IB DP Math MAA HL : IB Style Mock Exams – Set 3 Paper 1

Question

Find the least positive value of x for which cos \(\left ( \frac{x}{2} + \frac{\pi }{3} \right ) = \frac{1}{\sqrt{2}}.\)

▶️Answer/Explanation

Ans:

determines \(\frac{\pi }{4}\)  ( or 450) as the first quadrant (reference) angle attempts to solve \(\frac{x }{2} + \frac{\pi }{3} = \frac{\pi }{4}\)

Note: Award M1 for attempting to solve  \(\frac{x }{2} + \frac{\pi }{3} = \frac{\pi }{4}, \frac{7\pi }{4} (,…)\)

Question

A function f is defined by f(x) = \(\frac{2x – 1}{x + 1}\), where x ∈ R, x ≠ -1.
(a) The graph of y = f (x) has a vertical asymptote and a horizontal asymptote.
Write down the equation of
(i) the vertical asymptote;
(ii) the horizontal asymptote.

(b) On the set of axes below, sketch the graph of y = f (x) .
On your sketch, clearly indicate the asymptotes and the position of any points of intersection with the axes.

(c) Hence, solve the inequality \(0<\frac{2x – 1}{x + 1} <2.\)
(d) Solve the inequality \(0<\frac{2|x|-1}{|x| + 1} <2.\)

▶️Answer/Explanation

Ans:

(a) (i)  x =−1
    (ii) y = 2

(b)    

rational function shape with two branches in opposite quadrants, with two correctly positioned asymptotes and asymptotic behaviour shown axes intercepts clearly shown at \(x = \frac{1}{2} and y = -1\)

(c)   x >  \(\frac{1}{2}\)

Note: Accept correct alternative correct notation, such as \(\left ( \frac{1}{2}, \infty \right ) and ]\frac{1}{2}, \infty [.\)

(d) EITHER
attempts to sketch \(y = \frac{2|x| – 1}{|x|+1}\)

OR
attempts to solve 2|x| – 1 = 0

Note: Award the (M1) if \(x = \frac{1}{2} and x = -\frac{1}{2}\)   are identified.

THEN

\(x <-\frac{1}{2} and x >\frac{1}{2}\)

Note: Accept the use of a comma. Condone the use of ‘and’. Accept correct alternative notation.

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