Edexcel IAL - Further Pure Mathematics 3- 5.1 Vector and Scalar Triple Products- Study notes - New syllabus
Edexcel IAL – Further Pure Mathematics 3- 5.1 Vector and Scalar Triple Products -Study notes- New syllabus
Edexcel IAL – Further Pure Mathematics 3- 5.1 Vector and Scalar Triple Products -Study notes -Edexcel A level Maths- per latest Syllabus.
Key Concepts:
- 5.1 Vector and Scalar Triple Products
The Vector Product and the Triple Scalar Product
This topic introduces the vector (cross) product and the triple scalar product, together with their important geometrical interpretations as area and volume. These ideas are fundamental in vector geometry and mechanics.
1. The Vector Product \( \mathbf{a} \times \mathbf{b} \)![]()
The vector product of two vectors \( \mathbf{a} \) and \( \mathbf{b} \) is a vector:
Perpendicular to both \( \mathbf{a} \) and \( \mathbf{b} \)
With direction given by the right-hand rule
Its magnitude is defined by
\( |\mathbf{a} \times \mathbf{b}| = |\mathbf{a}||\mathbf{b}|\sin\theta \)![]()
where \( \theta \) is the angle between \( \mathbf{a} \) and \( \mathbf{b} \).
Vector Product in Component Form
If
\( \mathbf{a} = a_1\mathbf{i} + a_2\mathbf{j} + a_3\mathbf{k} \)
\( \mathbf{b} = b_1\mathbf{i} + b_2\mathbf{j} + b_3\mathbf{k} \)
then
\( \mathbf{a} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \end{vmatrix} \)
Geometrical Interpretation: Area
The magnitude of the vector product represents an area:

Area of the parallelogram with sides \( \mathbf{a} \) and \( \mathbf{b} \):
\( |\mathbf{a} \times \mathbf{b}| \)
Area of the triangle with sides \( \mathbf{a} \) and \( \mathbf{b} \):
\( \dfrac{1}{2}|\mathbf{a} \times \mathbf{b}| \)
2. The Triple Scalar Product
The triple scalar product of vectors \( \mathbf{a}, \mathbf{b}, \mathbf{c} \) is defined as![]()
\( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) \)
It is a scalar quantity.
In component form:
\( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = \begin{vmatrix} a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \\ c_1 & c_2 & c_3 \end{vmatrix} \)
Geometrical Interpretation: Volume
The absolute value of the triple scalar product represents a volume:

Volume of the parallelepiped formed by \( \mathbf{a}, \mathbf{b}, \mathbf{c} \):
\( |\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})| \)
If this value is zero, the vectors are coplanar.
Example
Given
\( \mathbf{a} = 2\mathbf{i} – \mathbf{j} + \mathbf{k} \), \( \mathbf{b} = \mathbf{i} + 3\mathbf{j} – \mathbf{k} \)
find \( \mathbf{a} \times \mathbf{b} \).
▶️ Answer/Explanation
\( \mathbf{a} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 2 & -1 & 1 \\ 1 & 3 & -1 \end{vmatrix} \)
\( = (-1)(-1) – (1)(3)\mathbf{i} – \left(2(-1) – 1(1)\right)\mathbf{j} + (2\cdot3 – (-1)\cdot1)\mathbf{k} \)
\( = -2\mathbf{i} + 3\mathbf{j} + 7\mathbf{k} \)
Conclusion: \( \mathbf{a} \times \mathbf{b} = -2\mathbf{i} + 3\mathbf{j} + 7\mathbf{k} \).
Example
Find the area of the triangle with sides
\( \mathbf{a} = 3\mathbf{i} + 2\mathbf{j} \), \( \mathbf{b} = \mathbf{i} – 4\mathbf{j} \).
▶️ Answer/Explanation
\( \mathbf{a} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 3 & 2 & 0 \\ 1 & -4 & 0 \end{vmatrix} = ( -12 – 2 )\mathbf{k} = -14\mathbf{k} \)
\( |\mathbf{a} \times \mathbf{b}| = 14 \)
Area of triangle \( = \dfrac{1}{2} \times 14 = 7 \)
Conclusion: The area of the triangle is 7 square units.
Example
Given
\( \mathbf{a} = \mathbf{i} + \mathbf{j} + \mathbf{k} \), \( \mathbf{b} = 2\mathbf{i} – \mathbf{j} + \mathbf{k} \), \( \mathbf{c} = \mathbf{i} + 2\mathbf{j} – \mathbf{k} \),
find the volume of the parallelepiped.
▶️ Answer/Explanation
\( \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c}) = \begin{vmatrix} 1 & 1 & 1 \\ 2 & -1 & 1 \\ 1 & 2 & -1 \end{vmatrix} \)
Evaluating the determinant gives \( -6 \).
Volume \( = | -6 | = 6 \)
Conclusion: The volume of the parallelepiped is 6 cubic units.
