Edexcel iGCSE Physics -4.16–4.17 Power, Energy, and Time- Study Notes- New Syllabus

Edexcel iGCSE Physics -4.16–4.17 Power, Energy, and Time- Study Notes- New syllabus

Edexcel iGCSE Physics -4.16–4.17 Power, Energy, and Time- Study Notes -Edexcel iGCSE Physics – per latest Syllabus.

Key Concepts:

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Edexcel iGCSE Physics -Concise Summary Notes- All Topics

Power: Rate of Energy Transfer

Power describes how quickly energy is transferred or how quickly work is done. Two devices may transfer the same amount of energy, but the one that does it in a shorter time has a greater power.

Definition of Power

Power is defined as the rate of transfer of energy or the rate of doing work.

Power = energy transferred ÷ time taken

\( \mathrm{P = \dfrac{E}{t}} \)

Since work done equals energy transferred:

\( \mathrm{P = \dfrac{W}{t}} \)

  • \( \mathrm{P} \) = power (watt, W)
  • \( \mathrm{E} \) = energy transferred (joule, J)
  • \( \mathrm{W} \) = work done (joule, J)
  • \( \mathrm{t} \) = time taken (second, s)

1 watt is defined as 1 joule per second.

Understanding Power

  • High power means energy is transferred quickly.
  • Low power means energy is transferred slowly.
  • Power depends on both energy and time.

Example: A powerful motor lifts an object faster than a less powerful motor, even if both do the same work.

Power and Energy Transfer

  • Lifting objects → power depends on how fast the object is lifted.
  • Electrical appliances → power shows how quickly electrical energy is used.
  • Engines → higher power means faster acceleration or higher speed.

Key Idea

  • Power measures speed of energy transfer.
  • Same energy in less time means greater power.
  • Measured in watts.

Important Points to Remember

  • Power is not energy.
  • Always use joules and seconds.
  • Energy transferred = power × time.

Example

A machine transfers \( \mathrm{600\ J} \) of energy in \( \mathrm{12\ s} \).

Calculate the power of the machine.

▶️ Answer / Explanation

Use:

\( \mathrm{P = \dfrac{E}{t}} \)

\( \mathrm{P = \dfrac{600}{12}} \)

\( \mathrm{P = 50\ W} \)

Example

A student lifts a \( \mathrm{20\ kg} \) box vertically through a height of \( \mathrm{1.5\ m} \) in \( \mathrm{3.0\ s} \).

Calculate the power developed by the student. (Take \( \mathrm{g = 10\ N/kg} \).)

▶️ Answer / Explanation

First calculate work done:

\( \mathrm{W = mgh = 20 \times 10 \times 1.5 = 300\ J} \)

Now calculate power:

\( \mathrm{P = \dfrac{W}{t} = \dfrac{300}{3.0}} \)

\( \mathrm{P = 100\ W} \)

Relationship Between Power, Work Done and Time

Power tells us how quickly work is done or energy is transferred. When the same amount of work is done in a shorter time, the power is greater.

Key Relationship

The relationship between power, work done and time taken is:

\( \mathrm{power = \dfrac{work\ done}{time\ taken}} \)

\( \mathrm{P = \dfrac{W}{t}} \)

Since work done equals energy transferred:

\( \mathrm{P = \dfrac{E}{t}} \)

  • \( \mathrm{P} \) = power (watt, W)
  • \( \mathrm{W} \) = work done (joule, J)
  • \( \mathrm{E} \) = energy transferred (joule, J)
  • \( \mathrm{t} \) = time taken (second, s)

1 watt = 1 joule per second.

Understanding the Relationship

  • For a fixed amount of work, reducing time increases power.
  • For a fixed time, doing more work increases power.
  • High-power devices transfer energy quickly.

Rearranging the Formula

  • Work done: \( \mathrm{W = P \times t} \)
  • Time taken: \( \mathrm{t = \dfrac{W}{P}} \)

Applications

  • Comparing electrical appliances
  • Calculating engine performance
  • Estimating energy use over time

Key Idea

  • Power measures the rate of energy transfer.
  • Same energy transferred faster → greater power.
  • Power links energy and time.

Important Points to Remember

  • Always convert time to seconds.
  • Energy and work are both measured in joules.
  • Power is measured in watts.

Example

A motor does \( \mathrm{900\ J} \) of work in \( \mathrm{15\ s} \).

Calculate the power of the motor.

▶️ Answer / Explanation

Use:

\( \mathrm{P = \dfrac{W}{t}} \)

\( \mathrm{P = \dfrac{900}{15}} \)

\( \mathrm{P = 60\ W} \)

Example

An electric heater has a power rating of \( \mathrm{2.0\ kW} \).

Calculate the energy transferred when it is switched on for \( \mathrm{5.0\ minutes} \).

▶️ Answer / Explanation

Convert units:

\( \mathrm{2.0\ kW = 2000\ W} \)

\( \mathrm{5.0\ minutes = 300\ s} \)

Use:

\( \mathrm{E = P \times t} \)

\( \mathrm{E = 2000 \times 300} \)

\( \mathrm{E = 600\,000\ J} \)

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