Home / Edexcel A Level / Study notes

Edexcel IAL - Further Pure Mathematics 2- 5.1 Linear Second Order Differential Equations- Study notes  - New syllabus

Edexcel IAL – Further Pure Mathematics 2- 5.1 Linear Second Order Differential Equations -Study notes- New syllabus

Edexcel IAL – Further Pure Mathematics 2- 5.1 Linear Second Order Differential Equations -Study notes -Edexcel A level Maths- per latest Syllabus.

Key Concepts:

  • 5.1 Linear Second Order Differential Equations

Edexcel IAL Maths-Study Notes- All Topics

Linear Second Order Differential Equationst

A linear second order differential equation has the form

\( a\dfrac{d^2y}{dx^2} + b\dfrac{dy}{dx} + cy = f(x) \)

where \( a, b, c \) are real constants and \( f(x) \) is a given function of \( x \).

The solution consists of two parts:

  • Complementary function (CF): solves the homogeneous equation \( ay” + by’ + cy = 0 \).
  • Particular integral (PI): any one solution of the full equation.

The complete solution is

\( y = \text{CF} + \text{PI} \)

Step 1: The Auxiliary Equation

For the homogeneous equation

\( ay” + by’ + cy = 0 \)

assume a solution of the form \( y = e^{mx} \). This gives the auxiliary equation:

\( am^2 + bm + c = 0 \)

The nature of the roots determines the CF.

RootsComplementary Function
Distinct real \( m_1, m_2 \)\( Ae^{m_1x} + Be^{m_2x} \)
Repeated root \( m \)\( (A + Bx)e^{mx} \)
Complex roots \( \alpha \pm i\beta \)\( e^{\alpha x}(A\cos\beta x + B\sin\beta x) \)

Step 2: Finding the Particular Integral

The particular integral depends on the form of \( f(x) \).

\( f(x) \)Trial PI
\( ke^{px} \)\( Ae^{px} \)
\( A + Bx \)\( C + Dx \)
PolynomialSame degree polynomial
\( m\cos\omega x + n\sin\omega x \)\( A\cos\omega x + B\sin\omega x \)

If the trial solution clashes with the CF, multiply by \( x \).

Example 

Solve \( \dfrac{d^2y}{dx^2} – 3\dfrac{dy}{dx} + 2y = 0 \).

▶️ Answer / Explanation

Auxiliary equation:

\( m^2 – 3m + 2 = 0 \Rightarrow (m-1)(m-2)=0 \)

\( m=1,2 \)

CF: \( y = Ae^x + Be^{2x} \)

Example 

Solve \( \dfrac{d^2y}{dx^2} + y = x \).

▶️ Answer / Explanation

Auxiliary equation: \( m^2 + 1 = 0 \Rightarrow m = \pm i \)

CF: \( A\cos x + B\sin x \)

Trial PI: \( y = ax + b \)

Substitute and solve for \( a,b \).

Example 

Solve \( \dfrac{d^2y}{dx^2} + 4y = \sin 2x \).

▶️ Answer / Explanation

Auxiliary equation: \( m^2 + 4 = 0 \Rightarrow m = \pm 2i \)

CF: \( A\cos 2x + B\sin 2x \)

Trial PI: \( y = a\cos 2x + b\sin 2x \)

Multiply by \( x \) since this clashes with CF.

Substitute \( y = x(a\cos2x + b\sin2x) \) and solve for \( a,b \).

Scroll to Top