Bateson and Punnett crossed two white-flowered sweet pea varieties (Lathyrus odoratus). They crossed two varieties that both had white flowers and discovered that the F1 generation all had purple flowers. When the F1 plants were self-fertilized, there was a 9:7 ratio of purple to white in the F2 generation. Bateson and Punnett deduced that the genotypes of the two white parental varieties were CCrr and ccRR.
a. State the genotype of the F1 hybrids. [1]
b. Explain how the 9:7 phenotypic ratio arises in the F2 generation. [3]
c. Predict the phenotypic ratio from crossing Ccrr × ccRr plants. [1]
▶️ Answer/Explanation
- Answer: CcRr
- Explanation:
The parental genotypes CCrr (white) and ccRR (white) produce gametes Cr and cR respectively. Their fusion yields F1 hybrids with genotype CcRr, showing complementation where both dominant alleles (C and R) are required for purple pigment production.
- Key Points:
- Gene Interaction: Two unlinked genes (C and R) interact epistatically, where both dominant alleles are required for purple color (C_R_).
- F2 Genotypes: Selfing CcRr × CcRr produces:
- 9/16 C_R_ (purple)
- 3/16 C_rr (white)
- 3/16 ccR_ (white)
- 1/16 ccrr (white)
- Ratio Formation: The 9:3:3:1 Mendelian ratio becomes 9:7 because three genotypic classes (3+3+1) all produce the same white phenotype.
- Punnett Square Visualization:
Gametes: CR, Cr, cR, cr → 9 purple : 7 white
- Answer: 1 purple : 3 white
- Explanation:
Possible gametes:
- Ccrr produces Cr and cr
- ccRr produces cR and cr
Offspring genotypes and phenotypes:
1 CcRr (purple), 1 Ccrr (white), 1 ccRr (white), 1 ccrr (white)
Genotype Phenotype Ratio CcRr Purple 1 Others White 3
CcRr ✔
a. Two unlinked genes (C and R) interact epistatically, requiring both dominant alleles for purple color (C_R_) ✔
b. Selfing CcRr × CcRr produces 9/16 C_R_ (purple), 3/16 C_rr (white), 3/16 ccR_ (white), 1/16 ccrr (white) ✔
c. The 9:3:3:1 ratio becomes 9:7 as three genotypic classes (C_rr, ccR_, ccrr) produce white phenotype ✔
1 purple : 3 white ✔