IB Mathematics SL 1.1 Operations with numbers AI HL Paper 1- Exam Style Questions- New Syllabus
The planet Earth takes one year to revolve around the Sun. Assume that a year is 365 days and the path of the Earth around the Sun is the circumference of a circle of radius \( 150000000 \, \text{km} \).
a) Calculate the distance travelled by the Earth in one day.
b) Give your answer to part (a) in the form \( a \times 10^k \) where \( 1 \leqslant a \leqslant 10 \) and \( k \in \mathbb{Z} \).
▶️ Answer/Explanation
a) To calculate the distance travelled by the Earth in one day:
The circumference of the Earth’s orbit is:
\( 2 \times \pi \times 150000000 \)
Distance travelled in one day (out of 365 days):
\( \frac{2 \times \pi \times 150000000}{365} \)
Calculate:
\( \pi \approx 3.1415926535 \)
\( 2 \times \pi \times 150000000 \approx 942477796.076 \)
\( \frac{942477796.076}{365} \approx 2582129.851 \)
To 3 significant figures:
\( 2580000 \, \text{km} \)
Thus:
Distance travelled is \( 2580000 \, \text{km} \) [4]
b) To express the answer from part (a) in the form \( a \times 10^k \):
From part (a), the distance is \( 2580000 \, \text{km} \).
Convert to scientific notation:
\( 2580000 = 2.58 \times 10^6 \)
Here, \( a = 2.58 \), \( k = 6 \), satisfying \( 1 \leqslant a \leqslant 10 \) and \( k \in \mathbb{Z} \).
Thus:
\( 2.58 \times 10^6 \, \text{km} \) [2]