IBDP Maths SL 3.2 Use of sine, cosine and tangent ratios AA HL Paper 2- Exam Style Questions- New Syllabus
Barry is at the top of a cliff, standing 80 m above sea level, and observes two yachts in the sea.
“Seaview” \((S)\) is at an angle of depression of 25°.
“Nauti Buoy” \((N)\) is at an angle of depression of 35°.
X lies at the foot of the cliff and angle \({\text{SXN}} = 70°\).
Find, to 3 significant figures, the distance between the two yachts. [6]
▶️ Answer/Explanation
attempt to use tan, or sine rule, in triangle BXN or BXS (M1)
\({\text{NX}} = 80\tan 55^\circ \left( { = \frac{{80}}{{\tan 35^\circ }} = 114.25} \right)\) (A1)
\({\text{SX}} = 80\tan 65^\circ \left( { = \frac{{80}}{{\tan 25^\circ }} = 171.56} \right)\) (A1)
Attempt to use cosine rule (M1)
\({\text{S}}{{\text{N}}^2} = {171.56^2} + {114.25^2} – 2 \times 171.56 \times 114.25\cos 70^\circ\) (A1)
\({\text{SN}} = 171{\text{ }}({\text{m}})\) (A1)
Note: Award final A1 only if the correct answer has been given to 3 significant figures.
[6 marks]