Edexcel Mathematics (4XMAH) -Unit 2 - 2.3 Expressions and Formulae- Study Notes- New Syllabus

Edexcel Mathematics (4XMAH) -Unit 2 – 2.3 Expressions and Formulae- Study Notes- New syllabus

Edexcel Mathematics (4XMAH) -Unit 2 – 2.3 Expressions and Formulae- Study Notes -Edexcel iGCSE Mathematics – per latest Syllabus.

Key Concepts:

A understand the process of manipulating formulae or equations to change the subject, including cases where the subject may appear twice or a power of the subject occurs
Make r the subject of V = 4/3 πr³
Make a the subject of 3a + 5 = (4 − a)/r
Make t the subject of T = 2π√(l/g)

Edexcel iGCSE Mathematics -Concise Summary Notes- All Topics

Changing the Subject of a Formula

Very often in mathematics and science we need to rearrange a formula so that a different variable becomes the subject.

The subject of a formula is the letter that stands alone on one side of the equation.

For example:

In \( A=\pi r^2 \), the subject is \( A \).

If we are asked to make \( r \) the subject, we must rearrange the equation so that \( r \) is alone.

Key Principle

An equation is like a balance. Whatever operation you do to one side, you must do to the other side.

You should always undo operations in the reverse order (this is called working with inverse operations):

  • Undo addition by subtraction
  • Undo subtraction by addition
  • Undo multiplication by division
  • Undo division by multiplication
  • Undo squares using square roots
  • Undo cubes using cube roots

Recommended Order

When rearranging:

1. Remove brackets

2. Remove fractions

3. Move terms containing the subject to one side

4. Factorise if the subject appears more than once

5. Undo powers or roots last

Important Situations

You must be especially careful when:

  • The subject appears twice
  • The subject is inside a bracket
  • The subject is squared or cubed
  • The subject is inside a square root

Example 1:

Make \( r \) the subject of \( V=\dfrac{4}{3}\pi r^3 \).

▶️ Answer/Explanation

Step 1: Remove the fraction by multiplying both sides by \( \dfrac{3}{4\pi} \).

\( r^3=\dfrac{3V}{4\pi} \)

Step 2: Undo the cube using a cube root.

\( r=\sqrt[3]{\dfrac{3V}{4\pi}} \)

Conclusion: \( r=\sqrt[3]{\dfrac{3V}{4\pi}} \).

Example 2:

Make \( x \) the subject of \( y=3x+5x^2 \).

▶️ Answer/Explanation

Rearrange into quadratic form:

\( 5x^2+3x-y=0 \)

Now solve using the quadratic formula:

\( x=\dfrac{-3\pm\sqrt{3^2-4(5)(-y)}}{2(5)} \)

\( x=\dfrac{-3\pm\sqrt{9+20y}}{10} \)

Conclusion: \( x=\dfrac{-3\pm\sqrt{9+20y}}{10} \).

Example 3:

Make \( l \) the subject of \( T=2\pi\sqrt{\dfrac{l}{g}} \).

▶️ Answer/Explanation

Step 1: Divide both sides by \( 2\pi \).

\( \dfrac{T}{2\pi}=\sqrt{\dfrac{l}{g}} \)

Step 2: Square both sides.

\( \dfrac{T^2}{4\pi^2}=\dfrac{l}{g} \)

Step 3: Multiply by \( g \).

\( l=\dfrac{gT^2}{4\pi^2} \)

Conclusion: \( l=\dfrac{gT^2}{4\pi^2} \).

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