Home / IB DP Biology-D1.2 Protein synthesis -FA 2025- IB Style Questions For HL Paper 1

IB DP Biology-D1.2 Protein synthesis -FA 2025- IB Style Questions For HL Paper 1

Question

Which diagram represents the modified mRNA after transcription?

▶️Answer/Explanation

Answer: A.

Explanation:

What does a mature/modified mRNA look like?

After transcription and RNA processing, a mature eukaryotic mRNA has:

  1. 5′ cap (G cap)
  2. Exons only (all introns are removed via splicing)
  3. 3′ Poly-A tail (AAAAA)
  4. And the strand is made of RNA → so U (Uracil) is present instead of T (Thymine)

Let’s look at the options:

Option A:

  •  5′ cap present
  • Only exons are there
  • Has poly-A tail
  • No introns 
  • Correct RNA direction 5′ → 3′
  • This looks like a perfect mature mRNA!

Option B:

  • 5′ cap
  • Introns still present
  • Poly-U tail (that’s not a thing should be Poly-A!)
  • Not fully processed mRNA

Option C:

  • Only introns are there, exons are missing.
  • Poly-A tail
  • Missing exons = NOT functional

Option D:

  • 5′ cap
  • Has both exons and introns = not yet fully spliced
  • Poly-U tail again — No

Question

The diagram shows the structure of a peptide.

How many bases are required in an mRNA molecule to code for this peptide?

A. 18

B. 36

C. 54

D. 72

▶️Answer/Explanation

Answer: C. 54

Explanation:

Step 1: Count the amino acids

From the diagram, let’s count each amino acid bubble: Gly, Ile, Val, Cys, Glu, Gln, Ala, Ser, Leu, Asp, Arg, Cys, Val, Pro, Lys, Phe, Tyr, Thr = 18 amino acids

So, the peptide is made up of 18 amino acids.

Step 2: Recall the golden rule of the genetic code

Each amino acid = 1 codon = 3 bases

So, to code 18 amino acids, we need: 18 × 3 = 54 bases

 
 

Question

This DNA sequence was used to synthesize a polypeptide.

DNA (sense strand): 3′ T A C T G A 5′

DNA (template strand): 5′ A T G A C T 3′

Which are the bases of the tRNA (anticodons)?

A. T A C   T G A

B. U A C   U G A

C. A U G   A C U

D. A T G   A C T

▶️Answer/Explanation

Answer: C. A U G   A C U

Explanation:

Step 1: Transcription – Create the mRNA sequence

mRNA is complementary to the DNA template strand, using U (uracil) instead of T (thymine).

So, the mRNA (from 3′ to 5′): → 3′ U A C U G A 5′

Step 2: Translation – Determine tRNA anticodons

tRNA anticodons are complementary to mRNA codons:

  • mRNA codons: UAC | UGA
  • tRNA anticodons: AUG | ACU

Correct Answer: C. A U G   A C U

Why Other Options Are Incorrect:

A. T A C   T G A → Uses thymine (T), which tRNA does not have.

B. U A C   U G A → This is the mRNA sequence, not the anticodons.

D. A T G   A C T → Uses DNA bases (T instead of U), not correct for tRNA.

Question

The image shows a polysome in a bacterial cell.

How many genes have been transcribed?

A. 1

B. 2

C. 3

D. 4

▶️Answer/Explanation

Answer: A. 1

Explanation:

What’s in the image?

The diagram shows one single mRNA strand with multiple ribosomes attached, each one busy making a polypeptide chain that’s a classic example of a polysome or polyribosome 

What does that mean?

In prokaryotes (like bacteria), translation can begin even before transcription finishes and multiple ribosomes can hop onto one mRNA strand to translate it simultaneously.

But the key thing is: All those ribosomes are translating the same mRNA, meaning it was transcribed from just one gene.

Only one gene has been transcribed. The multiple polypeptides being made are just copies of the same protein from that one gene’s mRNA.

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