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Edexcel IAL - Pure Maths 1- 1.2 Use and Manipulation of Surds- Study notes  - New syllabus

Edexcel IAL – Pure Maths 1- 1.2 Use and Manipulation of Surds -Study notes- New syllabus

Edexcel IAL – Pure Maths 1- 1.2 Use and Manipulation of Surds -Study notes -Edexcel A level Physics – per latest Syllabus.

Key Concepts:

  •  Use and Manipulation of Surds

Edexcel IAL Maths-Study Notes- All Topics

Use and Manipulation of Surds

A surd is an irrational root that cannot be expressed as a rational number, such as \( \sqrt{2},\ \sqrt{5},\ \sqrt[3]{7} \). Expressions involving surds can often be simplified by using index laws or by rationalising denominators.

Key Surd Rules

RuleExpression
Multiplying surds\( \sqrt{a}\sqrt{b} = \sqrt{ab} \)
Dividing surds\( \dfrac{\sqrt{a}}{\sqrt{b}} = \sqrt{\dfrac{a}{b}} \)
Indices with surds\( \sqrt{a} = a^{1/2},\quad \sqrt[n]{a} = a^{1/n} \)
Simplifying\( \sqrt{ab} = b\sqrt{a} \) if \( b^2 = a \)
Conjugate PairConjugate of \( a + \sqrt{b} \) is \( a – \sqrt{b} \)

Rationalising Denominators

Case 1: Denominator of the form \( \sqrt{a} \)

Multiply top and bottom by \( \sqrt{a} \):

\( \dfrac{1}{\sqrt{a}} = \dfrac{\sqrt{a}}{a} \)

Case 2: Denominator of the form \( a + \sqrt{b} \)

Multiply by its conjugate:

\( \dfrac{1}{a+\sqrt{b}} = \dfrac{a-\sqrt{b}}{a^2 – b} \)

Case 3: General expression with two surds

Multiply by conjugate of the denominator:

\( \dfrac{x}{\sqrt{a}-\sqrt{b}} = \dfrac{x(\sqrt{a}+\sqrt{b})}{a – b} \)

Example 

Simplify \( \sqrt{18} \).

▶️ Answer / Explanation

\( 18 = 9 \cdot 2 \)

\( \sqrt{18} = \sqrt{9}\sqrt{2} = 3\sqrt{2} \)

Example 

Rationalise the denominator: \( \dfrac{5}{\sqrt{3}} \).

▶️ Answer / Explanation

Multiply by \( \sqrt{3} \):

\( \dfrac{5}{\sqrt{3}} \cdot \dfrac{\sqrt{3}}{\sqrt{3}} = \dfrac{5\sqrt{3}}{3} \)

Example 

Rationalise the denominator: \( \dfrac{7}{2 + \sqrt{5}} \).

▶️ Answer / Explanation

Multiply by conjugate \( 2 – \sqrt{5} \):

\( \dfrac{7}{2+\sqrt{5}} \cdot \dfrac{2-\sqrt{5}}{2-\sqrt{5}} = \dfrac{7(2-\sqrt{5})}{4 – 5} \)

\( = \dfrac{7(2 – \sqrt{5})}{-1} = -14 + 7\sqrt{5} \)

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