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Edexcel IAL - Pure Maths 3- 3.2 The function ln x and its graph- Study notes  - New syllabus

Edexcel IAL – Pure Maths 3- 3.2 The function ln x and its graph -Study notes- New syllabus

Edexcel IAL – Pure Maths 3- 3.2 The function ln x and its graph -Study notes -Edexcel A level Physics – per latest Syllabus.

Key Concepts:

  • 3.2 The function ln x and its graph

Edexcel IAL Maths-Study Notes- All Topics

The Natural Logarithmic Function \( \ln x \)

The function \( y = \ln x \) is called the natural logarithmic function.

It is defined as the inverse function of the exponential function \( y = e^x \).

\( \ln x \) as the Inverse of \( e^x \)

If:

\( y = e^x \)

then its inverse is:

\( y = \ln x \)

This means:

\( \ln(e^x) = x \quad \text{and} \quad e^{\ln x} = x \)

The graphs of \( y = e^x \) and \( y = \ln x \) are reflections of each other in the line:

\( y = x \)

Key Properties of \( y = \ln x \)

PropertyDescription
Domain\( x > 0 \)
Range\( y \in \mathbb{R} \)
Intercept\( (1,0) \)
Asymptote\( x = 0 \)
MonotonicityStrictly increasing

Graph of \( y = \ln x \)

  • Passes through \( (1,0) \)
  • Approaches the y-axis as \( x \to 0^+ \)
  • Increases slowly for large \( x \)
  • Defined only for positive \( x \)

Solving Exponential Equations

Equations of the form \( e^{ax+b} = p \)

Method:

  • Take natural logarithms on both sides
  • Use \( \ln(e^k) = k \)
  • Solve for \( x \)

\( e^{ax+b} = p \Rightarrow ax + b = \ln p \)

Solving Logarithmic Equations

Equations of the form \( \ln(ax+b) = q \)

Method:

  • Rewrite using the exponential form
  • Solve for \( x \)
  • Check the domain \( ax+b>0 \)

\( \ln(ax+b) = q \Rightarrow ax+b = e^q \)

Example 

Solve:

\( e^{2x} = 5 \)

▶️ Answer / Explanation

Take natural logarithms:

\( 2x = \ln 5 \)

\( x = \dfrac{1}{2}\ln 5 \)

Example 

Solve:

\( e^{3x-1} = 7 \)

▶️ Answer / Explanation

Take natural logarithms:

\( 3x – 1 = \ln 7 \)

\( 3x = \ln 7 + 1 \)

\( x = \dfrac{\ln 7 + 1}{3} \)

Example

Solve:

\( \ln(2x – 3) = 1 \)

▶️ Answer / Explanation

Rewrite in exponential form:

\( 2x – 3 = e^1 = e \)

\( 2x = e + 3 \)

\( x = \dfrac{e + 3}{2} \)

Check domain:

\( 2x – 3 > 0 \Rightarrow x > \dfrac{3}{2} \)

The solution satisfies the domain.

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