Home / Edexcel A Level / Study notes

Edexcel IAL - Further Pure Mathematics 1- 1.1 Definition of Complex Numbers; Polar Form- Study notes  - New syllabus

Edexcel IAL – Further Pure Mathematics 1- 1.1 Definition of Complex Numbers; Polar Form -Study notes- New syllabus

Edexcel IAL – Further Pure Mathematics 1 – 1.1 Definition of Complex Numbers; Polar Form -Study notes -Edexcel A level Maths – per latest Syllabus.

Key Concepts:

  • 1.1 Definition of Complex Numbers; Polar Form

Edexcel IAL Maths-Study Notes- All Topics

Complex Numbers

A complex number is a number of the form:

\( z = a + ib \)

where:

  • \( a \) is the real part
  • \( b \) is the imaginary part
  • \( i \) is the imaginary unit with \( i^2 = -1 \)

Polar (Trigonometric) Form

A complex number can also be written as:

\( z = r(\cos\theta + i\sin\theta) \)

where:

  • \( r \) is the modulus
  • \( \theta \) is the argument

Key Definitions

TermMeaning
Real part\( \text{Re}(z) = a \)
Imaginary part\( \text{Im}(z) = b \)
Conjugate\( \overline{z} = a – ib \)
Modulus\( |z| = \sqrt{a^2 + b^2} \)
Argument\( \theta = \tan^{-1}\!\left(\dfrac{b}{a}\right) \)

Equality of Complex Numbers

Two complex numbers are equal if and only if their real parts and imaginary parts are equal.

If \( a + ib = c + id \), then \( a = c \) and \( b = d \).

Example 

Let \( z = 3 + 4i \). Find its real part, imaginary part, modulus, and conjugate.

▶️ Answer / Explanation

\( \text{Re}(z) = 3 \)

\( \text{Im}(z) = 4 \)

\( |z| = \sqrt{3^2 + 4^2} = 5 \)

\( \overline{z} = 3 – 4i \)

Example

Write the complex number \( z = -1 + \sqrt{3}i \) in the form \( r(\cos\theta + i\sin\theta) \).

▶️ Answer / Explanation

Modulus:

\( r = \sqrt{(-1)^2 + (\sqrt{3})^2} = \sqrt{4} = 2 \)

Argument:

\( \theta = \tan^{-1}\!\left(\dfrac{\sqrt{3}}{-1}\right) \)

The number lies in the second quadrant, so:

\( \theta = \dfrac{2\pi}{3} \)

Therefore:

\( z = 2(\cos\dfrac{2\pi}{3} + i\sin\dfrac{2\pi}{3}) \)

Example

If \( z = x + yi \) and \( \overline{z} = 3 – 2i \), find \( x \) and \( y \).

▶️ Answer / Explanation

Since \( \overline{z} = x – yi \), compare with \( 3 – 2i \):

\( x = 3 \), \( -y = -2 \Rightarrow y = 2 \)

So \( z = 3 + 2i \).

Scroll to Top