Home / Edexcel A Level / A Level (IAL) Physics (YPH11) / 2.8 Phase & Path Difference- Study Notes

Edexcel A Level (IAL) Physics-2.8 Phase & Path Difference- Study Notes- New Syllabus

Edexcel A Level (IAL) Physics -2.8 Phase & Path Difference- Study Notes- New syllabus

Edexcel A Level (IAL) Physics -2.8 Phase & Path Difference- Study Notes -Edexcel A level Physics – per latest Syllabus.

Key Concepts:

  • be able to use the relationship between phase difference and path difference

Edexcel A level Physics-Study Notes- All Topics

Relationship Between Phase Difference and Path Difference

The phase difference between two waves tells us how far “out of step” they are in a cycle. The path difference tells us how much further one wave has travelled compared to the other. These two quantities are directly related.

 Key Relationship

The phase difference \( \phi \) (in radians) is related to the path difference \( \Delta x \) by:

$ \phi = \frac{2\pi}{\lambda}\,\Delta x $

  • \( \phi \) = phase difference (radians)
  • \( \Delta x \) = path difference (m)
  • \( \lambda \) = wavelength (m)

Meaning:

  • One full wavelength → \( \Delta x = \lambda \) → \( \phi = 2\pi \).
  • Half wavelength → \( \Delta x = \lambda/2 \) → \( \phi = \pi \).
  • Quarter wavelength → \( \Delta x = \lambda/4 \) → \( \phi = \pi/2 \).

For Constructive and Destructive Interference

Constructive interference (waves in phase):

$ \Delta x = n\lambda,\quad \phi = 2\pi n $

Destructive interference (waves \( 180^\circ \) out of phase):

$ \Delta x = (n+\tfrac12)\lambda,\quad \phi = (2n+1)\pi $

Rearranged Form

Sometimes we know the phase difference and need the path difference:

$ \Delta x = \frac{\phi\,\lambda}{2\pi} $

Key Notes

  • Phase difference is dimensionless (measured in radians).
  • Phase difference determines interference pattern brightness/visibility.
  • Waves must be coherent for stable phase differences.

Example (Easy)

A path difference of one full wavelength occurs between two waves. What is the phase difference?

▶️ Answer / Explanation

If \( \Delta x = \lambda \), $ \phi = \frac{2\pi}{\lambda}\lambda = 2\pi $ The phase difference is \( 2\pi \) radians.

Example (Medium)

Two waves meet with a phase difference of \( \pi \). What is the corresponding path difference?

▶️ Answer / Explanation

$ \Delta x = \frac{\phi\lambda}{2\pi} = \frac{\pi\lambda}{2\pi} = \frac{\lambda}{2} $

The path difference is \( \lambda/2 \).

Example (Hard)

Two coherent waves arrive at a point having travelled paths differing by \( 3.0\,\mathrm{mm} \). The wavelength is \( 8.0\,\mathrm{mm} \). Find the phase difference.

▶️ Answer / Explanation

$ \phi = \frac{2\pi}{\lambda}\Delta x = \frac{2\pi}{8.0}\times 3.0 $

$ \phi = \frac{6\pi}{8} = \frac{3\pi}{4} $

Phase difference = \( 0.75\pi \,\text{rad} \)

Scroll to Top