Edexcel International A Level (IAL) Chemistry (YCH11) - Unit 2 - 8.6 Oxidising and reducing agents-Study Notes - New Syllabus

Edexcel International A Level (IAL) Chemistry (YCH11) -Unit 2 – 8.6 Oxidising and reducing agents- Study Notes- New syllabus

Edexcel International A Level (IAL) Chemistry (YCH11) -Unit 2 – 8.6 Oxidising and reducing agents- Study Notes -International A Level (IAL) Chemistry (YCH11) – per latest Syllabus.

Key Concepts:

8.6 know that oxidising agents gain electrons and reducing agents lose electrons

Edexcel International A Level (IAL) Chemistry (YCH11) -Concise Summary Notes- All Topics

8.6 Oxidising Agents and Reducing Agents

In redox reactions, substances can act as oxidising agents or reducing agents depending on whether they gain or lose electrons.

Oxidising agent:

  • A substance that gains electrons.
  • It causes another substance to be oxidised.

Reducing agent:

  • A substance that loses electrons.
  • It causes another substance to be reduced.

Key Relationships

  • Oxidising agent is reduced.
  • Reducing agent is oxidised.

Example 1

\( \mathrm{2Na + Cl_2 \rightarrow 2NaCl} \)

  • Na → \( \mathrm{Na^+ + e^-} \) (loses electrons) → reducing agent
  • \( \mathrm{Cl_2 + 2e^- \rightarrow 2Cl^-} \) (gains electrons) → oxidising agent

Example 2

\( \mathrm{Mg + Cu^{2+} \rightarrow Mg^{2+} + Cu} \)

  • Mg loses electrons → reducing agent
  • \( \mathrm{Cu^{2+}} \) gains electrons → oxidising agent

Using Oxidation Numbers

  • Oxidising agent → oxidation number decreases.
  • Reducing agent → oxidation number increases.

Key Points

  • Oxidising agents gain electrons.
  • Reducing agents lose electrons.
  • Both occur together in a redox reaction.
  • Can also be identified using oxidation numbers.

Therefore, identifying oxidising and reducing agents is essential for analysing redox reactions.

Example 1:

Identify the oxidising and reducing agents in the reaction:

\( \mathrm{Zn + Fe^{2+} \rightarrow Zn^{2+} + Fe} \)

▶️ Answer/Explanation

Zn loses electrons → reducing agent.

\( \mathrm{Fe^{2+}} \) gains electrons → oxidising agent.

Example 2 :

Using oxidation numbers, identify the oxidising agent in the reaction:

\( \mathrm{Cl_2 + 2Br^- \rightarrow 2Cl^- + Br_2} \)

▶️ Answer/Explanation

Cl: \( 0 \rightarrow -1 \) (reduction)

Therefore, \( \mathrm{Cl_2} \) is the oxidising agent.

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