → unlikely

Around 0.5 → even chance

Close to 1 → very likely

Important

Probability can also be written as a fraction, decimal or percentage.

Example 1:

What is the probability of rolling a 7 on a normal six-sided die?

▶️ Answer/Explanation

A die only has numbers 1 to 6.

Impossible event

Conclusion: \( P = 0 \).

Example 2:

What is the probability that the sun will rise tomorrow?

▶️ Answer/Explanation

This is considered certain.

Conclusion: \( P = 1 \).

Example 3:

A fair coin is tossed. What is the probability of getting a head?

▶️ Answer/Explanation

Two equally likely outcomes.

\( P(\text{Head}) = \dfrac{1}{2} = 0.5 \)

Conclusion: Even chance.

Theoretical Probability

When all outcomes are equally likely, probability can be calculated using a formula.

\( \text{Probability} = \dfrac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}} \)

This is called theoretical probability because it is based on reasoning, not experiment.

Examples of Equally Likely Outcomes

  • Tossing a fair coin
  • Rolling a fair die
  • Choosing a card from a well-shuffled deck
  • Important

The probability must always be between 0 and 1.

Example 1:

Find the probability of rolling a 4 on a fair six-sided die.

▶️ Answer/Explanation

Total outcomes = 6

Favourable outcomes = 1

\( P(4) = \dfrac{1}{6} \)

Conclusion: \( \dfrac{1}{6} \).

Example 2:

A bag contains 3 red balls and 5 blue balls. One ball is chosen at random. Find the probability of choosing a red ball.

▶️ Answer/Explanation

Total balls = 8

Red balls = 3

\( P(\text{red}) = \dfrac{3}{8} \)

Conclusion: \( \dfrac{3}{8} \).

Example 3:

A spinner has 8 equal sections numbered 1 to 8. Find the probability of landing on an even number.

▶️ Answer/Explanation

Even numbers: \( 2,4,6,8 \)

Favourable outcomes = 4

Total outcomes = 8

\( P(\text{even}) = \dfrac{4}{8} = \dfrac{1}{2} \)

Conclusion: \( \dfrac{1}{2} \).

Probability from Venn Diagrams

A Venn diagram shows events using overlapping circles inside a rectangle (the sample space).

Each number inside the diagram represents the number of outcomes.

Key Terms

 

Intersection \( (A \cap B) \) → outcomes common to both sets

Union \( (A \cup B) \) → outcomes in either set

Outside both circles → neither event

Finding Probability

\( P(\text{event}) = \dfrac{\text{number in the event}}{\text{total number of outcomes}} \)

First find the total number of outcomes in the rectangle.

Example 1:

In a group of students:

12 like Maths only

5 like both Maths and Science

8 like Science only

5 like neither

Find \( P(\text{Maths}) \).

▶️ Answer/Explanation

Students who like Maths:

\( 12 + 5 = 17 \)

Total students:

\( 12 + 5 + 8 + 5 = 30 \)

\( P(\text{Maths}) = \dfrac{17}{30} \)

Conclusion: \( \dfrac{17}{30} \).

Example 2:

Using the same data, find \( P(\text{both Maths and Science}) \).

▶️ Answer/Explanation

Favourable outcomes = 5

Total = 30

\( P = \dfrac{5}{30} = \dfrac{1}{6} \)

Conclusion: \( \dfrac{1}{6} \).

Example 3:

Find \( P(\text{neither subject}) \).

▶️ Answer/Explanation

Neither = 5

Total = 30

\( P = \dfrac{5}{30} = \dfrac{1}{6} \)

Conclusion: \( \dfrac{1}{6} \).

Sample Space and Events

The sample space is the list of all possible outcomes of a random experiment.

An event is one or more outcomes chosen from the sample space.

Notation

Sample space \( S \)

Event \( A \subseteq S \)

Finding Probability from a Sample Space

\( P(A) = \dfrac{\text{Number of outcomes in event }A}{\text{Total number of outcomes in }S} \)

Each outcome must be equally likely.

Example 1:

A coin is tossed once. Write the sample space.

▶️ Answer/Explanation

\( S = \{H, T\} \)

Conclusion: Two outcomes.

Example 2:

Two coins are tossed. List the sample space.

▶️ Answer/Explanation

\( S = \{(H,H), (H,T), (T,H), (T,T)\} \)

Conclusion: Four outcomes.

Example 3:

A die is rolled. Find the probability of getting an even number.

▶️ Answer/Explanation

Sample space:

\( S = \{1,2,3,4,5,6\} \)

Event (even numbers):

\( A = \{2,4,6\} \)

\( P(A) = \dfrac{3}{6} = \dfrac{1}{2} \)

Conclusion: \( \dfrac{1}{2} \).

Listing Outcomes Systematically

To find probabilities correctly, we must list all possible outcomes without missing any.

This is called listing outcomes systematically.

Single Events

A single event involves one experiment.

 

Example: Rolling one die

\( \{1,2,3,4,5,6\} \)

Two Successive Events

Two experiments happen one after the other.

We list outcomes in an ordered way so none are missed.

Example: Tossing two coins

\( (H,H), (H,T), (T,H), (T,T) \)

Tip

Fix the first outcome, then list all possibilities for the second outcome.

Example 1:

List all outcomes when a coin is tossed once.

▶️ Answer/Explanation

\( H, T \)

Conclusion: 2 outcomes.

Example 2:

List all outcomes when a die is rolled twice.

▶️ Answer/Explanation

Fix first number and vary second:

\( (1,1),(1,2),(1,3),(1,4),(1,5),(1,6) \)

\( (2,1),(2,2),(2,3),(2,4),(2,5),(2,6) \)

\( (3,1),(3,2),(3,3),(3,4),(3,5),(3,6) \)

\( (4,1),(4,2),(4,3),(4,4),(4,5),(4,6) \)

\( (5,1),(5,2),(5,3),(5,4),(5,5),(5,6) \)

\( (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) \)

Conclusion: 36 outcomes.

Example 3:

Two coins are tossed. How many outcomes are possible?

▶️ Answer/Explanation

\( (H,H),(H,T),(T,H),(T,T) \)

Conclusion: 4 outcomes.

Estimating Probability from Data

Probability can be estimated using results from an experiment.

This is called experimental probability.

\( \text{Estimated probability} = \dfrac{\text{Number of times the event occurs}}{\text{Total number of trials}} \)

The more trials carried out, the more reliable the estimate becomes.

Important

Experimental probability may not be exactly the same as theoretical probability, especially with a small number of trials.

Example 1:

A coin is tossed 40 times and lands on heads 18 times. Estimate the probability of getting a head.

▶️ Answer/Explanation

\( \dfrac{18}{40} = \dfrac{9}{20} = 0.45 \)

Conclusion: Estimated probability \( 0.45 \).

Example 2:

A die is rolled 60 times. A six appears 7 times. Estimate the probability of rolling a six.

▶️ Answer/Explanation

\( \dfrac{7}{60} \approx 0.117 \)

Conclusion: Approximately \( 0.117 \).

Example 3:

A spinner is spun 100 times. It lands on blue 28 times. Estimate the probability of landing on blue.

▶️ Answer/Explanation

\( \dfrac{28}{100} = 0.28 \)

Conclusion: Estimated probability \( 0.28 \).

Complement of an Event

The complement of an event means the event does not happen.

If event \( A \) happens, its complement is written \( A’ \).F

\( A’ \) = “not \( A \)”

Key Rule

\( P(A’) = 1 – P(A) \)

This works because either an event happens or it does not happen.

Important

The probabilities of an event and its complement always add to 1.

\( P(A) + P(A’) = 1 \)

Example 1:

The probability that it rains tomorrow is \( 0.3 \). Find the probability that it does not rain.

▶️ Answer/Explanation

\( P(\text{not rain}) = 1 – 0.3 = 0.7 \)

Conclusion: \( 0.7 \).

Example 2:

A bag contains only red and blue balls. The probability of choosing a red ball is \( \dfrac{2}{5} \). Find the probability of choosing a blue ball.

▶️ Answer/Explanation

\( P(\text{blue}) = 1 – \dfrac{2}{5} = \dfrac{3}{5} \)

Conclusion: \( \dfrac{3}{5} \).

Example 3:

The probability a student passes an exam is \( 0.82 \). Find the probability the student fails.

▶️ Answer/Explanation

\( 1 – 0.82 = 0.18 \)

Conclusion: \( 0.18 \).

Addition Rule for Mutually Exclusive Events

Two events are mutually exclusive if they cannot happen at the same time.

Example: When rolling a die, you cannot get both a 2 and a 5 in one roll.

Addition Rule

If events \( A \) and \( B \) are mutually exclusive:

\( P(A \text{ or } B) = P(A) + P(B) \)

This is the probability that either event occurs.

Important

Only use this rule when the events cannot occur together.

Example 1:

A fair die is rolled. Find the probability of getting a 1 or a 6.

▶️ Answer/Explanation

\( P(1) = \dfrac{1}{6} \)

\( P(6) = \dfrac{1}{6} \)

\( P(1 \text{ or } 6) = \dfrac{1}{6} + \dfrac{1}{6} = \dfrac{2}{6} = \dfrac{1}{3} \)

Conclusion: \( \dfrac{1}{3} \).

Example 2:

A card is chosen from a standard deck of 52 cards. Find the probability of getting a King or a Queen.

▶️ Answer/Explanation

Kings = 4

Queens = 4

\( P = \dfrac{4}{52} + \dfrac{4}{52} = \dfrac{8}{52} = \dfrac{2}{13} \)

Conclusion: \( \dfrac{2}{13} \).

Example 3:

A spinner has 10 equal sections numbered 1 to 10. Find the probability of landing on a multiple of 3 or a multiple of 5.

▶️ Answer/Explanation

Multiples of 3: \( 3,6,9 \) → 3 outcomes

Multiples of 5: \( 5,10 \) → 2 outcomes

Total favourable = 5

\( P = \dfrac{5}{10} = \dfrac{1}{2} \)

Conclusion: \( \dfrac{1}{2} \).

Expected Frequency

The expected frequency is the number of times we expect an event to occur after many trials.

It is based on probability.

\( \text{Expected frequency} = \text{number of trials} \times \text{probability of the event} \)

This gives an estimate, not an exact value.

Important

The larger the number of trials, the closer the result is likely to be to the expected frequency.

Example 1:

An event has probability \( 0.4 \). How many times is it expected to happen in 300 trials?

▶️ Answer/Explanation

\( 300 \times 0.4 = 120 \)

Conclusion: 120 times.

Example 2:

The probability of getting a head when tossing a fair coin is \( \dfrac{1}{2} \). How many heads are expected in 80 tosses?

▶️ Answer/Explanation

\( 80 \times \dfrac{1}{2} = 40 \)

Conclusion: 40 heads.

Example 3:

A spinner lands on red with probability \( 0.25 \). Estimate how many times it will land on red in 200 spins.

▶️ Answer/Explanation

\( 200 \times 0.25 = 50 \)

Conclusion: 50 times.

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