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Edexcel IAL - Statistics 2- 4.5 One-Tailed and Two-Tailed Tests- Study notes  - New syllabus

Edexcel IAL – Statistics 2- 4.5 One-Tailed and Two-Tailed Tests -Study notes- New syllabus

Edexcel IAL – Statistics 2- 4.5 One-Tailed and Two-Tailed Tests -Study notes -Edexcel A level Maths- per latest Syllabus.

Key Concepts:

  • 4.5 One-Tailed and Two-Tailed Tests

Edexcel IAL Maths-Study Notes- All Topics

One-Tailed and Two-Tailed Hypothesis Tests

In hypothesis testing, the form of the alternative hypothesis determines whether a test is one-tailed or two-tailed. This choice affects the location of the critical region and the interpretation of results.

One-Tailed Tests

A one-tailed test is used when the alternative hypothesis specifies a direction of departure from the null hypothesis.

 

Only one extreme of the sampling distribution is considered.

Forms of One-Tailed Alternative Hypotheses

Upper-tailed test: \( \mathrm{H_1}:\; \mu > \mu_0 \)

Lower-tailed test: \( \mathrm{H_1}:\; \mu < \mu_0 \)

The entire significance level \( \alpha \) is placed in one tail of the distribution.

Example:

Testing whether a new process increases mean output

Two-Tailed Tests

A two-tailed test is used when the alternative hypothesis does not specify a direction.

Departures in both directions from the null hypothesis are considered.

Form of Two-Tailed Alternative Hypothesis

\( \mathrm{H_1}:\; \mu \neq \mu_0 \)

The significance level \( \alpha \) is split equally between the two tails.

Example:

Testing whether a machine is correctly calibrated

Comparison of One-Tailed and Two-Tailed Tests

FeatureOne-Tailed TestTwo-Tailed Test
Alternative hypothesisDirectionalNon-directional
Critical regionOne tailBoth tails
Significance levelAll in one tailSplit equally

Critical Values (Normal Distribution)

At the 5% significance level:

One-tailed test: critical value \( \mathrm{Z} = 1.645 \)

Two-tailed test: critical values \( \mathrm{Z} = \pm 1.96 \)

Choosing Between One-Tailed and Two-Tailed Tests

The choice must be made before data are collected.

  • Use a one-tailed test only when deviations in one direction are meaningful
  • Use a two-tailed test when deviations in either direction are important

Changing the test after seeing the data is not valid.

Examination Points

  • The alternative hypothesis determines the type of test
  • Always state whether the test is one-tailed or two-tailed
  • Use the correct critical values

Example :

A manufacturer claims that the mean lifetime of a battery is 100 hours. A random sample of 25 batteries has a mean lifetime of 104 hours. The population standard deviation is known to be 10 hours.

Test the claim at the 5% significance level.

▶️ Answer/Explanation

Hypotheses:

\( \mathrm{H_0}:\; \mu = 100 \)

\( \mathrm{H_1}:\; \mu > 100 \)

Test statistic:

\( Z = \dfrac{104 – 100}{10/\sqrt{25}} = 2 \)

Critical value (upper-tailed, 5%):

\( Z = 1.645 \)

Since \( 2 > 1.645 \), the test statistic lies in the critical region.

Conclusion: Reject \( \mathrm{H_0} \). There is evidence that the mean battery life exceeds 100 hours.

Example:

A machine is designed to fill bags with an average mass of 2 kg. A sample of 36 bags has a mean mass of 1.94 kg. The population standard deviation is 0.12 kg.

Test whether the machine is under-filling at the 5% significance level.

▶️ Answer/Explanation

Hypotheses:

\( \mathrm{H_0}:\; \mu = 2.0 \)

\( \mathrm{H_1}:\; \mu < 2.0 \)

Test statistic:

\( Z = \dfrac{1.94 – 2.0}{0.12/\sqrt{36}} = -3 \)

Critical value (lower-tailed, 5%):

\( Z = -1.645 \)

Since \( -3 < -1.645 \), the result is significant.

Conclusion: Reject \( \mathrm{H_0} \). There is evidence that the machine is under-filling.

Example :

A light bulb manufacturer claims that the mean lifetime of bulbs is 1200 hours. A random sample of 64 bulbs has a mean lifetime of 1170 hours. The population standard deviation is 160 hours.

Test the claim at the 5% significance level.

▶️ Answer/Explanation

Hypotheses:

\( \mathrm{H_0}:\; \mu = 1200 \)

\( \mathrm{H_1}:\; \mu \neq 1200 \)

Test statistic:

\( Z = \dfrac{1170 – 1200}{160/\sqrt{64}} = -1.5 \)

Critical values (two-tailed, 5%):

\( Z = \pm 1.96 \)

Since \( -1.96 < -1.5 < 1.96 \), the test statistic does not lie in the critical region.

Conclusion: Fail to reject \( \mathrm{H_0} \). There is insufficient evidence that the mean lifetime differs from 1200 hours.

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