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Edexcel IAL - Pure Maths 4- 3.1 Parametric Equations and Conversion to Cartesian Form- Study notes  - New syllabus

Edexcel IAL – Pure Maths 4- 3.1 Parametric Equations and Conversion to Cartesian Form -Study notes- New syllabus

Edexcel IAL – Pure Maths 4- 3.1 Parametric Equations and Conversion to Cartesian Form -Study notes -Edexcel A level Physics – per latest Syllabus.

Key Concepts:

  • 3.1 Parametric Equations and Conversion to Cartesian Form

Edexcel IAL Maths-Study Notes- All Topics

Parametric Equations of Curves

A curve can be described by expressing both \( x \) and \( y \) in terms of a third variable, called a parameter.

This parameter is usually denoted by \( t \).

\( x = f(t), \quad y = g(t) \)

As \( t \) varies, the point \( (x,y) \) moves along the curve.

Why Use Parametric Equations

  • To describe curves that cannot be written easily as \( y=f(x) \)
  • To represent motion in mechanics
  • To describe curves with direction

Conversion from Parametric to Cartesian

To convert to a Cartesian equation:

  • Eliminate the parameter \( t \)
  • Express \( y \) directly in terms of \( x \)

Conversion from Cartesian to Parametric

Choose a parameter and write:

\( x = f(t) \)

Then substitute into the equation for \( y \).

Example 

The curve is defined by:

\( x = 2t,\ y = t^2 \)

Find the Cartesian equation.

▶️ Answer / Explanation

From \( x=2t \),

\( t = \dfrac{x}{2} \)

Substitute into \( y \):

\( y = \left(\dfrac{x}{2}\right)^2 = \dfrac{x^2}{4} \)

Example 

The curve has Cartesian equation:

\( y = x^2 + 1 \)

Write it in parametric form.

▶️ Answer / Explanation

Let \( x = t \)

Then:

\( y = t^2 + 1 \)

So the parametric form is:

\( x = t,\ y = t^2 + 1 \)

Example 

The curve is given by:

\( x = 1 + \cos t,\ y = 2 + \sin t \)

Find the Cartesian equation.

▶️ Answer / Explanation

From \( x = 1+\cos t \):

\( \cos t = x-1 \)

From \( y = 2+\sin t \):

\( \sin t = y-2 \)

Use identity:

\( \cos^2 t + \sin^2 t = 1 \)

So:

\( (x-1)^2 + (y-2)^2 = 1 \)

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