IB DP Chemistry - Structure 3.1 The periodic table: Classification of elements- IB Style Questions For HL Paper 1A -FA 2025

Question

Which elements would react with one another most vigorously?
(A) K(s) and Br2(g)
(B) K(s) and Cl2(g)
(C) Na(s) and Br2(g)
(D) Na(s) and Cl2(g)
▶️ Answer/Explanation
Detailed solution

Reactivity depends on:

  • Metal: K is more reactive than Na (lower ionization energy)
  • Halogen: Cl2 is more reactive than Br2 (higher electronegativity)

Most vigorous reaction: Most reactive metal (K) + most reactive halogen (Cl2)

Answer: (B)

Question

Which statement best explains the first ionization energy of sulfur being lower than that of phosphorus?
(A) Sulfur has more protons than phosphorus.
(B) Phosphorus does not have paired electrons in the outer p sub-level.
(C) Sulfur has an unpaired electron in the outer p sub-level.
(D) Phosphorus is more reactive than sulfur.
▶️ Answer/Explanation
Detailed solution

The first ionization energy is the energy needed to remove one electron from a gaseous atom. Across a period, it generally increases because the nuclear charge increases and electrons are held more strongly.

Phosphorus has the electron configuration ending in 3p³, with three unpaired electrons in the outer p sub-level (one in each p orbital). This half-filled arrangement is relatively stable and experiences less electron–electron repulsion.

Sulfur has the configuration ending in 3p⁴, meaning one of the p orbitals now contains a pair of electrons. The paired electrons in the same orbital repel each other, so it takes less energy to remove one of them. This extra repulsion lowers the first ionization energy of sulfur compared with phosphorus.

Statement (B) correctly captures this idea: phosphorus does not have paired electrons in the outer p sub-level, whereas sulfur does, leading to a lower first ionization energy for sulfur.

Answer: (B)

Question

Which molecule could give rise to the ¹H NMR spectrum shown below (single peak near ~2 ppm)?
A. CH₃COOCH₃
B. CH₃COOCH₃
C. CH₃CHO
D. CH₃CH₂CH₃

▶️ Answer/Explanation

Correct answer: B

• The spectrum shows only one singlet → all protons must be chemically equivalent.
CH₃COOCH₃ has two equivalent methyl groups giving a single peak around 2 ppm.
• The other molecules have multiple proton environments → multiple signals, not one.

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