To estimate the probability that a randomly selected visitor will ride The Dragon on Tuesday, we consider the frequency data provided from Monday’s sample. The total number of visitors sampled is 40. The number of visitors who rode The Dragon at least once is:

\[ 16 \text{ (once)} + 13 \text{ (twice)} + 2 \text{ (three times)} + 3 \text{ (four times)} = 34 \]

The probability is therefore:

\[ \frac{34}{40} = \frac{17}{20} = 0.85 \]

\(\boxed{0.85}\)

The expected number of times a visitor will ride The Dragon is calculated using the expected value formula:

\[ E(X) = \sum [x \times P(X = x)] \]

Calculating each term:

\[ (0 \times \frac{6}{40}) + (1 \times \frac{16}{40}) + (2 \times \frac{13}{40}) + (3 \times \frac{2}{40}) + (4 \times \frac{3}{40}) \]

\[ = 0 + \frac{16}{40} + \frac{26}{40} + \frac{6}{40} + \frac{12}{40} = \frac{60}{40} = 1.5 \]

\(\boxed{1.5 \text{ times}}\)

First calculate the total expected rides for 1000 visitors:

\[ 1.5 \text{ rides/visitor} \times 1000 \text{ visitors} = 1500 \text{ rides} \]

With a capacity of 10 people per run:

\[ \frac{1500 \text{ rides}}{10 \text{ people/run}} = 150 \text{ runs} \]

\(\boxed{150 \text{ runs}}\)