Edexcel International A Level (IAL) Chemistry (YCH11) - Unit 2 - 7.1 Types of intermolecular forces-Study Notes - New Syllabus

Edexcel International A Level (IAL) Chemistry (YCH22) -Unit 2 – 7.1 Types of intermolecular forces- Study Notes- New syllabus

Edexcel International A Level (IAL) Chemistry (YCH11) -Unit 2 – 7.1 Types of intermolecular forces- Study Notes -International A Level (IAL) Chemistry (YCH22) – per latest Syllabus.

Key Concepts:

7.1 understand the nature of the following intermolecular forces:
i London forces (instantaneous dipole-induced dipole)
ii permanent dipole–permanent dipole interactions
iii hydrogen bonds

Edexcel International A Level (IAL) Chemistry (YCH22) -Concise Summary Notes- All Topics

7.1 (i) London Forces (Instantaneous Dipole–Induced Dipole)

London forces are the weakest type of intermolecular force and are present in all molecules, especially in non-polar substances.

Definition

London forces arise from temporary fluctuations in electron distribution, which create instantaneous dipoles that induce dipoles in neighbouring molecules.

How They Arise (Step-by-Step)  

  • Electrons are constantly moving.
  • At any instant, electrons may be unevenly distributed.
  • This creates an instantaneous dipole.
  • This dipole induces a dipole in a neighbouring molecule.
  • Weak electrostatic attraction forms between them.

Key Features

  • Present in all molecules.
  • Only force in non-polar molecules.
  • Very weak compared to other intermolecular forces.
  • Strength increases with:
    • Number of electrons
    • Size of molecule (molar mass)
    • Surface area (long chains > compact molecules)

Examples

  • Noble gases: \( \mathrm{He, Ne, Ar} \)
  • Non-polar molecules: \( \mathrm{CH_4, Cl_2} \)

Effect on Physical Properties

  • Stronger London forces → higher boiling point.
  • Larger molecules have stronger forces → higher melting/boiling points.

Trend Example

  • \( \mathrm{CH_4 < C_2H_6 < C_3H_8} \) (increasing boiling point)
  • Due to increasing number of electrons → stronger London forces.

Therefore, London forces explain why even non-polar substances can exist as liquids or solids.

Example 1 :

Explain why iodine (\( \mathrm{I_2} \)) has a much higher boiling point than chlorine (\( \mathrm{Cl_2} \)).

▶️ Answer/Explanation

\( \mathrm{I_2} \) has more electrons than \( \mathrm{Cl_2} \).

Stronger London forces are formed.

More energy required to overcome these forces.

Therefore, higher boiling point.

Example 2 :

Explain why straight-chain alkanes have higher boiling points than branched isomers.

▶️ Answer/Explanation

Straight-chain molecules have larger surface area.

More contact between molecules → stronger London forces.

Branched molecules are more compact → weaker forces.

Therefore, lower boiling point for branched isomers.

7.1 (ii) Permanent Dipole–Permanent Dipole Interactions

Permanent dipole–dipole interactions occur between polar molecules that have a permanent separation of charge.

Definition

These are electrostatic attractions between the δ⁺ (partial positive) end of one molecule and the δ⁻ (partial negative) end of another molecule.

How They Arise

  • Occur in molecules with polar bonds.
  • Due to difference in electronegativity between atoms.IB DP Chemistry - S2.2.8 Intermolecular forces- Study Notes
  • If molecule is asymmetrical → permanent dipole forms.

Example

  • \( \mathrm{HCl} \):
    • H = δ⁺, Cl = δ⁻
    • Molecules attract via dipole–dipole forces.

Key Features

  • Occur only in polar molecules.
  • Stronger than London forces (for similar size molecules).
  • Weaker than hydrogen bonding.

Conditions for Occurrence

  • Molecule must have:
    • Polar bonds
    • Asymmetrical shape (net dipole)

Effect on Physical Properties

  • Stronger intermolecular forces → higher boiling point.
  • Polar molecules generally have higher boiling points than non-polar molecules of similar size.

Comparison Example

  • \( \mathrm{HCl} \) vs \( \mathrm{Cl_2} \)
  • \( \mathrm{HCl} \): dipole–dipole + London forces
  • \( \mathrm{Cl_2} \): only London forces
  • Therefore, \( \mathrm{HCl} \) has stronger intermolecular forces.

Therefore, permanent dipole–dipole interactions explain why polar molecules have stronger intermolecular attractions than non-polar ones.

Example 1:

Explain why \( \mathrm{HCl} \) has a higher boiling point than \( \mathrm{Cl_2} \), even though they have similar molar masses.

▶️ Answer/Explanation

\( \mathrm{HCl} \) is polar and has permanent dipole–dipole interactions.

\( \mathrm{Cl_2} \) is non-polar and only has London forces.

Dipole–dipole forces are stronger.

Therefore, \( \mathrm{HCl} \) has a higher boiling point.

Example 2:

Explain why \( \mathrm{CO_2} \) does not exhibit permanent dipole–dipole interactions, despite having polar bonds.

▶️ Answer/Explanation

\( \mathrm{CO_2} \) has polar C=O bonds.

Molecule is linear and symmetrical.

Dipoles cancel out.

Therefore, no permanent dipole exists.

7.1 (iii) Hydrogen Bonding

Hydrogen bonding is a strong type of intermolecular force that occurs in molecules containing hydrogen bonded to highly electronegative atoms.

Definition

A hydrogen bond is the strong electrostatic attraction between a hydrogen atom (δ⁺), covalently bonded to a highly electronegative atom (N, O, or F), and a lone pair of electrons on another N, O, or F atom.

Conditions for Hydrogen Bonding

  • Hydrogen must be bonded to:
    • \( \mathrm{N} \), \( \mathrm{O} \), or \( \mathrm{F} \)
  • Presence of lone pair on neighbouring molecule

Examples

  • Water: \( \mathrm{H_2O} \)
  • Ammonia: \( \mathrm{NH_3} \)
  • Hydrogen fluoride: \( \mathrm{HF} \)

How It Arises

  • N, O, F are highly electronegative.
  • Bond with H becomes highly polar.
  • H becomes strongly δ⁺.
  • Strong attraction forms with lone pair on nearby molecule.

Key Features

  • Stronger than dipole–dipole interactions.
  • Still weaker than covalent bonds.
  • Directional (specific orientation required).

Effect on Physical Properties

  • Much higher boiling points.
  • Increased viscosity.
  • Greater solubility in water.

Important Example

  • \( \mathrm{H_2O} \) has unusually high boiling point.
  • Due to extensive hydrogen bonding network.

Comparison with Other Forces

  • London forces < Dipole–dipole < Hydrogen bonding

Therefore, hydrogen bonding plays a crucial role in determining the physical properties of many important substances.

Example 1 :

Explain why water has a much higher boiling point than methane (\( \mathrm{CH_4} \)).

▶️ Answer/Explanation

Water forms hydrogen bonds between molecules.

Methane only has London forces.

Hydrogen bonds are much stronger.

Therefore, more energy is required to separate water molecules.

Example 2:

Explain why hydrogen chloride (\( \mathrm{HCl} \)) does not form hydrogen bonds.

▶️ Answer/Explanation

Hydrogen bonding requires H bonded to N, O, or F.

Chlorine is less electronegative than these elements.

Therefore, HCl does not form strong hydrogen bonds.

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