Edexcel International A Level (IAL) Chemistry (YCH11) - Unit 4 - 14.8 Ka expression-Study Notes - New Syllabus
Edexcel International A Level (IAL) Chemistry (YCH11) -Unit 4 – 14.8 Ka expression- Study Notes- New syllabus
Edexcel International A Level (IAL) Chemistry (YCH11) -Unit 4 – 14.8 Ka expression- Study Notes -International A Level (IAL) Chemistry (YCH11) – per latest Syllabus.
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Edexcel International A Level (IAL) Chemistry (YCH11) -Concise Summary Notes- All Topics
14.8 Acid Dissociation Constant (\( \mathrm{K_a} \)) for a Weak Acid
The acid dissociation constant, \( \mathrm{K_a} \), is an equilibrium constant that measures the extent to which a weak acid dissociates in aqueous solution. It is derived directly from the equilibrium expression for the ionisation of a weak acid.
Step 1: Write the Dissociation Equation
For a weak acid \( \mathrm{HA} \):
\( \mathrm{HA(aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + A^-(aq)} \)
(Water is often omitted for simplicity):
\( \mathrm{HA(aq) \rightleftharpoons H^+(aq) + A^-(aq)} \)
Step 2: Write the Equilibrium Expression
Applying the general expression for equilibrium constants:
\( \mathrm{K_c = \frac{[H^+][A^-]}{[HA]}} \)
Step 3: Define \( \mathrm{K_a} \)
Since water is a pure liquid and its concentration is constant, it is omitted. The equilibrium constant is therefore called the acid dissociation constant, \( \mathrm{K_a} \):
\( \mathrm{K_a = \frac{[H^+][A^-]}{[HA]}} \)
Key Features of \( \mathrm{K_a} \)
- Applies only to weak acids.
- Derived from an equilibrium expression.
- Does not include water.
- Units depend on concentration powers (typically \( \mathrm{mol\ dm^{-3}} \)).
Interpretation of \( \mathrm{K_a} \)
- Large \( \mathrm{K_a} \) → greater dissociation → stronger acid.
- Small \( \mathrm{K_a} \) → less dissociation → weaker acid.
Alternative Form (using \( \mathrm{H_3O^+} \))
\( \mathrm{K_a = \frac{[H_3O^+][A^-]}{[HA]}} \)
Both forms are acceptable.
Key Features
- \( \mathrm{K_a} \) is derived from equilibrium of weak acid dissociation.
- Water is omitted from the expression.
- Indicates strength of a weak acid.
- Larger \( \mathrm{K_a} \) means stronger acid.
Example 1:
Deduce the expression for \( \mathrm{K_a} \) for ethanoic acid, \( \mathrm{CH_3COOH} \).
▶️ Answer/Explanation
Dissociation:
\( \mathrm{CH_3COOH \rightleftharpoons H^+ + CH_3COO^-} \)
Therefore:
\( \mathrm{K_a = \frac{[H^+][CH_3COO^-]}{[CH_3COOH]}} \)
Example 2:
Explain what a small value of \( \mathrm{K_a} \) indicates about a weak acid.
▶️ Answer/Explanation
A small \( \mathrm{K_a} \) means that the equilibrium lies far to the left.
Only a small proportion of the acid dissociates.
Therefore, the acid is weak.
