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Edexcel IAL - Pure Maths 1- 5.1 Indefinite Integration as the Reverse of Differentiation- Study notes  - New syllabus

Edexcel IAL – Pure Maths 1- 5.1 Indefinite Integration as the Reverse of Differentiation -Study notes- New syllabus

Edexcel IAL – Pure Maths 1- 5.1 Indefinite Integration as the Reverse of Differentiation -Study notes -Edexcel A level Physics – per latest Syllabus.

Key Concepts:

  • Indefinite Integration as the Reverse of Differentiation

Edexcel IAL Maths-Study Notes- All Topics

Indefinite Integration as the Reverse of Differentiation

Indefinite integration is the process of finding a function whose derivative is a given expression. Since differentiation removes constants, integration introduces an arbitrary constant.

Key Idea

If \( \dfrac{d}{dx}(F(x)) = f(x) \), then the indefinite integral is \( \displaystyle \int f(x)\,dx = F(x) + C \)

Here, \( C \) is the constant of integration, required whenever the integral is indefinite.

Why is the constant required?

  • Because many functions differ only by a constant but share the same derivative
  • E.g., the derivative of \( x^2 + 5 \), \( x^2 – 3 \), and \( x^2 + 100 \) is always \( 2x \)
  • Thus \( \displaystyle \int 2x\,dx = x^2 + C \)

Basic Integration Rules (Reversing Differentiation)

FunctionIndefinite Integral
\( x^n \) (for \( n \ne -1 \))\( \displaystyle \int x^n dx = \dfrac{x^{n+1}}{n+1} + C \)
\( \cos x \)\( \displaystyle \int \cos x\,dx = \sin x + C \)
\( \sin x \)\( \displaystyle \int \sin x\,dx = -\cos x + C \)
\( e^x \)\( \displaystyle \int e^x dx = e^x + C \)

Example 

Find \( \displaystyle \int 6x\,dx \).

▶️ Answer / Explanation

\( \int 6x\,dx = 6 \cdot \dfrac{x^2}{2} + C = 3x^2 + C \)

Example 

Find \( \displaystyle \int (4x^3 – 5x)\,dx \).

▶️ Answer / Explanation

\( \int 4x^3 dx = x^4 \)

\( \int -5x dx = -\dfrac{5}{2}x^2 \)

So the result is:

\( x^4 – \dfrac{5}{2}x^2 + C \)

Example 

Find \( \displaystyle \int (2e^{3x})\,dx \).

▶️ Answer / Explanation

Use reverse chain rule idea:

\( \int 2e^{3x}\,dx = 2 \cdot \dfrac{1}{3} e^{3x} + C \)

\( = \dfrac{2}{3}e^{3x} + C \)

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