Edexcel iGCSE Physics -5.5 Pressure, Force, and Area- Study Notes- New Syllabus

Edexcel iGCSE Physics -5.5 Pressure, Force, and Area- Study Notes- New syllabus

Edexcel iGCSE Physics -5.5 Pressure, Force, and Area- Study Notes -Edexcel iGCSE Physics – per latest Syllabus.

Key Concepts:

update

Edexcel iGCSE Physics -Concise Summary Notes- All Topics

Pressure, Force and Area

Pressure describes how concentrated a force is over a surface. A large force acting on a small area produces a high pressure, while the same force acting over a larger area produces a lower pressure.

Relationship Between Pressure, Force and Area

The relationship is:

\( \mathrm{pressure = \dfrac{force}{area}} \)

\( \mathrm{P = \dfrac{F}{A}} \)

  • \( \mathrm{P} \) = pressure (pascal, Pa)
  • \( \mathrm{F} \) = force (newton, N)
  • \( \mathrm{A} \) = area (square metre, m²)

1 pascal = 1 newton per square metre (N/m²).

Understanding the Relationship

  • For a constant force, decreasing the area increases pressure.
  • For a constant area, increasing the force increases pressure.
  • Pressure depends on both force and contact area.

Everyday examples:

  • Sharp knives cut better because they have a small contact area.
  • High-heeled shoes exert more pressure than flat shoes.
  • Snowshoes reduce pressure to prevent sinking into snow.

Rearranging the Formula

  • Force: \( \mathrm{F = P \times A} \)
  • Area: \( \mathrm{A = \dfrac{F}{P}} \)

Key Idea

  • Pressure is force per unit area.
  • Small area → high pressure.
  • Large area → low pressure.

Important Points to Remember

  • Area must be in m².
  • Force must be in newtons.
  • Pressure is measured in pascals.

Example

A force of \( \mathrm{600\ N} \) acts on an area of \( \mathrm{0.30\ m^2} \).

Calculate the pressure exerted.

▶️ Answer / Explanation

Use:

\( \mathrm{P = \dfrac{F}{A}} \)

\( \mathrm{P = \dfrac{600}{0.30}} \)

\( \mathrm{P = 2000\ Pa} \)

Example

A pressure of \( \mathrm{5.0 \times 10^4\ Pa} \) acts on an area of \( \mathrm{0.20\ m^2} \).

Calculate the force producing this pressure.

▶️ Answer / Explanation

Rearrange:

\( \mathrm{F = P \times A} \)

\( \mathrm{F = 5.0 \times 10^4 \times 0.20} \)

\( \mathrm{F = 1.0 \times 10^4\ N} \)

Scroll to Top