Edexcel International A Level (IAL) Chemistry (YCH11) - Unit 4 - 15.8 Reactions of carbonyls-Study Notes - New Syllabus

Edexcel International A Level (IAL) Chemistry (YCH11) – Unit 4 – 15.8 Reactions of carbonyls-Study Notes- New syllabus

Edexcel International A Level (IAL) Chemistry (YCH11) – Unit 4 – 15.8 Reactions of carbonyls-Study Notes -International A Level (IAL) Chemistry (YCH11) – per latest Syllabus.

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Edexcel International A Level (IAL) Chemistry (YCH11) -Concise Summary Notes- All Topics

15.8 Reactions of Carbonyl Compounds

(i) Reactions with Fehling’s/Benedict’s Solution, Tollens’ Reagent and Acidified Dichromate(VI)

Aldehydes are readily oxidised because the carbonyl carbon is bonded to a hydrogen atom. Ketones are generally resistant to oxidation under mild conditions.

Aldehydes

  • Oxidised to carboxylic acids.
  • Positive results with oxidation tests.

Ketones

  • Not oxidised by mild oxidising agents.
  • Negative results with these tests.

1. Fehling’s Solution / Benedict’s Solution

Reagent

  • Alkaline copper(II) solution.

Observation with Aldehydes

  • Blue solution forms a:

Brick-red precipitate

due to formation of \( \mathrm{Cu_2O} \).

Observation with Ketones

  • No change.

General Oxidation Equation

\( \mathrm{RCHO + [O] \rightarrow RCOOH} \)

2. Tollens’ Reagent

Reagent

  • Ammoniacal silver nitrate solution.

Observation with Aldehydes

  • Formation of a:

Silver mirror

due to deposition of silver metal.

Observation with Ketones

  • No reaction.

Importance

  • Distinguishes aldehydes from ketones.

3. Acidified Dichromate(VI) Ions

Reagent

  • \( \mathrm{K_2Cr_2O_7/H^+} \)

Observation with Aldehydes

  • Orange solution changes to:

Green

Observation with Ketones

  • No change.

Oxidation Equation

\( \mathrm{RCHO + [O] \rightarrow RCOOH} \)

Why Ketones Resist Oxidation

  • No hydrogen attached directly to carbonyl carbon.
  • Oxidation would require breaking C–C bonds.

(ii) Reduction with Lithium Tetrahydridoaluminate(III)

Reagent

\( \mathrm{LiAlH_4} \) in dry ether (ethoxyethane)

\( \mathrm{LiAlH_4} \) is a strong reducing agent supplying hydride ions (\( \mathrm{H^-} \)).

In equations, reduction may be represented by:

\( \mathrm{[H]} \)

Reduction of Aldehydes

  • Aldehydes are reduced to:

Primary alcohols

General Equation

\( \mathrm{RCHO + 2[H] \rightarrow RCH_2OH} \)

Example

\( \mathrm{CH_3CHO + 2[H] \rightarrow CH_3CH_2OH} \)

Reduction of Ketones

  • Ketones are reduced to:

Secondary alcohols

General Equation

\( \mathrm{RCOR’ + 2[H] \rightarrow RCH(OH)R’} \)

Example

\( \mathrm{CH_3COCH_3 + 2[H] \rightarrow CH_3CH(OH)CH_3} \)

Conditions

  • Dry ether solvent required because \( \mathrm{LiAlH_4} \) reacts violently with water.

Summary Table

ReactionAldehydeKetone
Fehling’s/Benedict’sBrick-red precipitateNo reaction
Tollens’ reagentSilver mirrorNo reaction
Acidified dichromate(VI)Orange → greenNo reaction
\( \mathrm{LiAlH_4} \)Primary alcoholSecondary alcohol

Key Features

  • Aldehydes are easily oxidised.
  • Ketones resist mild oxidation.
  • \( \mathrm{LiAlH_4} \) reduces carbonyl compounds to alcohols.
  • Oxidation tests distinguish aldehydes from ketones.

Example 1:

Compound X gives a silver mirror with Tollens’ reagent and forms a green solution with acidified dichromate(VI). Identify the functional group present.

▶️ Answer/Explanation

The compound is oxidised by both reagents.

This behaviour is characteristic of an aldehyde.

Therefore, compound X contains an aldehyde group.

Example 2:

State the product formed when propanone is reduced using \( \mathrm{LiAlH_4} \).

▶️ Answer/Explanation

Propanone is a ketone.

Reduction converts ketones into secondary alcohols.

Product:

\( \mathrm{propan\text{-}2\text{-}ol} \)

(iii) Reaction with HCN in the Presence of KCN

Aldehydes and ketones undergo nucleophilic addition reactions with hydrogen cyanide, \( \mathrm{HCN} \), to form hydroxynitriles.

Role of Reagents

  • \( \mathrm{KCN} \) provides the nucleophile:

\( \mathrm{CN^-} \)

  • \( \mathrm{HCN} \) provides \( \mathrm{H^+} \).

Why Carbonyl Compounds React

  • Carbonyl bond is polar.
  • Oxygen is more electronegative than carbon.

\( \mathrm{C^{\delta +}=O^{\delta -}} \)

Therefore, the carbonyl carbon is electrophilic.

Mechanism (Nucleophilic Addition)

Step 1: Nucleophilic Attack

  • Lone pair on \( \mathrm{CN^-} \) attacks carbonyl carbon.
  • \( \mathrm{\pi} \)-bond electrons move to oxygen.

Step 2: Protonation

  • Alkoxide ion gains \( \mathrm{H^+} \) from HCN.
  • Hydroxynitrile forms.

General Equation

\( \mathrm{RCHO + HCN \rightarrow RCH(OH)CN} \)

Example

\( \mathrm{CH_3CHO + HCN \rightarrow CH_3CH(OH)CN} \)

Optical Activity Evidence

  • Carbonyl carbon is planar.
  • \( \mathrm{CN^-} \) can attack from either side equally.
  • If a chiral centre forms, both enantiomers form.
  • Product becomes a racemic mixture.

(iv) Reaction with 2,4-Dinitrophenylhydrazine (2,4-DNPH)

2,4-DNPH is used as a qualitative test for aldehydes and ketones.

Purpose of the Test

  • Detect presence of carbonyl group.
  • Identify unknown carbonyl compounds using melting point data.

Observation

  • Formation of an:

Orange precipitate

due to formation of a 2,4-dinitrophenylhydrazone derivative.

Importance of Melting Point

  • Different derivatives have different melting points.
  • Measured melting point compared with data table to identify compound.

Limitations

  • Cannot distinguish aldehydes from ketones.
  • Only confirms carbonyl group presence.

(v) Iodoform Test

The iodoform test identifies compounds containing the:

\( \mathrm{CH_3CO-} \)

group.

Reagents

  • Iodine
  • Aqueous alkali (e.g. NaOH)

Positive Result

  • Formation of a:

Yellow precipitate

of iodoform:

\( \mathrm{CHI_3} \)

Compounds Giving Positive Test

  • Ethanal
  • Methyl ketones
  • Secondary alcohols containing:

\( \mathrm{CH_3CH(OH)-} \)

Reason

  • These compounds can form the \( \mathrm{CH_3CO-} \) group under reaction conditions.

Example

\( \mathrm{CH_3COCH_3} \) gives positive iodoform test.

Summary Table

ReagentPositive ObservationPurpose
\( \mathrm{HCN/KCN} \)Hydroxynitrile formedNucleophilic addition
2,4-DNPHOrange precipitateDetect carbonyl group
Iodine/alkaliYellow \( \mathrm{CHI_3} \) precipitateDetect \( \mathrm{CH_3CO-} \) group

Key Features

  • \( \mathrm{HCN} \) reactions proceed by nucleophilic addition.
  • Planar carbonyl groups can produce racemic mixtures.
  • 2,4-DNPH detects aldehydes and ketones.
  • Iodoform test identifies methyl ketones and ethanal.

Example 1:

Explain why addition of HCN to ethanal produces a racemic mixture.

▶️ Answer/Explanation

The carbonyl carbon in ethanal is planar.

\( \mathrm{CN^-} \) can attack from either side equally.

A chiral centre forms, producing both enantiomers in equal amounts.

Therefore, a racemic mixture is formed.

Example 2:

Compound X forms an orange precipitate with 2,4-DNPH and a yellow precipitate with iodine in alkali. Suggest a possible functional group present.

▶️ Answer/Explanation

The 2,4-DNPH test shows a carbonyl compound is present.

Positive iodoform test indicates a \( \mathrm{CH_3CO-} \) group.

Therefore, compound X is likely a methyl ketone.

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