Home / IBDP Maths AHL 2.16 The graphs of the functions AA HL Paper 1- Exam Style Questions

IBDP Maths AHL 2.16 The graphs of the functions AA HL Paper 1- Exam Style Questions- New Syllabus

Question

Consider a function \( f \) characterized by the following features:

  • a local maximum at the point \( A\left(-1, -\frac{5}{2}\right) \),
  • a local minimum at the point \( B\left(0, \frac{15}{2}\right) \),
  • a vertical asymptote defined by the line \( x = -\frac{1}{2} \),
  • and an oblique asymptote defined by \( y = 5x + 5 \).
A portion of the graph of \( f \) and this information are illustrated in the diagram below.
 
(a) Sketch the graph of the transformation \( y = |f(x)| \) on a new set of axes, making sure to indicate any asymptotes.
 
(b) On a separate set of axes, sketch the graph of the reciprocal function \( y = \frac{1}{f(x)} \). Clearly label all intercepts with the axes and any asymptotes.
 

Syllabus Topic Codes (IB Mathematics AA HL):

SL 2.11: Transformations of graphs — part (a)
AHL 2.13: Rational functions; horizontal, vertical and oblique asymptotes — parts (a), (b) 
AHL 2.16: The graphs of the functions \( y=|f(x)| \) and \( y=\frac{1}{f(x)} \) — parts (a), (b) 
▶️ Answer/Explanation

(a) Sketch of \( y = |f(x)| \):

 

• The vertical asymptote remains at \( x = -\frac{1}{2} \).
• The oblique asymptote \( y = 5x + 5 \) becomes \( y = |5x + 5| \), which is V-shaped with vertex at \( x = -1 \) (where \( 5x+5=0 \)).
• Local maximum at \( A(-1, -\frac{5}{2}) \) reflects to become a local minimum at \( (-1, \frac{5}{2}) \) after taking absolute value.
• Local minimum at \( B(0, \frac{15}{2}) \) stays at \( (0, \frac{15}{2}) \) since positive.
• Portions of the original graph below the x-axis (e.g., near \( A \)) are reflected above the x-axis.
correct vertical asymptote, reflected oblique asymptote, correct turning points after reflection.

(b) Sketch of \( y = \frac{1}{f(x)} \):

 

• Vertical asymptotes of \( \frac{1}{f} \) occur where \( f(x) = 0 \) (x-intercepts of original \( f \)), and where \( f \) has vertical asymptotes (here \( x = -\frac{1}{2} \)) become zeros of \( \frac{1}{f} \).
• Horizontal asymptote: As \( |x| \to \infty \), \( f(x) \approx 5x+5 \), so \( \frac{1}{f(x)} \approx \frac{1}{5x+5} \to 0 \). Thus \( y = 0 \) is a horizontal asymptote.
• Intercepts: \( \frac{1}{f(x)} = 0 \) occurs where \( f(x) \) has vertical asymptotes (i.e., \( x = -\frac{1}{2} \)). • Original local extrema become local extrema of reciprocal with reversed nature (max ↔ min) and reciprocal y-values.
correct vertical/horizontal asymptotes, intercept at \( (-\frac{1}{2}, 0) \), behaviour near original turning points.

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