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Edexcel A Level (IAL) Physics-5.9 Nuclear Binding Energy & Mass Deficit- Study Notes- New Syllabus

Edexcel A Level (IAL) Physics -5.9 Nuclear Binding Energy & Mass Deficit- Study Notes- New syllabus

Edexcel A Level (IAL) Physics -5.9 Nuclear Binding Energy & Mass Deficit- Study Notes -Edexcel A level Physics – per latest Syllabus.

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Edexcel A level Physics-Study Notes- All Topics

Nuclear Binding Energy and Using \( \Delta E = c^2 \Delta m \)

Nuclear binding energy is the energy required to completely separate a nucleus into its individual protons and neutrons. It is a measure of how strongly the nucleons are bound together.

 Mass Defect

The mass of a nucleus is less than the total mass of its separate nucleons. This difference is called the mass defect.

\( \Delta m = (\text{total mass of separate nucleons}) – (\text{mass of nucleus}) \)

  • \( \Delta m \) = mass defect (kg or u)
  • Occurs because energy is released when the nucleus forms

Key idea: Mass is converted into energy during nuclear formation.

Nuclear Binding Energy

The nuclear binding energy is the energy equivalent of the mass defect:

\( \Delta E = c^2 \Delta m \)

  • \( \Delta E \) = binding energy (J)
  • \( c \) = speed of light \( (3.00\times10^8\ \mathrm{m\,s^{-1}}) \)
  • \( \Delta m \) = mass defect (kg)

This equation shows that a small mass defect corresponds to a very large energy.

Meaning of Binding Energy

  • Large binding energy → very stable nucleus
  • Small binding energy → less stable nucleus
  • Energy must be supplied to break the nucleus apart

Binding energy per nucleon is often used to compare stability:

\( \text{binding energy per nucleon} = \dfrac{\text{total binding energy}}{\text{number of nucleons}} \)

Using \( \Delta E = c^2 \Delta m \) in Calculations

Typical steps:

  1. Calculate total mass of separate protons and neutrons.
  2. Subtract the nuclear mass to find \( \Delta m \).
  3. Convert mass units to kg if necessary.
  4. Use \( \Delta E = c^2 \Delta m \) to find energy.

Useful conversion:

\( 1\ \mathrm{u} = 1.66\times10^{-27}\ \mathrm{kg} \)

Importance in Nuclear Reactions

  • Fusion: light nuclei combine → mass defect → energy released
  • Fission: heavy nucleus splits → mass defect → energy released
  • Energy output of nuclear power stations
  • Energy produced in stars

Example (Easy)

A nucleus has a mass defect of \( 2.0\times10^{-28}\ \mathrm{kg} \). Calculate its binding energy.

▶️ Answer / Explanation

\( \Delta E = c^2 \Delta m = (3.00\times10^8)^2 \times 2.0\times10^{-28} \)

\( \Delta E = 1.8\times10^{-11}\ \mathrm{J} \)

Example (Medium)

The mass defect of a nucleus is \( 0.030\ \mathrm{u} \). Calculate the binding energy.

▶️ Answer / Explanation

Convert to kg:

\( \Delta m = 0.030 \times 1.66\times10^{-27} = 4.98\times10^{-29}\ \mathrm{kg} \)

Calculate energy:

\( \Delta E = (3.00\times10^8)^2 \times 4.98\times10^{-29} \)

\( \Delta E = 4.48\times10^{-12}\ \mathrm{J} \)

Example (Hard)

Explain why energy is released during nuclear fusion using the concept of mass defect.

▶️ Answer / Explanation
  • The mass of the fused nucleus is less than the total mass of the original nuclei.
  • The missing mass is the mass defect.
  • This mass is converted into energy using \( \Delta E = c^2 \Delta m \).
  • The energy released appears as kinetic energy and radiation.
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