Question
A sector of a circle, centre O and radius 4.5m, is shown in the following diagram.![]()
(a) (i) Find the angle AÔB.
(ii) Find the area of the shaded segment.
A square field with side 8m has a goat tied to a post in the centre by a rope such that the
goat can reach all parts of the field up to 4.5m from the post.![]()
(b) Find the area of the field that can be reached by the goat.
Let V be the volume of grass eaten by the goat, in cubic metres, and t be the length of time,
in hours, that the goat has been in the field.
The goat eats grass at the rate of \(\frac{dV}{dt}=0.3te^{-t}\).
(c) Find the value of t at which the goat is eating grass at the greatest rate.
The goat is tied in the field for 8 hours.
(d) Find the total volume of grass eaten by the goat during this time.
Answer/Explanation
Ans:
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Question
The graph alongside shows how a cyclist accelerates away from an intersection.
a. Estimate the instantaneous speed of the cyclist after:
i) 4 seconds
ii) 6 seconds.
b. Describe what happens to the cyclist’s speed over time.
▶️Answer/Explanation
(a)
![]()
i)
The tangent at $t=4$ passes through $(2,0)$ and $(7,40)$.
$\therefore$ the instantaneous speed at $t=4$
$$
\begin{aligned}
& =\frac{(40-0) \mathrm{m}}{(7-2) \mathrm{s}} \\
& =\frac{40}{5} \mathrm{~ms}^{-1} \\
& =8 \mathrm{~ms}^{-1}
\end{aligned}
$$
ii)
The tangent at $t=6$ passes through $(3.5,0)$ and $(8,70)$.
$\therefore$ the instantaneous speed at $t=6$
$$
\begin{aligned}
& =\frac{(70-0) \mathrm{m}}{(8-3.5) \mathrm{s}} \\
& =\frac{70}{4.5} \mathrm{~m} \mathrm{~s}^{-1} \\
& \approx 15.6 \mathrm{~m} \mathrm{~s}^{-1}
\end{aligned}
$$
b) As time increases, the tangent to the curve gets steeper and steeper. The gradient of the tangent is increasing, so the speed of the cyclist is increasing.
