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Edexcel A Level (IAL) Physics-1.31 Core Practical 3: Investigating Young Modulus- Study Notes- New Syllabus

Edexcel A Level (IAL) Physics -1.31 Core Practical 3: Investigating Young Modulus- Study Notes- New syllabus

Edexcel A Level (IAL) Physics -1.31 Core Practical 3: Investigating Young Modulus- Study Notes -Edexcel A level Physics – per latest Syllabus.

Key Concepts:

  • 1.31 Determine the Young modulus of a material

Edexcel A level Physics-Study Notes- All Topics

CORE PRACTICAL 3: Determine the Young Modulus of a Material

This practical measures how much a material (usually a wire) extends when forces are applied, and uses stress–strain relationships to calculate the Young modulus.

Aim

To determine the Young modulus \( E \) of a material using the relationship:

$ E = \frac{\text{stress}}{\text{strain}} = \frac{F L_0}{A \Delta L} $

Apparatus

  • Long test wire (e.g., nichrome)
  • Micrometer screw gauge (to measure wire diameter)
  • Metre ruler or measuring scale
  • Clamps and stand
  • Pointer attached to the wire
  • Masses and mass hanger (to apply known force)
  • Reference wire (to eliminate support movement)
  • Vernier scale / travelling microscope (for precision)

Theory

The wire obeys:

$ \text{stress} = \frac{F}{A}, \quad \text{strain} = \frac{\Delta L}{L_0} $

So the Young modulus is:

$ E = \frac{F L_0}{A \Delta L} $

  • \( F = mg \) is the applied force
  • \( L_0 \) = original length of wire
  • \( \Delta L \) = extension
  • \( A = \pi r^2 \) = cross-sectional area

Procedure

  1. Measure diameter of wire at several points using a micrometer. Take an average radius \( r \).
  2. Secure the wire firmly at the top clamp. Attach a pointer at the bottom near the scale.
  3. Measure the initial length \( L_0 \) of the wire from the clamp to the pointer.
  4. Set up a second reference wire alongside to compensate for stand movement.
  5. Hang a mass hanger on the test wire and add masses gently.
  6. Record extension \( \Delta L \) for each added mass using the pointer scale.
  7. Repeat readings at least three times for accuracy.
  8. Plot a graph of F (y-axis) against extension ΔL (x-axis).

Data Processing

The graph should be linear in the elastic region.

  • The gradient gives stiffness \( k \):

    \( k = \frac{F}{\Delta L} \)

  • The Young modulus can be calculated using:

    $ E = \frac{F L_0}{A \Delta L} $

Assumptions

  • The wire obeys Hooke’s Law (within elastic limit).
  • The wire is of uniform diameter.
  • Temperature remains constant.
  • No slipping occurs at the clamp.
  • Extensions are small compared to original length.

Sources of Error

  • Parallax error in reading pointer scale.
  • Wire not perfectly vertical.
  • Diameter of wire varies along its length.
  • Wire may have initial kinks.
  • Stand may move slightly (corrected using reference wire).
  • Temperature changes can affect elasticity.

How to Improve Accuracy

  • Use a travelling microscope to measure extension precisely.
  • Use a long wire to reduce percentage errors in extension.
  • Repeat diameter measurements in multiple orientations.
  • Use small mass increments to avoid overshooting elastic limit.
  • Plot a best-fit line on the F–ΔL graph.

Example

A 2.00 m wire of radius \( 0.25\, \mathrm{mm} \) extends by \( 0.75\, \mathrm{mm} \) when a mass of \( 1.50\, \mathrm{kg} \) is added. Calculate the Young modulus.

▶️ Answer / Explanation

Cross-sectional area:

\( A = \pi r^2 = \pi (0.00025)^2 = 1.96\times10^{-7}\, \mathrm{m^2} \)

Force applied:

\( F = mg = 1.50 \times 9.8 = 14.7\, \mathrm{N} \)

Extension:

\( \Delta L = 0.75\,\mathrm{mm} = 7.5\times10^{-4}\,\mathrm{m} \)

Substitute into formula:

$ E = \frac{F L_0}{A \Delta L} = \frac{14.7 \times 2.00}{(1.96\times10^{-7})(7.5\times10^{-4})} $

\( E \approx 2.0\times10^{11}\, \mathrm{Pa} \)

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