Edexcel International A Level (IAL) Chemistry (YCH11) - Unit 2 - 7.4 Predicting hydrogen bonding-Study Notes - New Syllabus

Edexcel International A Level (IAL) Chemistry (YCH11) -Unit 2 – 7.4 Predicting hydrogen bonding- Study Notes- New syllabus

Edexcel International A Level (IAL) Chemistry (YCH11) -Unit 2 – 7.4 Predicting hydrogen bonding- Study Notes -International A Level (IAL) Chemistry (YCH11) – per latest Syllabus.

Key Concepts:

7.4 be able to predict the presence of hydrogen bonding in molecules analogous to those mentioned in 7.2

Edexcel International A Level (IAL) Chemistry (YCH11) -Concise Summary Notes- All Topics

7.4 Predicting Hydrogen Bonding in Molecules

To predict whether a molecule shows hydrogen bonding, you must check for specific structural features similar to \( \mathrm{H_2O} \), \( \mathrm{NH_3} \), and \( \mathrm{HF} \).

Essential Conditions

 

  • Hydrogen must be directly bonded to:
    • \( \mathrm{N} \), \( \mathrm{O} \), or \( \mathrm{F} \)
  • A neighbouring molecule must have:
    • A lone pair on \( \mathrm{N} \), \( \mathrm{O} \), or \( \mathrm{F} \)

Prediction Rule 

If a molecule contains H–N, H–O, or H–F bonds, it can form hydrogen bonds.

Examples That DO Show Hydrogen Bonding

  • \( \mathrm{CH_3OH} \) (methanol) → contains O–H
  • \( \mathrm{C_2H_5OH} \) (ethanol) → contains O–H
  • \( \mathrm{CH_3NH_2} \) (methylamine) → contains N–H
  • \( \mathrm{HF} \) → contains H–F

Examples That DO NOT Show Hydrogen Bonding

  • \( \mathrm{CH_4} \) → no N, O, F
  • \( \mathrm{HCl} \) → H–Cl not strong enough
  • \( \mathrm{CH_3OCH_3} \) → has O but no O–H bond

Important Insight

  • Having N, O, or F alone is not enough.
  • Must have H directly bonded to them.

Intermolecular vs Intramolecular

  • Usually intermolecular (between molecules).
  • Occasionally intramolecular (within same molecule).

Effect on Properties

  • Higher boiling points.
  • Greater solubility in water.

Step-by-Step Prediction Method

  • Step 1: Look for N, O, or F.
  • Step 2: Check if H is bonded to them.
  • Step 3: Confirm presence of lone pairs.
  • Step 4: Conclude hydrogen bonding possible.

Therefore, hydrogen bonding can be predicted by identifying specific bonding patterns in molecules.

Example 1:

Which of the following molecules can form hydrogen bonds: \( \mathrm{CH_3OH} \), \( \mathrm{CH_3Cl} \), \( \mathrm{NH_3} \)? Explain.

▶️ Answer/Explanation

\( \mathrm{CH_3OH} \): yes (O–H bond).

\( \mathrm{NH_3} \): yes (N–H bond).

\( \mathrm{CH_3Cl} \): no (no H–N/O/F bond).

Example 2:

Explain why ethanol has a higher boiling point than dimethyl ether (\( \mathrm{CH_3OCH_3} \)).

▶️ Answer/Explanation

Ethanol has O–H bonds → hydrogen bonding.

Dimethyl ether lacks O–H bonds.

Only weaker intermolecular forces present.

Therefore, ethanol has stronger intermolecular forces and higher boiling point.

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